* Thus wrote Ben Edwards ([EMAIL PROTECTED]):
> Wan I insatiate an object I want to pass a database resource that can be
> used throughout the object. The below code should indicate what I want but
> I get the error "mysql_query(): supplied argument is not a valid MySQL-Link
> resource". I gue
Wan I insatiate an object I want to pass a database resource that can be
used throughout the object. The below code should indicate what I want but
I get the error "mysql_query(): supplied argument is not a valid MySQL-Link
resource". I guess this is because "$this->$db = $db" is wrong.
Ben
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