[PHP] Re: Can someone tell me why this is not working?

2009-06-18 Thread Shawn McKenzie 
Gary wrote:
 The center echo does not show.  It will show if I replace $newmort with 
 anything else.  I have copied the first if statement,pasted it in the 
 second position, and it works fine.  Once I change the var to $newmort, it 
 will not show. The third echo shows fine, it is only if I use newmort.  I 
 have renamed the var from mort1, because I was getting the same thing.
 
 tr
   tdPurchase Price: /td
   td input name=purchprice type=text/td
   /tr
 tr
   tdMortgage Amount: /td
   td input name=newmort type=text/td
   /tr
 tr
   tdHow long seller has owned property: /td
   td input name=howlong type=text size=4/td
   /tr
 
 
 $newmort=STRIPSLASHES($_POST['newmort']);
 $purchprice=STRIPSLASHES($_POST['purchprice']);
 $howlong=STRIPSLASHES($_POST['howlong']);
 
 if ($purchprice)  {
 echo Purchase Price:$ $purchpricebr /;
 }
 if ($newmort)  {
 echo Mortgage Amount:$ $newmortbr /;
 }
 if ($howlong) {
 echo How Long has seller owned property: $howlongbr /br /;
 }
 
 Thanks
 
 Gary 
 
 

if ($purchprice)  {
echo Purchase Price:\$ $purchpricebr /;
}
if ($newmort)  {
echo Mortgage Amount:\$ $newmortbr /;
}
if ($howlong) {
echo How Long has seller owned property: $howlongbr /br /;
}

-- 
Thanks!
-Shawn
http://www.spidean.com

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[PHP] Re: Can someone tell me why this is not working?

2009-06-18 Thread Gary 
Nope, I added slashes to all of the $, still no go.

Thank you for your help.

Gary


Shawn McKenzie nos...@mckenzies.net wrote in message 
news:53.c2.08167.5206a...@pb1.pair.com...
 Gary wrote:
 The center echo does not show.  It will show if I replace $newmort with
 anything else.  I have copied the first if statement,pasted it in the
 second position, and it works fine.  Once I change the var to $newmort, 
 it
 will not show. The third echo shows fine, it is only if I use newmort.  I
 have renamed the var from mort1, because I was getting the same thing.

 tr
   tdPurchase Price: /td
   td input name=purchprice type=text/td
   /tr
 tr
   tdMortgage Amount: /td
   td input name=newmort type=text/td
   /tr
 tr
   tdHow long seller has owned property: /td
   td input name=howlong type=text size=4/td
   /tr


 $newmort=STRIPSLASHES($_POST['newmort']);
 $purchprice=STRIPSLASHES($_POST['purchprice']);
 $howlong=STRIPSLASHES($_POST['howlong']);

 if ($purchprice)  {
 echo Purchase Price:$ $purchpricebr /;
 }
 if ($newmort)  {
 echo Mortgage Amount:$ $newmortbr /;
 }
 if ($howlong) {
 echo How Long has seller owned property: $howlongbr /br /;
 }

 Thanks

 Gary



 if ($purchprice)  {
 echo Purchase Price:\$ $purchpricebr /;
 }
 if ($newmort)  {
 echo Mortgage Amount:\$ $newmortbr /;
 }
 if ($howlong) {
 echo How Long has seller owned property: $howlongbr /br /;
 }

 -- 
 Thanks!
 -Shawn
 http://www.spidean.com 



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Re: [PHP] Re: Can someone tell me why this is not working?

2009-06-18 Thread Bastien Koert 
On Thu, Jun 18, 2009 at 11:44 AM, Garygwp...@ptd.net wrote:
 Nope, I added slashes to all of the $, still no go.

 Thank you for your help.

 Gary


 Shawn McKenzie nos...@mckenzies.net wrote in message
 news:53.c2.08167.5206a...@pb1.pair.com...
 Gary wrote:
 The center echo does not show.  It will show if I replace $newmort with
 anything else.  I have copied the first if statement,pasted it in the
 second position, and it works fine.  Once I change the var to $newmort,
 it
 will not show. The third echo shows fine, it is only if I use newmort.  I
 have renamed the var from mort1, because I was getting the same thing.

 tr
   tdPurchase Price: /td
   td input name=purchprice type=text/td
   /tr
     tr
   tdMortgage Amount: /td
   td input name=newmort type=text/td
   /tr
     tr
   tdHow long seller has owned property: /td
   td input name=howlong type=text size=4/td
   /tr


 $newmort=STRIPSLASHES($_POST['newmort']);
 $purchprice=STRIPSLASHES($_POST['purchprice']);
 $howlong=STRIPSLASHES($_POST['howlong']);

 if ($purchprice)  {
 echo Purchase Price:$ $purchpricebr /;
 }
 if ($newmort)  {
 echo Mortgage Amount:$ $newmortbr /;
 }
 if ($howlong) {
 echo How Long has seller owned property: $howlongbr /br /;
 }

 Thanks

 Gary



 if ($purchprice)  {
 echo Purchase Price:\$ $purchpricebr /;
 }
 if ($newmort)  {
 echo Mortgage Amount:\$ $newmortbr /;
 }
 if ($howlong) {
 echo How Long has seller owned property: $howlongbr /br /;
 }

 --
 Thanks!
 -Shawn
 http://www.spidean.com



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try wrapping the data in htmlentites(). Maybe there is a funky control
characters in there or a null value

$newmort=htmlentities(STRIPSLASHES($_POST['newmort']));

-- 

Bastien

Cat, the other other white meat

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[PHP] Re: Can someone tell me why this is not working?

2009-06-18 Thread Gary 
Everything is exaclty the same, but this one will not work.  I have retyped 
them, copied from those working, changed the name, changed the input 
name...If I change the var to $zip, it works.

Any other suggestions?

Thanks again.
Gary gwp...@ptd.net wrote in message 
news:89.71.08167.d8d5a...@pb1.pair.com...
 The center echo does not show.  It will show if I replace $newmort with 
 anything else.  I have copied the first if statement,pasted it in the 
 second position, and it works fine.  Once I change the var to $newmort, it 
 will not show. The third echo shows fine, it is only if I use newmort.  I 
 have renamed the var from mort1, because I was getting the same thing.

 tr
  tdPurchase Price: /td
  td input name=purchprice type=text/td
  /tr
tr
  tdMortgage Amount: /td
  td input name=newmort type=text/td
  /tr
tr
  tdHow long seller has owned property: /td
  td input name=howlong type=text size=4/td
  /tr


 $newmort=STRIPSLASHES($_POST['newmort']);
 $purchprice=STRIPSLASHES($_POST['purchprice']);
 $howlong=STRIPSLASHES($_POST['howlong']);

 if ($purchprice)  {
 echo Purchase Price:$ $purchpricebr /;
 }
 if ($newmort)  {
 echo Mortgage Amount:$ $newmortbr /;
 }
 if ($howlong) {
 echo How Long has seller owned property: $howlongbr /br /;
 }

 Thanks

 Gary
 



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Re: [PHP] Re: Can someone tell me why this is not working?

2009-06-18 Thread Martin Scotta 
if ($newmort)  {
echo Mortgage Amount:$ $newmortbr /;
}

check $newmort value

var_dump( $newmort );
if ($newmort)  {
echo Mortgage Amount:$ $newmortbr /;
}

you if fails is $newmort is there but empty


On Thu, Jun 18, 2009 at 1:11 PM, Gary gwp...@ptd.net wrote:

 Everything is exaclty the same, but this one will not work.  I have retyped
 them, copied from those working, changed the name, changed the input
 name...If I change the var to $zip, it works.

 Any other suggestions?

 Thanks again.
 Gary gwp...@ptd.net wrote in message
 news:89.71.08167.d8d5a...@pb1.pair.com...
  The center echo does not show.  It will show if I replace $newmort with
  anything else.  I have copied the first if statement,pasted it in the
  second position, and it works fine.  Once I change the var to $newmort,
 it
  will not show. The third echo shows fine, it is only if I use newmort.  I
  have renamed the var from mort1, because I was getting the same thing.
 
  tr
   tdPurchase Price: /td
   td input name=purchprice type=text/td
   /tr
 tr
   tdMortgage Amount: /td
   td input name=newmort type=text/td
   /tr
 tr
   tdHow long seller has owned property: /td
   td input name=howlong type=text size=4/td
   /tr
 
 
  $newmort=STRIPSLASHES($_POST['newmort']);
  $purchprice=STRIPSLASHES($_POST['purchprice']);
  $howlong=STRIPSLASHES($_POST['howlong']);
 
  if ($purchprice)  {
  echo Purchase Price:$ $purchpricebr /;
  }
  if ($newmort)  {
  echo Mortgage Amount:$ $newmortbr /;
  }
  if ($howlong) {
  echo How Long has seller owned property: $howlongbr /br /;
  }
 
  Thanks
 
  Gary
 



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-- 
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Re: [PHP] Re: Can someone tell me why this is not working?

2009-06-18 Thread Kirk . Johnson 
 [PHP] Re: Can someone tell me why this is not working?
 
  The center echo does not show.  It will show if I replace $newmort 
with 
  anything else.  I have copied the first if statement,pasted it in 
the 
  second position, and it works fine.  Once I change the var to 
$newmort, it 
  will not show. The third echo shows fine, it is only if I use newmort. 
 I 
  have renamed the var from mort1, because I was getting the same thing.
 
  $newmort=STRIPSLASHES($_POST['newmort']);
  $purchprice=STRIPSLASHES($_POST['purchprice']);
  $howlong=STRIPSLASHES($_POST['howlong']);
 
  if ($purchprice)  {
  echo Purchase Price:$ $purchpricebr /;
  }
  if ($newmort)  {
  echo Mortgage Amount:$ $newmortbr /;
  }
  if ($howlong) {
  echo How Long has seller owned property: $howlongbr /br /;

Echo out the value of $newmort just above the if statement. If it is 
zero or blank, the if will evaluate to false.

Is there a second form field named newmort lower on the page? If so, it 
will be the value of $_POST['newmort'] that you receive in the post.

Kirk

Re: [PHP] Re: Can someone tell me why this is not working?

2009-06-18 Thread Gabriel Sosa 

on this line


echo Mortgage Amount:$ $newmortbr /;


the echo is trying to evaluate the string...

in your case you should escape the $ sign... like this \$


echo Mortgage Amount:\$ $newmortbr /;




regards

On Jun 18, 2009, at 1:15 PM, Martin Scotta wrote:


if ($newmort)  {
echo Mortgage Amount:$ $newmortbr /;
}

check $newmort value

var_dump( $newmort );
if ($newmort)  {
echo Mortgage Amount:$ $newmortbr /;
}

you if fails is $newmort is there but empty


On Thu, Jun 18, 2009 at 1:11 PM, Gary gwp...@ptd.net wrote:

Everything is exaclty the same, but this one will not work.  I have  
retyped

them, copied from those working, changed the name, changed the input
name...If I change the var to $zip, it works.

Any other suggestions?

Thanks again.
Gary gwp...@ptd.net wrote in message
news:89.71.08167.d8d5a...@pb1.pair.com...
The center echo does not show.  It will show if I replace $newmort  
with
anything else.  I have copied the first if statement,pasted it  
in the
second position, and it works fine.  Once I change the var to  
$newmort,

it
will not show. The third echo shows fine, it is only if I use  
newmort.  I
have renamed the var from mort1, because I was getting the same  
thing.


tr
tdPurchase Price: /td
td input name=purchprice type=text/td
/tr
  tr
tdMortgage Amount: /td
td input name=newmort type=text/td
/tr
  tr
tdHow long seller has owned property: /td
td input name=howlong type=text size=4/td
/tr


$newmort=STRIPSLASHES($_POST['newmort']);
$purchprice=STRIPSLASHES($_POST['purchprice']);
$howlong=STRIPSLASHES($_POST['howlong']);

if ($purchprice)  {
echo Purchase Price:$ $purchpricebr /;
}
if ($newmort)  {
echo Mortgage Amount:$ $newmortbr /;
}
if ($howlong) {
echo How Long has seller owned property: $howlongbr /br /;
}

Thanks

Gary





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Re: [PHP] Re: Can someone tell me why this is not working?

2009-06-18 Thread Gary 
Thanks...Now I get NULL

I have another set of these if($) echo, and the all work, it is just this 
one that refuses to give it up.


Martin Scotta martinsco...@gmail.com wrote in message 
news:6445d94e0906180915o392d1500hd906b23dbf5c4...@mail.gmail.com...
 if ($newmort)  {
 echo Mortgage Amount:$ $newmortbr /;
 }

 check $newmort value

 var_dump( $newmort );
 if ($newmort)  {
 echo Mortgage Amount:$ $newmortbr /;
 }

 you if fails is $newmort is there but empty


 On Thu, Jun 18, 2009 at 1:11 PM, Gary gwp...@ptd.net wrote:

 Everything is exaclty the same, but this one will not work.  I have 
 retyped
 them, copied from those working, changed the name, changed the input
 name...If I change the var to $zip, it works.

 Any other suggestions?

 Thanks again.
 Gary gwp...@ptd.net wrote in message
 news:89.71.08167.d8d5a...@pb1.pair.com...
  The center echo does not show.  It will show if I replace $newmort with
  anything else.  I have copied the first if statement,pasted it in the
  second position, and it works fine.  Once I change the var to $newmort,
 it
  will not show. The third echo shows fine, it is only if I use newmort. 
  I
  have renamed the var from mort1, because I was getting the same thing.
 
  tr
   tdPurchase Price: /td
   td input name=purchprice type=text/td
   /tr
 tr
   tdMortgage Amount: /td
   td input name=newmort type=text/td
   /tr
 tr
   tdHow long seller has owned property: /td
   td input name=howlong type=text size=4/td
   /tr
 
 
  $newmort=STRIPSLASHES($_POST['newmort']);
  $purchprice=STRIPSLASHES($_POST['purchprice']);
  $howlong=STRIPSLASHES($_POST['howlong']);
 
  if ($purchprice)  {
  echo Purchase Price:$ $purchpricebr /;
  }
  if ($newmort)  {
  echo Mortgage Amount:$ $newmortbr /;
  }
  if ($howlong) {
  echo How Long has seller owned property: $howlongbr /br /;
  }
 
  Thanks
 
  Gary
 



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 -- 
 Martin Scotta
 



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Re: [PHP] Re: Can someone tell me why this is not working?

2009-06-18 Thread Daniel Brown 
On Thu, Jun 18, 2009 at 12:22, Garygwp...@ptd.net wrote:
 Thanks...Now I get NULL

 I have another set of these if($) echo, and the all work, it is just this
 one that refuses to give it up.

Gary, if you can, send the link to the live development copy on
which you're working.  Even if it's just a temporary copy of the file
for now, for debugging purposes.

-- 
/Daniel P. Brown
daniel.br...@parasane.net || danbr...@php.net
http://www.parasane.net/ || http://www.pilotpig.net/
50% Off All Shared Hosting Plans at PilotPig: Use Coupon DOW1

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Re: [PHP] Re: Can someone tell me why this is not working?

2009-06-18 Thread Gary 
Thanks, but that is not it, have already slashed the $, but the others 
without the \ still work.


Gabriel Sosa sosagabr...@gmail.com wrote in message 
news:c4316a8f-3ee4-43d0-9b30-c4b447428...@gmail.com...
 on this line

 echo Mortgage Amount:$ $newmortbr /;

 the echo is trying to evaluate the string...

 in your case you should escape the $ sign... like this \$

 echo Mortgage Amount:\$ $newmortbr /;



 regards

 On Jun 18, 2009, at 1:15 PM, Martin Scotta wrote:

 if ($newmort)  {
 echo Mortgage Amount:$ $newmortbr /;
 }

 check $newmort value

 var_dump( $newmort );
 if ($newmort)  {
 echo Mortgage Amount:$ $newmortbr /;
 }

 you if fails is $newmort is there but empty


 On Thu, Jun 18, 2009 at 1:11 PM, Gary gwp...@ptd.net wrote:

 Everything is exaclty the same, but this one will not work.  I have 
 retyped
 them, copied from those working, changed the name, changed the input
 name...If I change the var to $zip, it works.

 Any other suggestions?

 Thanks again.
 Gary gwp...@ptd.net wrote in message
 news:89.71.08167.d8d5a...@pb1.pair.com...
 The center echo does not show.  It will show if I replace $newmort 
 with
 anything else.  I have copied the first if statement,pasted it  in 
 the
 second position, and it works fine.  Once I change the var to 
 $newmort,
 it
 will not show. The third echo shows fine, it is only if I use  newmort. 
 I
 have renamed the var from mort1, because I was getting the same  thing.

 tr
 tdPurchase Price: /td
 td input name=purchprice type=text/td
 /tr
   tr
 tdMortgage Amount: /td
 td input name=newmort type=text/td
 /tr
   tr
 tdHow long seller has owned property: /td
 td input name=howlong type=text size=4/td
 /tr


 $newmort=STRIPSLASHES($_POST['newmort']);
 $purchprice=STRIPSLASHES($_POST['purchprice']);
 $howlong=STRIPSLASHES($_POST['howlong']);

 if ($purchprice)  {
 echo Purchase Price:$ $purchpricebr /;
 }
 if ($newmort)  {
 echo Mortgage Amount:$ $newmortbr /;
 }
 if ($howlong) {
 echo How Long has seller owned property: $howlongbr /br /;
 }

 Thanks

 Gary




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 -- 
 Martin Scotta
 



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Re: [PHP] Re: Can someone tell me why this is not working?

2009-06-18 Thread Gary 
Ok, I dont really know how it got working, but it is.  I did try the test, 
and after that it worked, however I had tried one before

But thank you all for your time and help.

Gary


kirk.john...@zootweb.com wrote in message 
news:of24965909.4acbeaf3-on872575d9.00598a62-872575d9.0059e...@zootweb.com...
 [PHP] Re: Can someone tell me why this is not working?

  The center echo does not show.  It will show if I replace $newmort
 with
  anything else.  I have copied the first if statement,pasted it in
 the
  second position, and it works fine.  Once I change the var to
 $newmort, it
  will not show. The third echo shows fine, it is only if I use newmort.
 I
  have renamed the var from mort1, because I was getting the same thing.
 
  $newmort=STRIPSLASHES($_POST['newmort']);
  $purchprice=STRIPSLASHES($_POST['purchprice']);
  $howlong=STRIPSLASHES($_POST['howlong']);
 
  if ($purchprice)  {
  echo Purchase Price:$ $purchpricebr /;
  }
  if ($newmort)  {
  echo Mortgage Amount:$ $newmortbr /;
  }
  if ($howlong) {
  echo How Long has seller owned property: $howlongbr /br /;

 Echo out the value of $newmort just above the if statement. If it is
 zero or blank, the if will evaluate to false.

 Is there a second form field named newmort lower on the page? If so, it
 will be the value of $_POST['newmort'] that you receive in the post.

 Kirk 



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Re: [PHP] Re: Can someone tell me why this is not working?

2009-06-18 Thread Gary 
I was about to do something really stupid.  I had gotten it to work (even a 
blind squirell gets a nut every now and again),  and had copied the code to 
send to you to look at.and then realized it was working so you would be 
chasing ghosts.

Thank you for your help.

Gary


Daniel Brown danbr...@php.net wrote in message 
news:ab5568160906180925q18afdc95ua9d48f1e8f6ae...@mail.gmail.com...
 On Thu, Jun 18, 2009 at 12:22, Garygwp...@ptd.net wrote:
 Thanks...Now I get NULL

 I have another set of these if($) echo, and the all work, it is just this
 one that refuses to give it up.

Gary, if you can, send the link to the live development copy on
 which you're working.  Even if it's just a temporary copy of the file
 for now, for debugging purposes.

 -- 
 /Daniel P. Brown
 daniel.br...@parasane.net || danbr...@php.net
 http://www.parasane.net/ || http://www.pilotpig.net/
 50% Off All Shared Hosting Plans at PilotPig: Use Coupon DOW1 



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