RE: [PHP] Error message trying to include a file

2003-12-02 Thread Wouter van Vliet
On maandag 1 december 2003 23:17 Curt Zirzow told the butterflies:
 * Thus wrote Matthias Wulkow ([EMAIL PROTECTED]):
  
  I have an array filled with urls of javascript files and then I
  include them one by one in a loop.
  
  for( $i = 0 ; $i  sizeof($this-page-javascript) ; $i++ ){
  
   include($this-page-javascript[$i]);
   //This line above is line 52 shown on error warning }
 
 what does print_r($this-page-javascript) yield?
 
 you'd be better off with a loop like:
 foreach($this-page-javascript as $file_to_include) {  
 include($file_to_include); }
 
 
 
 Curt
 --
 If eval() is the answer, you're almost certainly asking the
 wrong question. -- Rasmus Lerdorf, BDFL of PHP

Probably 

include($this-page-javascript[$i]);

Is the problem. There's this thing in PHP that you can't do this thing with
referencing to an object property from within an other object. Or whatever
to call that. Sounds silly and stupid, but it bullies me too. Try this:

$Page = $this-page;
foreach($Page-javascript as $File) include($File);

or this (if you care about memory usage):

$Page = $this-page;
foreach(array_keys($Page-javascript) as $i)
include($Page-javascript[$i]);

Because php doesn't do reference thingies in a foreach loop, sadly.

Wouter

-note that you do not need { and } for oneline if/foreach/for/while/..
blocks

-- 
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php



[PHP] Error message trying to include a file

2003-12-01 Thread Matthias Wulkow

Hi php-general,

I have an array filled with urls of javascript files and then I
include them one by one in a loop.

for( $i = 0 ; $i  sizeof($this-page-javascript) ; $i++ ){

 include($this-page-javascript[$i]);
 //This line above is line 52 shown on error warning
}

When I had only two files to include it worked. Now I added a third
and I get following error message:

Notice: Undefined offset: 2 in /usr/local/www/ViewPageClass.php on line 52

Warning: writehead() [function.writehead]:
Failed opening '' for inclusion (include_path='.:/usr/local/lib/php')
in /usr/local/www/ViewPageClass.php on line 52

I don't really know what to do,the function writehead doesn't seem to
exist... the javascript file is
http://pajhome.org.uk/crypt/md5/md5.js. I suppose it's free of
errors...

SvT

-- 
Who is the ennemy?

-- 
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php



[PHP] Error message trying to include a file

2003-12-01 Thread Matthias Wulkow

Hi php-general,

sorry for the post before, forget the sentence about the writehead
function. It means writeHead() (error Warning doesn't seem to be case
sensitive...). It's the name of my method... :-(
But it has nothing to do with the error itself...

SvT

-- 
Who is the ennemy?

-- 
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php



Re: [PHP] Error message trying to include a file

2003-12-01 Thread Curt Zirzow
* Thus wrote Matthias Wulkow ([EMAIL PROTECTED]):
 
 I have an array filled with urls of javascript files and then I
 include them one by one in a loop.
 
 for( $i = 0 ; $i  sizeof($this-page-javascript) ; $i++ ){
 
  include($this-page-javascript[$i]);
  //This line above is line 52 shown on error warning
 }

what does print_r($this-page-javascript) yield?

you'd be better off with a loop like:
foreach($this-page-javascript as $file_to_include) {
  include($file_to_include);
}



Curt
-- 
If eval() is the answer, you're almost certainly asking the
wrong question. -- Rasmus Lerdorf, BDFL of PHP

-- 
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php