On Thu, Jul 31, 2008 at 10:18 AM, Jignesh Thummar
[EMAIL PROTECTED] wrote:
I'm trying to upload the file. It's showing me successfully uploaded.
But it's not able to move from temp directory to my defined directory
my code:
if (is_uploaded_file($_FILES['myfile']['tmp_name'])) {
it's writable.
On Thu, Jul 31, 2008 at 3:37 PM, Eric Butera [EMAIL PROTECTED] wrote:
On Thu, Jul 31, 2008 at 10:18 AM, Jignesh Thummar
[EMAIL PROTECTED] wrote:
I'm trying to upload the file. It's showing me successfully uploaded.
But it's not able to move from temp directory to my defined
Maybe check the return value of the function:
http://us3.php.net/manual/en/function.move-uploaded-file.php
Thank you,
Micah Gersten
onShore Networks
Internal Developer
http://www.onshore.com
Jignesh Thummar wrote:
I'm trying to upload the file. It's showing me successfully uploaded.
But it's
On Thu, Jul 31, 2008 at 10:18 AM, Jignesh Thummar
[EMAIL PROTECTED] wrote:
I'm trying to upload the file. It's showing me successfully uploaded.
But it's not able to move from temp directory to my defined directory
my code:
if (is_uploaded_file($_FILES['myfile']['tmp_name'])) {
Jignesh Thummar wrote:
I'm trying to upload the file. It's showing me successfully uploaded.
But it's not able to move from temp directory to my defined directory
my code:
if (is_uploaded_file($_FILES['myfile']['tmp_name'])) {
move_uploaded_file($_FILES['myfile']['tmp_name'], $myfilename);
Thanks.. It's fixed...
- Jignesh
On Thu, Jul 31, 2008 at 6:05 PM, brian [EMAIL PROTECTED] wrote:
Jignesh Thummar wrote:
I'm trying to upload the file. It's showing me successfully uploaded.
But it's not able to move from temp directory to my defined directory
my code:
if
On Sat, July 9, 2005 1:39 am, Ahmed Abdel-Aliem said:
Hi
i have a problem with a code to upload files on server
here is the code
$f = $HTTP_POST_FILES['News_Pic'];
Use $_FILES to stay current...
$dst_file_name = generateUniqueId();
$arr = split(\.,$f['name']);
$f['name'] =
From: Mark Colvin [mailto:[EMAIL PROTECTED]]
Sent: Thursday, July 18, 2002 10:09 AM
-- upload.php --
?php
if ('img1' != ) {
This will allways be true! 'img1' is a string and will never be empty.
You probably mean if($img1 != )
However, I'm not sure this will
Joakim,
Thank you for your reply. I tried your example and get 'Possible file upload
attack: filename.' meaning that 'if
(is_uploaded_file($_FILES['img1']['tmp_name']))' returns false. I put a
couple of echo statements in before the if statement to check '$img1_name'
'$img1_size and '$img1_type'
From: Mark Colvin [mailto:[EMAIL PROTECTED]]
Sent: Thursday, July 18, 2002 12:41 PM
To: [EMAIL PROTECTED]
Joakim,
Thank you for your reply. I tried your example and get
'Possible file upload
attack: filename.' meaning that 'if
(is_uploaded_file($_FILES['img1']['tmp_name']))' returns
Joakim,
Thanks again. $HTTP_POST did the trick. I did look through the archives
before posting but didn't come across this solution. I obviously didn't look
hard enough!
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