Fernando A soporteallpurp...@gmail.com wrote:
I am working with php and codeigniter, but I have not yet experienced.
I need create a variable that is available throughout system.
This variable contains the number of company and can change.
as I can handle this?
Hi, Fernando, welcome. I'm
Hello,
I am working with php and codeigniter, but I have not yet experienced.
I need create a variable that is available throughout system.
This variable contains the number of company and can change.
as I can handle this?
Thank you, very much!
Ferd
Paul Halliday wrote:
I think I just might be missing the logic here.
I have a page that is created and within this page, I include an
iframe like this:
$qp = urlencode($when $wFilter $aFilter);
echo \rtrtd id=links colspan=2 style=\display:none; padding-left:
12px;\
\rIFRAME
On Thu, Sep 2, 2010 at 5:43 PM, Jim Lucas li...@cmsws.com wrote:
Paul Halliday wrote:
I think I just might be missing the logic here.
I have a page that is created and within this page, I include an
iframe like this:
$qp = urlencode($when $wFilter $aFilter);
echo \rtrtd id=links colspan=2
I have a problem that i cant send variable over a form. Because of that when i watn
to echo the variable next page an error occured...i use redhat 9.0, apache 2 and php
4.3.4. Please help me
Abdullah Teke
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Telephone : +90 555 337 21 89
Messenger
: [PHP] problem sending variables with forms
I have a problem that i cant send variable over a form. Because of that
when i watn to echo the variable next page an error occured...i use redhat
9.0, apache 2 and php 4.3.4. Please help me
Abdullah Teke
To: [EMAIL PROTECTED]
Subject: [PHP] Problem setting variables.
I'm creating a script that filters the table of results from a database
based on the configuration set by the user (config stored in database as
well).
For example a table has 30 columns. However the user need only see 5.
Every user
: Monday, July 28, 2003 4:24 AM
To: 'Jason Martyn'; [EMAIL PROTECTED]
Subject: RE: [PHP] Problem setting variables.
//Find User Configuration
$sql = mysql_query(SELECT field_name FROM config WHERE show_field=1)
OR die(Could not query database: .mysql_error().);
while($result = mysql_fetch_array($sql
I'm creating a script that filters the table of results from a database based on the
configuration set by the user (config stored in database as well).
For example a table has 30 columns. However the user need only see 5. Every user is
different so a user configuration is stored in the
I have this page where I am printing some items that are defined by size
and color which all the info is pulled from a database.
in the first item loop
PRINT ("tdinput type=\"text\" name=\"$Color$Temp[$f]\" size=\"3\"/td\n");
translated looks like this.
tdinput type="text" name=\"WhiteS"
Ian, I think what you want is a variable variable - have a look at
http://www.php.net/manual/en/html/language.variables.variable.html
I think you might want something like this:
${$Color$Temp[$f]}
HTH.
--
Hardy Merrill
Mission Critical Linux, Inc.
http://www.missioncriticallinux.com
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