Whatever variable that is suppose to contain the URL is an array. If you
try to print a variable that is an array the value you get is 'Array'. You
will either have to step through it, or implode it, or something of that
nature to get what the array contains.
- Original Message -
From:
But what could the user be typing into the field to return an array?
I'm completely at a loss.
Quoting Joseph W. Goff [EMAIL PROTECTED]:
### Whatever variable that is suppose to contain the URL is an array. If you
### try to print a variable that is an array the value you get is 'Array'.
###
I don't know. You need to show your code.
- Original Message -
From: [EMAIL PROTECTED]
To: Joseph W. Goff [EMAIL PROTECTED]
Cc: php-general [EMAIL PROTECTED]
Sent: Monday, December 16, 2002 12:01 PM
Subject: Re: [PHP] URL field receiving Array for others
But what could the user
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