RE: [PHP] Error message trying to include a file
On maandag 1 december 2003 23:17 Curt Zirzow told the butterflies: * Thus wrote Matthias Wulkow ([EMAIL PROTECTED]): I have an array filled with urls of javascript files and then I include them one by one in a loop. for( $i = 0 ; $i sizeof($this-page-javascript) ; $i++ ){ include($this-page-javascript[$i]); //This line above is line 52 shown on error warning } what does print_r($this-page-javascript) yield? you'd be better off with a loop like: foreach($this-page-javascript as $file_to_include) { include($file_to_include); } Curt -- If eval() is the answer, you're almost certainly asking the wrong question. -- Rasmus Lerdorf, BDFL of PHP Probably include($this-page-javascript[$i]); Is the problem. There's this thing in PHP that you can't do this thing with referencing to an object property from within an other object. Or whatever to call that. Sounds silly and stupid, but it bullies me too. Try this: $Page = $this-page; foreach($Page-javascript as $File) include($File); or this (if you care about memory usage): $Page = $this-page; foreach(array_keys($Page-javascript) as $i) include($Page-javascript[$i]); Because php doesn't do reference thingies in a foreach loop, sadly. Wouter -note that you do not need { and } for oneline if/foreach/for/while/.. blocks -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Error message trying to include a file
Hi php-general, I have an array filled with urls of javascript files and then I include them one by one in a loop. for( $i = 0 ; $i sizeof($this-page-javascript) ; $i++ ){ include($this-page-javascript[$i]); //This line above is line 52 shown on error warning } When I had only two files to include it worked. Now I added a third and I get following error message: Notice: Undefined offset: 2 in /usr/local/www/ViewPageClass.php on line 52 Warning: writehead() [function.writehead]: Failed opening '' for inclusion (include_path='.:/usr/local/lib/php') in /usr/local/www/ViewPageClass.php on line 52 I don't really know what to do,the function writehead doesn't seem to exist... the javascript file is http://pajhome.org.uk/crypt/md5/md5.js. I suppose it's free of errors... SvT -- Who is the ennemy? -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Error message trying to include a file
Hi php-general, sorry for the post before, forget the sentence about the writehead function. It means writeHead() (error Warning doesn't seem to be case sensitive...). It's the name of my method... :-( But it has nothing to do with the error itself... SvT -- Who is the ennemy? -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Error message trying to include a file
* Thus wrote Matthias Wulkow ([EMAIL PROTECTED]): I have an array filled with urls of javascript files and then I include them one by one in a loop. for( $i = 0 ; $i sizeof($this-page-javascript) ; $i++ ){ include($this-page-javascript[$i]); //This line above is line 52 shown on error warning } what does print_r($this-page-javascript) yield? you'd be better off with a loop like: foreach($this-page-javascript as $file_to_include) { include($file_to_include); } Curt -- If eval() is the answer, you're almost certainly asking the wrong question. -- Rasmus Lerdorf, BDFL of PHP -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php