Re: [PHP] Destroy a session var passed as an argument

On Wednesday, April 24, 2002, at 02:59 PM, Julio Nobrega Trabalhando wrote: > And this is how I use it: > > if (isset($_SESSION['forum']['error']['insert'])) { > echo showError($_SESSION['forum']['error']['insert'])); > } Try this: function showError(&$mensagem) { // print what

Re: [PHP] Destroy a session var passed as an argument

> And let me know if that works or doesn't work. (It's kind of a hunch, > hard to tell from your code if it will work.) Didn't. I still get the same error, using unset($mensagem). Also tried: global $mensagem; session_unregister($mensagem) Also tried: showError(&$_SESSION And a mix

Re: [PHP] Destroy a session var passed as an argument

On Wednesday, April 24, 2002, at 02:59 PM, Julio Nobrega Trabalhando wrote: > I have a simple function that returns a message: > > function showError ($mensagem) > { > return '' . $mensagem . ''; > } > > And this is how I use it: > > if (isset($_SESSION['forum']['error']['insert'])) {

[PHP] Destroy a session var passed as an argument

Hi All! I have a simple function that returns a message: function showError ($mensagem) { return '' . $mensagem . ''; } And this is how I use it: if (isset($_SESSION['forum']['error']['insert'])) { echo showError($_SESSION['forum']['error']['insert'])); } But I want that when