[PHP] Invalid Argument why?

2009-07-16 Thread Miller, Terion
Why is this an invalid argument? foreach(($row['inType']) as $inType){ echo $inType,'br';} I am trying to output results from a data base that may have multiple results for the same name So trying to use an array and foreach that is the right track ...right? -- PHP General Mailing List

Re: [PHP] Invalid Argument why?

2009-07-16 Thread Ashley Sheridan
On Thu, 2009-07-16 at 15:41 -0400, Miller, Terion wrote: Why is this an invalid argument? foreach(($row['inType']) as $inType){ echo $inType,'br';} I am trying to output results from a data base that may have multiple results for the same name So trying to use an array and

Re: [PHP] Invalid Argument why?

2009-07-16 Thread Kyle Smith
Miller, Terion wrote: Why is this an invalid argument? foreach(($row['inType']) as $inType){ echo $inType,'br';} I am trying to output results from a data base that may have multiple results for the same name So trying to use an array and foreach that is the right track ...right?

Re: [PHP] Invalid Argument why? (RESOLVED)

2009-07-16 Thread Miller, Terion
Actually this ended up doing what I needed: $result = mysql_query($sql) or die(mysql_error()); $header = false;

Re: [PHP] Invalid Argument why?

2009-07-16 Thread Martin Scotta
foreach iterates over an array or a object (see Traversable ). If you pass anything different he complains ?php if( !is_scalar( $collection ) ) foreach( $collection as $element ) print_r( $element ); On Thu, Jul 16, 2009 at 4:53 PM, Kyle Smith kyle.sm...@inforonics.comwrote: