Basically, you want to do is evaluate if they entered anything for each
item, and if so, print an additional line to the message.
?
$message = I would like to order:\n;
if($pizza != ) { $message .= Pizza: $pizza \n; }
if($chips != ) { $message .= Chips: $chips \n; }
if($hamburger != ) {
,
$header
);
?
Matthew Luchak
Webmaster
Kaydara Inc.
[EMAIL PROTECTED]
-Original Message-
From: Raymond Lilleodegard [mailto:[EMAIL PROTECTED]]
Sent: Tuesday, November 20, 2001 1:57 PM
To: [EMAIL PROTECTED]
Subject: [PHP] Re: A tricky one?
Thanks
$header
);
?
Matthew Luchak
Webmaster
Kaydara Inc.
[EMAIL PROTECTED]
-Original Message-
From: Raymond Lilleodegard [mailto:[EMAIL PROTECTED]]
Sent: Tuesday, November 20, 2001 1:57 PM
To: [EMAIL PROTECTED]
Subject: [PHP] Re: A tricky one?
Thanks for answering.
But this only works if the custome
If you only want to show the ones variables that have values input by
the user, you could do this with the while loop:
while (list($var, $val) = each($HTTP_POST_VARS)) {
if ((strlen($val) 0) ($var !=email) ($var !=SUBMIT)
(isset($var)) {
$message .= $val $var were
w Luchak
Webmaster
Kaydara Inc.
[EMAIL PROTECTED]
-Original Message-
From: Raymond Lilleodegard [mailto:[EMAIL PROTECTED]]
Sent: Tuesday, November 20, 2001 3:52 PM
To: [EMAIL PROTECTED]
Subject: Re: [PHP] Re: A tricky one?
It works after modifying it a little. BUT... :) It lists all the
v
)
Matthew Luchak
Webmaster
Kaydara Inc.
[EMAIL PROTECTED]
-Original Message-
From: Raymond Lilleodegard [mailto:[EMAIL PROTECTED]]
Sent: Tuesday, November 20, 2001 3:52 PM
To: [EMAIL PROTECTED]
Subject: Re: [PHP] Re: A tricky one?
It works after
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