Re: [PHP] Calendar Problem
At 4:08 PM -0400 8/11/09, Robert Cummings wrote:
tedd wrote:
Hi gang:
I want to show the dates for all Fridays +-30 days from a specific date.
For example, given today's date (8/11/2009) the Fridays that fall
+-30 days are July 17, July 24, July 31, Aug 7, Aug 14, Aug 21, Aug
28, and Sept 4.
I'm curious, how would you guys solve this?
?php
$fridays = array();
for( $i = -30; $i = 30; $i++ )
{
$mod = $i 0 ? $i : '+'.$i;
$time = strtotime( $mod.' day' );
if( date( 'D', $time ) == 'Fri' )
{
$fridays[] = date( 'Y-m-d', $time );
}
}
print_r( $fridays );
?
Cheers,
Rob.
Rob:
That's slick -- you never let me down with your simplicity and creativity.
My solution was to find the next Friday and then cycle through +-28
days (four weeks) from that date, like so:
?php
$fridays = array();
for( $i = 1; $i = 7; $i++ )
{
$time = strtotime( $i . ' day' );
if( date( 'D', $time ) == 'Fri' )
{
$start = 28 - $i;
$end = 28 + $i;
}
}
for( $i = -$start; $i = $end; $i += 7 )
{
$time = strtotime( $i . ' day' );
$fridays[] = date( 'Y-m-d', $time );
}
print_r( $fridays );
?
Your solution had 61 iterations (for loop) while mind had only 21, so
mine's a bit faster. Here's the comparison:
http://php1.net/b/fridays/
But I'll use your solution -- it's more elegant.
Thanks for the code,
tedd
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Re: [PHP] Calendar Problem
tedd wrote:
At 4:08 PM -0400 8/11/09, Robert Cummings wrote:
tedd wrote:
Hi gang:
I want to show the dates for all Fridays +-30 days from a specific date.
For example, given today's date (8/11/2009) the Fridays that fall
+-30 days are July 17, July 24, July 31, Aug 7, Aug 14, Aug 21, Aug
28, and Sept 4.
I'm curious, how would you guys solve this?
?php
$fridays = array();
for( $i = -30; $i = 30; $i++ )
{
$mod = $i 0 ? $i : '+'.$i;
$time = strtotime( $mod.' day' );
if( date( 'D', $time ) == 'Fri' )
{
$fridays[] = date( 'Y-m-d', $time );
}
}
print_r( $fridays );
?
Cheers,
Rob.
Rob:
That's slick -- you never let me down with your simplicity and creativity.
My solution was to find the next Friday and then cycle through +-28
days (four weeks) from that date, like so:
?php
$fridays = array();
for( $i = 1; $i = 7; $i++ )
{
$time = strtotime( $i . ' day' );
if( date( 'D', $time ) == 'Fri' )
{
$start = 28 - $i;
$end = 28 + $i;
}
}
for( $i = -$start; $i = $end; $i += 7 )
{
$time = strtotime( $i . ' day' );
$fridays[] = date( 'Y-m-d', $time );
}
print_r( $fridays );
?
Your solution had 61 iterations (for loop) while mind had only 21, so
mine's a bit faster. Here's the comparison:
http://php1.net/b/fridays/
But I'll use your solution -- it's more elegant.
Thanks for the code,
tedd
I think Shawn McKenzie's is the best. It seems his would take at most 12
iterations.
Cheers,
Rob.
--
http://www.interjinn.com
Application and Templating Framework for PHP
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Re: [PHP] Calendar Problem
At 4:08 PM -0400 8/11/09, Robert Cummings wrote: I think Shawn McKenzie's is the best. It seems his would take at most 12 iterations. Cheers, Rob. Rob: For some reason I did not see/consider Shawn's solutions -- sorry Shawn. However, it appears that mine is still the fastest in most test. Check this: http://php1.net/b/fridays/ Cheers, tedd -- --- http://sperling.com http://ancientstones.com http://earthstones.com -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Calendar Problem
On Wed, Aug 12, 2009 at 10:25 AM, Robert Cummings rob...@interjinn.comwrote:
tedd wrote:
At 4:08 PM -0400 8/11/09, Robert Cummings wrote:
tedd wrote:
Hi gang:
I want to show the dates for all Fridays +-30 days from a specific date.
For example, given today's date (8/11/2009) the Fridays that fall +-30
days are July 17, July 24, July 31, Aug 7, Aug 14, Aug 21, Aug 28, and Sept
4.
I'm curious, how would you guys solve this?
?php
$fridays = array();
for( $i = -30; $i = 30; $i++ )
{
$mod = $i 0 ? $i : '+'.$i;
$time = strtotime( $mod.' day' );
if( date( 'D', $time ) == 'Fri' )
{
$fridays[] = date( 'Y-m-d', $time );
}
}
print_r( $fridays );
?
Cheers,
Rob.
Rob:
That's slick -- you never let me down with your simplicity and creativity.
My solution was to find the next Friday and then cycle through +-28 days
(four weeks) from that date, like so:
?php
$fridays = array();
for( $i = 1; $i = 7; $i++ )
{
$time = strtotime( $i . ' day' );
if( date( 'D', $time ) == 'Fri' )
{
$start = 28 - $i;
$end = 28 + $i;
}
}
for( $i = -$start; $i = $end; $i += 7 )
{
$time = strtotime( $i . ' day' );
$fridays[] = date( 'Y-m-d', $time );
}
print_r( $fridays );
?
Your solution had 61 iterations (for loop) while mind had only 21, so
mine's a bit faster. Here's the comparison:
http://php1.net/b/fridays/
But I'll use your solution -- it's more elegant.
Thanks for the code,
tedd
I think Shawn McKenzie's is the best. It seems his would take at most 12
iterations.
Cheers,
Rob.
--
http://www.interjinn.com
Application and Templating Framework for PHP
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
Hi all
This is my point of view.
I try to stay the most legible and simple as possible.
@tedd: can you benchmark this script too? usualy legibility performance
?php
$fridays = array(); # I'll store the friday here
$day = strtotime('-1 month', time() ); # let's start at one month ago
while( 5 != date('w', $day)) # advance to a friday
$day = strtotime('+1 day', $day);
# I'll stop when $day where ahead one month from today
$end = strtotime( '+1 month', time() );
do{
$friday[] = date('Y-m-d', $day); # store the friday
$day = strtotime('+1 week', $day); # advance one week
} while( $day $end );
# job's done!
print_r( $friday );
--
Martin Scotta
Re: [PHP] Calendar Problem
2009/8/12 tedd tedd.sperl...@gmail.com: At 4:08 PM -0400 8/11/09, Robert Cummings wrote: I think Shawn McKenzie's is the best. It seems his would take at most 12 iterations. Cheers, Rob. Rob: For some reason I did not see/consider Shawn's solutions -- sorry Shawn. However, it appears that mine is still the fastest in most test. Check this: http://php1.net/b/fridays/ Bit late to this party, but give this a whizz... http://dev.stut.net/php/fridays.php -Stuart -- http://stut.net/ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Calendar Problem
At 11:03 AM -0300 8/12/09, Martin Scotta wrote:
Hi all
This is my point of view.
I try to stay the most legible and simple as possible.
@tedd: can you benchmark this script too? usualy legibility performance
?php
$fridays = array(); # I'll store the friday here
$day = strtotime('-1 month', time() ); # let's start at one month ago
while( 5 != date('w', $day)) # advance to a friday
$day = strtotime('+1 day', $day);
# I'll stop when $day where ahead one month from today
$end = strtotime( '+1 month', time() );
do{
$friday[] = date('Y-m-d', $day); # store the friday
$day = strtotime('+1 week', $day); # advance one week
} while( $day $end );
# job's done!
print_r( $friday );
--
Martin Scotta
Martin:
It's included here:
http://php1.net/b/fridays/
Works great -- thanks.
As Shawn said Many ways to skin a cat
As Jeff Foxworthy added But he ain't going to like any of them!
Cheers,
tedd
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Re: [PHP] Calendar Problem
tedd wrote: Your solution had 61 iterations (for loop) while mind had only 21, so mine's a bit faster. Here's the comparison: http://php1.net/b/fridays/ But I'll use your solution -- it's more elegant. Thanks for the code, tedd Actually, if you refresh your page you have different winners. When I first visited the page yours was fastest by approximately .001, but on refresh yours is slower by .001. You need to execute the test let's say 100 or 1000 times or more (more is better) and take either the average or I would say the minimum. -- Thanks! -Shawn http://www.spidean.com -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Calendar Problem
At 3:26 PM +0100 8/12/09, Stuart wrote: 2009/8/12 tedd tedd.sperl...@gmail.com: At 4:08 PM -0400 8/11/09, Robert Cummings wrote: I think Shawn McKenzie's is the best. It seems his would take at most 12 iterations. Cheers, Rob. Rob: For some reason I did not see/consider Shawn's solutions -- sorry Shawn. However, it appears that mine is still the fastest in most test. Check this: http://php1.net/b/fridays/ Bit late to this party, but give this a whizz... http://dev.stut.net/php/fridays.php -Stuart It's included here: http://php1.net/b/fridays/ Looks like your solution is the fastest. Cheers, tedd -- --- http://sperling.com http://ancientstones.com http://earthstones.com -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Calendar Problem
At 9:50 AM -0500 8/12/09, Shawn McKenzie wrote: tedd wrote: Your solution had 61 iterations (for loop) while mind had only 21, so mine's a bit faster. Here's the comparison: http://php1.net/b/fridays/ But I'll use your solution -- it's more elegant. Thanks for the code, tedd Actually, if you refresh your page you have different winners. When I first visited the page yours was fastest by approximately .001, but on refresh yours is slower by .001. You need to execute the test let's say 100 or 1000 times or more (more is better) and take either the average or I would say the minimum. -- Thanks! But of course -- no one try is definitive, you need many. For example, I wrote a script to show that PHP's rounding function had an upward bias, which it does, but it took thousands of iterations to see it. Not worth the effort to correct. In any event, it's interesting to see how we all approached the problem from different directions. Cheers, tedd -- --- http://sperling.com http://ancientstones.com http://earthstones.com -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Calendar Problem
On Wed, Aug 12, 2009 at 12:07 PM, tedd tedd.sperl...@gmail.com wrote: At 9:50 AM -0500 8/12/09, Shawn McKenzie wrote: tedd wrote: Your solution had 61 iterations (for loop) while mind had only 21, so mine's a bit faster. Here's the comparison: http://php1.net/b/fridays/ But I'll use your solution -- it's more elegant. Thanks for the code, tedd Actually, if you refresh your page you have different winners. When I first visited the page yours was fastest by approximately .001, but on refresh yours is slower by .001. You need to execute the test let's say 100 or 1000 times or more (more is better) and take either the average or I would say the minimum. -- Thanks! But of course -- no one try is definitive, you need many. For example, I wrote a script to show that PHP's rounding function had an upward bias, which it does, but it took thousands of iterations to see it. Not worth the effort to correct. In any event, it's interesting to see how we all approached the problem from different directions. Cheers, tedd -- --- http://sperling.com http://ancientstones.com http://earthstones.com -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php Well, this was a nice experiment. What do we must learn about this? performance legibility Stuart solutions look that's the faster, but in the other hand Shawn's solution 2 looks the most legible (so far). -- Martin Scotta
[PHP] Calendar Problem
Hi gang: I want to show the dates for all Fridays +-30 days from a specific date. For example, given today's date (8/11/2009) the Fridays that fall +-30 days are July 17, July 24, July 31, Aug 7, Aug 14, Aug 21, Aug 28, and Sept 4. I'm curious, how would you guys solve this? Cheers, tedd -- --- http://sperling.com http://ancientstones.com http://earthstones.com -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Calendar Problem
tedd wrote:
Hi gang:
I want to show the dates for all Fridays +-30 days from a specific date.
For example, given today's date (8/11/2009) the Fridays that fall
+-30 days are July 17, July 24, July 31, Aug 7, Aug 14, Aug 21, Aug
28, and Sept 4.
I'm curious, how would you guys solve this?
?php
$fridays = array();
for( $i = -30; $i = 30; $i++ )
{
$mod = $i 0 ? $i : '+'.$i;
$time = strtotime( $mod.' day' );
if( date( 'D', $time ) == 'Fri' )
{
$fridays[] = date( 'Y-m-d', $time );
}
}
print_r( $fridays );
?
Cheers,
Rob.
--
http://www.interjinn.com
Application and Templating Framework for PHP
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Calendar Problem
Robert Cummings wrote:
tedd wrote:
Hi gang:
I want to show the dates for all Fridays +-30 days from a specific date.
For example, given today's date (8/11/2009) the Fridays that fall +-30
days are July 17, July 24, July 31, Aug 7, Aug 14, Aug 21, Aug 28, and
Sept 4.
I'm curious, how would you guys solve this?
?php
$fridays = array();
for( $i = -30; $i = 30; $i++ )
{
$mod = $i 0 ? $i : '+'.$i;
man, please use some parenthesis...
my translation of the above would be the following:
$mod = (($i 0) ? $i : ('+'.$i));
would that be correct?
$time = strtotime( $mod.' day' );
if( date( 'D', $time ) == 'Fri' )
{
$fridays[] = date( 'Y-m-d', $time );
}
}
print_r( $fridays );
?
Cheers,
Rob.
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Re: [PHP] Calendar Problem
Jim Lucas wrote:
Robert Cummings wrote:
tedd wrote:
Hi gang:
I want to show the dates for all Fridays +-30 days from a specific date.
For example, given today's date (8/11/2009) the Fridays that fall +-30
days are July 17, July 24, July 31, Aug 7, Aug 14, Aug 21, Aug 28, and
Sept 4.
I'm curious, how would you guys solve this?
?php
$fridays = array();
for( $i = -30; $i = 30; $i++ )
{
$mod = $i 0 ? $i : '+'.$i;
man, please use some parenthesis...
my translation of the above would be the following:
$mod = (($i 0) ? $i : ('+'.$i));
would that be correct?
Yes... in a superfluous hold-my-hand sort of way :)
Cheers,
Rob.
--
http://www.interjinn.com
Application and Templating Framework for PHP
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Re: [PHP] Calendar Problem
On Tue, Aug 11, 2009 at 03:53:58PM -0400, tedd wrote: Hi gang: I want to show the dates for all Fridays +-30 days from a specific date. For example, given today's date (8/11/2009) the Fridays that fall +-30 days are July 17, July 24, July 31, Aug 7, Aug 14, Aug 21, Aug 28, and Sept 4. I'm curious, how would you guys solve this? Convert to julian days, then add or subtract days as desired. Then convert back to gregorian. Paul -- Paul M. Foster -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] Calendar problem
I have two fields in my form. When two dates are entered in these two boxes, I need to find the diiference in calendar months and remaining days between these two dates. This Calendar months and remaining days is important. The functions that I know do not work for calendar months. Can anyone help me and tell me how this could be achieved and are there any PHP functions to do this? You can use strtotime() (probably) to convert what's entered into a unix timestamp. From there you know how many seconds are in a day, so a little math can figure out how many days are between the two dates. You can use date() to find out the month of each one and do some more math... ---John W. Holmes... PHP Architect - A monthly magazine for PHP Professionals. Get your copy today. http://www.phparch.com/ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Calendar problem
Hello friends. I have two fields in my form. When two dates are entered in these two boxes, I need to find the diiference in calendar months and remaining days between these two dates. This Calendar months and remaining days is important. The functions that I know do not work for calendar months. Can anyone help me and tell me how this could be achieved and are there any PHP functions to do this? best regards Denis -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
