Re: [PHP] Undefined variable problem
Hello, This is a reply to an e-mail that you wrote on Fri, 1 Aug 2003 at 14:47, lines prefixed by '' were originally written by you. Notice: Undefined variable: email1 in c:phpdevwwwbwhprojectcompare.php on line 117 $$tmp.= $value; /* This is the error line 117*** */ You are trying to append to the variable instead of create it, change this line to: $$tmp = $value; David. -- phpmachine :: The quick and easy to use service providing you with professionally developed PHP scripts :: http://www.phpmachine.com/ Professional Web Development by David Nicholson http://www.djnicholson.com/ QuizSender.com - How well do your friends actually know you? http://www.quizsender.com/ (developed entirely in PHP) -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Undefined variable problem
Hello
This is the code:
$m = 1;
while ($line = mysql_fetch_assoc($rs)) { //dumping into an array
foreach ($line as $field = $value) {
$tmp = $field.$m;
$$tmp.= $value; /* This is the error line 117*** */
}
$m++;
}
This is basically so that i can use the array via variables like so:
if($tcl2==1){echo $tcl2;}
instead of: if($arrayname['tcl']['1']==1){echo $arrayname['tcl']['1'];} and
so onesp since i have 38 fields.
I can of course just shut off error reporting...but thats not the best
solution right? and i still wouldnt know whats causing these notices...
Simply define $$tmp -variable before adding stuff in it.
[code]
$m = 1;
while ($line = mysql_fetch_assoc($rs)) { //dumping into an array
foreach ($line as $field = $value) {
$tmp = $field.$m;
$$tmp = ;
$$tmp .= $value;
}
$m++;
}
[/code]
No it should whine about undefined vars.
Cheers, Joona
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Joona Kulmala [EMAIL PROTECTED]
PHP Finland
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Re: [PHP] Undefined variable problem
IT WORKS!!! Thanks for replying and the solution. Cheers, -Ryan Hello, This is a reply to an e-mail that you wrote on Fri, 1 Aug 2003 at 14:47, lines prefixed by '' were originally written by you. Notice: Undefined variable: email1 in c:phpdevwwwbwhprojectcompare.php on line 117 $$tmp.= $value; /* This is the error line 117*** */ You are trying to append to the variable instead of create it, change this line to: $$tmp = $value; David. -- phpmachine :: The quick and easy to use service providing you with professionally developed PHP scripts :: http://www.phpmachine.com/ Professional Web Development by David Nicholson http://www.djnicholson.com/ QuizSender.com - How well do your friends actually know you? http://www.quizsender.com/ (developed entirely in PHP) We will slaughter you all! - The Iraqi (Dis)information ministers site http://MrSahaf.com -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Undefined variable problem
* Thus wrote Ryan A ([EMAIL PROTECTED]):
Notice: Undefined variable: email1 in c:\phpdev\www\bwh\project\compare.php
on line 117
[...]
$m = 1;
while ($line = mysql_fetch_assoc($rs)) { //dumping into an array
foreach ($line as $field = $value) {
$tmp = $field.$m;
$$tmp.= $value; /* This is the error line 117*** */
Your concating a variable that doesnt exist.
Curt
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