$b=array($surname,$init), // does it work
like
it does work like that, but you're creating an array of one item which is a
string holding to values comma seperated.
you can do this too:
$b=array($surname,$init), // does it work like
w/o the
Can't help too much without more code, but the diagnostics I'd use would be
foreach() and count() to find out what is there rather than seeing if what I
expect to be there actually is.
Tim Ward
--
From: Scott Mebberson [SMTP:[EMAIL PROTECTED]]
Sent: 24 August
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