[PHP] Dumb Question - Casting

2010-02-18 Thread Chuck
Sorry, been doing heavy perl and haven't written any PHP in 3 years so a tad rusty. Can someone explain why the second expression in this code snippet evaluates to 7 and not 8? $a = (int) (0.1 +0.7); echo $a\n; $x = (int) ((0.1 + 0.7) * 10); echo $x\n; $y = (int) (8); echo $y\n;

Re: [PHP] Dumb Question - Casting

2010-02-18 Thread Ashley Sheridan
On Thu, 2010-02-18 at 09:47 -0600, Chuck wrote: Sorry, been doing heavy perl and haven't written any PHP in 3 years so a tad rusty. Can someone explain why the second expression in this code snippet evaluates to 7 and not 8? $a = (int) (0.1 +0.7); echo $a\n; $x = (int) ((0.1 + 0.7)

Re: [PHP] Dumb Question - Casting

2010-02-18 Thread Andrew Ballard
On Thu, Feb 18, 2010 at 10:50 AM, Ashley Sheridan a...@ashleysheridan.co.uk wrote: On Thu, 2010-02-18 at 09:47 -0600, Chuck wrote: Sorry, been doing heavy perl and haven't written any PHP in 3 years so a tad rusty. Can someone explain why the second expression in this code snippet evaluates

Re: [PHP] Dumb Question - Casting

2010-02-18 Thread Daniel Egeberg
On Thu, Feb 18, 2010 at 16:47, Chuck chuck.car...@gmail.com wrote: Sorry, been doing heavy perl and haven't written any PHP in 3 years so a tad rusty. Can someone explain why the second expression in this code snippet evaluates to 7 and not 8? $a = (int) (0.1 +0.7); echo $a\n; $x =

Re: [PHP] Dumb Question - Casting

2010-02-18 Thread Joseph Thayne
According to the PHP manual using the same expression, Never cast an unknown fraction to integer, as this can sometimes lead to unexpected results. My guess is that since it is an expression of floating points, that the result is not quite 8 (for whatever reason). Therefore, it is rounded

Re: [PHP] Dumb Question - Casting

2010-02-18 Thread Nathan Rixham
Daniel Egeberg wrote: On Thu, Feb 18, 2010 at 16:47, Chuck chuck.car...@gmail.com wrote: Sorry, been doing heavy perl and haven't written any PHP in 3 years so a tad rusty. Can someone explain why the second expression in this code snippet evaluates to 7 and not 8? $a = (int) (0.1 +0.7);

[PHP] DUMB QUESTION I'M SURE

2003-01-02 Thread Adam French
I'm just starting out, this is my script... ? $name = $_POST['username']; $name = $name; $db = mysql_connect(localhost); mysql_select_db(vinyldealers,$db); $query = SELECT shops.name FROM shops WHERE name = .$name.; $result = mysql_query($query); while ($record = mysql_fetch_assoc($result)) {

Re: [PHP] DUMB QUESTION I'M SURE

2003-01-02 Thread Tom Rogers
Hi, Friday, January 3, 2003, 4:18:05 PM, you wrote: AF I'm just starting out, this is my script... AF ? AF $name = $_POST['username']; AF $name = $name; AF $db = mysql_connect(localhost); AF mysql_select_db(vinyldealers,$db); AF $query = SELECT shops.name FROM shops WHERE name = .$name.; AF

RE: [PHP] DUMB QUESTION I'M SURE

2003-01-02 Thread Cesar Aracena
PROTECTED] Asunto: [PHP] DUMB QUESTION I'M SURE I'm just starting out, this is my script... ? $name = $_POST['username']; $name = $name; $db = mysql_connect(localhost); mysql_select_db(vinyldealers,$db); $query = SELECT shops.name FROM shops WHERE name = .$name.; $result = mysql_query($query); while

RE: [PHP] DUMB QUESTION I'M SURE

2003-01-02 Thread Cesar Aracena
de enero de 2003 3:18 Para: [EMAIL PROTECTED] Asunto: [PHP] DUMB QUESTION I'M SURE I'm just starting out, this is my script... ? $name = $_POST['username']; $name = $name; $db = mysql_connect(localhost); mysql_select_db(vinyldealers,$db); $query = SELECT shops.name FROM shops WHERE name = .$name

Re: [PHP] DUMB QUESTION I'M SURE

2003-01-02 Thread Jason k Larson
I think it's just the $query var not having the right number of quotes. I added single quotes around the value. ? $name = $_POST['username']; $name = $name; $db = mysql_connect(localhost); mysql_select_db(vinyldealers,$db); $query = SELECT shops.name FROM shops WHERE name = '.$name.'; $result =

RE: [PHP] DUMB QUESTION I'M SURE

2003-01-02 Thread rw
[mailto:[EMAIL PROTECTED]] ### Enviado el: viernes, 03 de enero de 2003 3:18 ### Para: [EMAIL PROTECTED] ### Asunto: [PHP] DUMB QUESTION I'M SURE ### ### I'm just starting out, this is my script... ### ### ? ### $name = $_POST['username']; ### $name = $name; ### $db = mysql_connect(localhost

[PHP] Dumb Question

2002-08-31 Thread Gerard Samuel
And I feel foolish asking... What is meant by 'procedural code' ??? -- Gerard Samuel http://www.trini0.org:81/ http://dev.trini0.org:81/ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php

Re: [PHP] Dumb Question

2002-08-31 Thread @ Edwin
My "dumb" answer :) Try Google. Type: "procedural code" You might want to check, "object-oriented" as well... I'm sure, you'll find helpful explanations... - E And I feel foolish asking... What is meant by 'procedural code' ??? -- Gerard Samuel http://www.trini0.org:81/

Re: [PHP] Dumb Question

2002-08-31 Thread Gerard Samuel
Google didn't have much to offer. But if I should also check 'object-oriented' then I believe it deals with classes. I thought it was something else. Just trying to figure out if phpdoc is for me, which it seems like its not :( Thanks @ Edwin wrote: My "dumb" answer :) Try Google. Type:

Re: [PHP] Dumb Question

2002-08-31 Thread @ Edwin
Google didn't have much to offer. Sorry 'bout that. Actually, if you have an idea of what OO ("object-oriented") is, I think I can say that "procedural" is just the opposite of it. I tried Google myself and this came out on top: "Writing Procedural Code in Non-Procedural SQL" There's a

Re: [PHP] Dumb Question

2002-08-31 Thread Michael Sims
On Sat, 31 Aug 2002 14:04:11 -0400, you wrote: And I feel foolish asking... What is meant by 'procedural code' ??? It's the opposite of declarative code. Here's a page that briefly explains the difference: http://www.wdvl.com/Authoring/DB/SQL/BeginSQL/beginSQL2_1.html and

Re: [PHP] Dumb Question

2002-08-31 Thread Gerard Samuel
Here is my stab at it. One person described it as the opposite of OO. So something similar to - ?php do_this() { // do this code } do_that() { // do that code } if (isset( $_GET['foo'] )) { do_this(); } else { do_that(); } ? would be considered procedural code. If Im wrong I

[PHP] Dumb question

2002-08-21 Thread Liam MacKenzie
Hey guys, got a basic question for you... ? function getvar() { $vari = bollocks; } getvar(); echo $vari; ? How do I make that function return the variable? Thanks, Liam -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php

Re: [PHP] Dumb question

2002-08-21 Thread Bob Irwin
] Sent: Thursday, August 22, 2002 1:27 PM Subject: [PHP] Dumb question Hey guys, got a basic question for you... ? function getvar() { $vari = bollocks; } getvar(); echo $vari; ? How do I make that function return the variable? Thanks, Liam -- PHP General

[Fwd: Re: [PHP] Dumb question]

2002-08-21 Thread David Christensen
() { global $vari; $vari = bollocks; } getvar(); echo $vari; ? Best Regards Bob Irwin Server Admin Web Programmer Planet Netcom - Original Message - From: Liam MacKenzie [EMAIL PROTECTED] To: [EMAIL PROTECTED] Sent: Thursday, August 22, 2002 1:27 PM Subject: [PHP] Dumb

[PHP] Dumb question on terminology

2002-02-26 Thread Dean Householder
Some arrays use the format: $row-data while some use: $row['data'] What is the terminology of these types so I sound like I know what I'm talking about. Also, when and how do each come about? Dean

RE: [PHP] Dumb question on terminology

2002-02-26 Thread Martin Towell
, February 27, 2002 11:32 AM To: [EMAIL PROTECTED] Subject: [PHP] Dumb question on terminology Some arrays use the format: $row-data while some use: $row['data'] What is the terminology of these types so I sound like I know what I'm talking about. Also, when and how do each come about? Dean