[PHP] Please help me with in_array
Hi all I have been stuck on this problem for 4 hours. Please anyone that can help here I would appreciate it. If I print_r($_GET) I have Array ([question] = Array ( [10] = 1 [11] = 2 [12] = 1 [13] = 1)' So now I try foreach($_GET['question'] as $key) { if(!in_array($key, $_SESSION['question'])) { print not matched lets updatebr. $_GET[question][$key]; // HERE I WANT IT TO SHOW $key is 10 and its value should be 1 (as printed in the Array above) } else { print matched; } } Where it gets to the section not matched I need to print out from the question array question[$key][$value] (question '10' = '1' as above) I am not sure if I am even making sense here anymore... Thanks in advance Chris
Re: [PHP] Please help me with in_array
Chris G wrote: Hi all I have been stuck on this problem for 4 hours. Please anyone that can help here I would appreciate it. If I print_r($_GET) I have Array ([question] = Array ( [10] = 1 [11] = 2 [12] = 1 [13] = 1)' So now I try foreach($_GET['question'] as $key) { foreach($_GET['question'] as $key = $value) { if(!in_array($key, $_SESSION['question'])) { print not matched lets updatebr. $_GET[question][$key]; // HERE I WANT IT TO SHOW $key is 10 and its value should be 1 (as printed in the Array above) } else { print matched; } } Where it gets to the section not matched I need to print out from the question array question[$key][$value] (question '10' = '1' as above) I am not sure if I am even making sense here anymore... Thanks in advance Chris -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Please help me with in_array
Chris G wrote: I have already tried using foreach($_GET['question'] as $key = $value) the in_array function does not work with it for some reason. 'does not work with it' ?? use var_dump(); to see what's actually in your variables. On 8/5/06, *Jochem Maas* [EMAIL PROTECTED] mailto:[EMAIL PROTECTED] wrote: foreach($_GET['question'] as $key = $value) { var_dump($key, $value); if(!in_array($key, $_SESSION['question'])) { print not matched lets updatebr. $_GET[question][$key]; // HERE I WANT IT TO SHOW $key is 10 and its value should be 1 (as printed in the Array above) } else { print matched; } } Where it gets to the section not matched I need to print out from the question array question[$key][$value] (question '10' = '1' as above) I am not sure if I am even making sense here anymore... Thanks in advance Chris -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php