Re: [PHP] Array difficulty
On Tue, July 31, 2007 8:27 am, Carlton Whitehead wrote:
> I have an array like this:
>
> $chance = array("lowercase" => 27, "uppercase" => 62, "integer" =>
> 46);
>
> The values for each of the keys are randomly generated. I want to find
> the key name of the one which has the highest value. Currently, I'm
> doing this as follows:
>
> arsort($chance);
$result = key($chance);
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Re: [PHP] Array difficulty
On 31/07/07, Alister Bulman <[EMAIL PROTECTED]> wrote:
> On 31/07/07, Carlton Whitehead <[EMAIL PROTECTED]> wrote:
> >> Couldn't you just do
> >> arsort($chance);
> >> $lastItem = chance[( count( $chance ) - 1 )];
>
> > I tried that earlier, but the problem is:
> > count( $chance ) - 1 ); returns an integer, so I would be asking for
> > something like $chance[1] or $chance[0], neither of which exist in the
> > array. Keep in mind $chance only has keys with string names:
>
> http://uk3.php.net/current
>
> $chance = array("lowercase" => 27, "uppercase" => 62, "integer" => 46);
> arsort($chance);
max() returns the maximum value of an array.
array_search() finds the key for a value
So all that's needed to find the key of the maximum value is:
$result = array_search(max($chance), $chance);
I'd pretty much guarantee it'll be about an order of magnitude faster
than any solution that relies on sorting the array.
-robin
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Re: [PHP] Array difficulty
On 31/07/07, Carlton Whitehead <[EMAIL PROTECTED]> wrote:
>> Couldn't you just do
>> arsort($chance);
>> $lastItem = chance[( count( $chance ) - 1 )];
> I tried that earlier, but the problem is:
> count( $chance ) - 1 ); returns an integer, so I would be asking for
> something like $chance[1] or $chance[0], neither of which exist in the array.
> Keep in mind $chance only has keys with string names:
http://uk3.php.net/current
$chance = array("lowercase" => 27, "uppercase" => 62, "integer" => 46);
arsort($chance);
$lastItem = current($chance);
echo "$lastItem\n\n"; // 62
Alister
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RE: [PHP] Array difficulty
> > Couldn't you just do > > arsort($chance); > > $lastItem = chance[( count( $chance ) - 1 )]; > $lastItem = end( $chance ); end() returns the value as well. You would also need to use key(). thnx, Chris -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] Array difficulty
On Tue, 2007-07-31 at 14:43 +0100, Chris Boget wrote: > > At this point, $result would be equal to "uppercase". I feel > > like this is a really kludgey way to accomplish this. Is there > > a better way? > > Couldn't you just do > > arsort($chance); > $lastItem = chance[( count( $chance ) - 1 )]; $lastItem = end( $chance ); Cheers, Rob. -- ... SwarmBuy.com - http://www.swarmbuy.com Leveraging the buying power of the masses! ... -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Array difficulty
On 31/07/07, Carlton Whitehead <[EMAIL PROTECTED]> wrote:
> Hi all,
>
> I have an array like this:
>
> $chance = array("lowercase" => 27, "uppercase" => 62, "integer" => 46);
>
> The values for each of the keys are randomly generated. I want to find the
> key name of the one which has the highest value. Currently, I'm doing this as
> follows:
>
> arsort($chance);
> foreach ($chance as $type => $value)
> {
> $result = $type;
> break;
> }
>
Assuming $chance is non-empty.
$result = array_search(max($chance), $chance);
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Re: [PHP] Array difficulty
At this point, $result would be equal to "uppercase". I feel like this is a really kludgey way to accomplish this. Is there a better way? Not tested it, but max() should work as the first parameter can be an array: http://uk3.php.net/max Except he's looking for the key and not the value, which max() would return. Come to think of it, the solution I provided does the same thing. Untested but one of the below should work: arsort($chance); $lastItem = key( $chance[( count( $chance ) - 1 )]); OR arsort($chance); $lastItem = key( end( $chance )); thnx, Chris -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Array difficulty
I tried that earlier, but the problem is:
count( $chance ) - 1 ); returns an integer, so I would be asking for something
like $chance[1] or $chance[0], neither of which exist in the array. Keep in
mind $chance only has keys with string names:
The array looks like this:
$chance = array("lowercase" => 27, "uppercase" => 62, "integer" => 46);
The values assigned to each key are randomly generated.
Regards,
Carlton Whitehead
- Original Message -
From: "Chris Boget" <[EMAIL PROTECTED]>
To: "Carlton Whitehead" <[EMAIL PROTECTED]>, php-general@lists.php.net
Sent: Tuesday, July 31, 2007 9:43:00 AM (GMT-0500) America/New_York
Subject: RE: [PHP] Array difficulty
> At this point, $result would be equal to "uppercase". I feel
> like this is a really kludgey way to accomplish this. Is there
> a better way?
Couldn't you just do
arsort($chance);
$lastItem = chance[( count( $chance ) - 1 )];
? Why iterate through the array when all you need is the last value?
thnx,
Chris
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RE: [PHP] Array difficulty
> At this point, $result would be equal to "uppercase". I feel > like this is a really kludgey way to accomplish this. Is there > a better way? Couldn't you just do arsort($chance); $lastItem = chance[( count( $chance ) - 1 )]; ? Why iterate through the array when all you need is the last value? thnx, Chris -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Array difficulty
Hi Carlton,
Tuesday, July 31, 2007, 2:27:46 PM, you wrote:
> I have an array like this:
> $chance = array("lowercase" => 27, "uppercase" => 62, "integer" => 46);
> The values for each of the keys are randomly generated. I want to
> find the key name of the one which has the highest value. Currently, I'm
> doing this as follows:
> arsort($chance);
> foreach ($chance as $type => $value)
> {
> $result = $type;
> break;
> }
> At this point, $result would be equal to "uppercase". I feel like
> this is a really kludgey way to accomplish this. Is there a better way?
Not tested it, but max() should work as the first parameter can be an
array:
http://uk3.php.net/max
Cheers,
Rich
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[PHP] Array difficulty
Hi all,
I have an array like this:
$chance = array("lowercase" => 27, "uppercase" => 62, "integer" => 46);
The values for each of the keys are randomly generated. I want to find the key
name of the one which has the highest value. Currently, I'm doing this as
follows:
arsort($chance);
foreach ($chance as $type => $value)
{
$result = $type;
break;
}
At this point, $result would be equal to "uppercase". I feel like this is a
really kludgey way to accomplish this. Is there a better way?
Regards,
Carlton Whitehead
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