Use eval ... although beware of the serious security implications.
Hi.
I'm changing my website to one based on My-SQL which will help with
organization and searching etc. Hopefully, the code for all the pages
will be stored in the database too.
However, I cannot get PHP to parse / execute the code stored in the
database. The script
$query = mysql_query(SELECT * FROM pages, $link);
$result = mysql_fetch_array($query);
print $result['4'];
gets the content of the page (column 4 of the database) but displays
include(common/counter.php); include(common/navbar.php);
to the screen instead of opening and including these two files in the
output.
Is there something I need to do to the result to make it executable?
Might I need a \n between the two lines of code?
I'm using Win 98, Apache 1.3.19, PHP 4.2.0 and MySQL but I'm not sure
which version! (fairly recent though)
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Dan Hardiker [[EMAIL PROTECTED]]
ADAM Software Systems Engineer
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