[PHP] All of a sudden I get Warning: Bad arguments to implode() in busca_01.php on line 133

2001-05-22 Thread Martin Cabrera Diaubalick
Hello Everyone! This is my code if (count($array_id)==1) { $string_id=$array_id; } else { $string_id= implode(:,$array_id); } I've been testing it for three days and never had an error, now it

Re: [PHP] All of a sudden I get Warning: Bad arguments to implode() in busca_01.php on line 133

2001-05-22 Thread Zak Greant
Sounds like you are trying to implode a non-existant array. Change your code to handle an empty or missing array. ie. - Original Message - From: Martin Cabrera Diaubalick [EMAIL PROTECTED] To: [EMAIL PROTECTED] Sent: Tuesday, May 22, 2001 2:41 AM Subject: [PHP] All of a sudden I get

Re: [PHP] All of a sudden I get Warning: Bad arguments to implode() in busca_01.php on line 133

2001-05-22 Thread Zak Greant
ie. Oops! Hit the right keys at the wrong time! :) if (! count ($array_id)) { echo '$array_id is empty or not set.'; } else if (1 == count($array_id)) { $string_id=$array_id; } else { $string_id= implode(:,$array_id); } --zak -- PHP General Mailing List (http://www.php.net/) To

RE: [PHP] All of a sudden I get Warning: Bad arguments to implode() in busca_01.php on line 133

2001-05-22 Thread Maxim Maletsky
Try: if (!is_array($array_id)) { $string_id=$array_id; } else { $string_id= implode(:,$array_id); } You have to always make sure, you are passing Array into an implode() or explode(). BTW: your