[PHP] Re: Eval var from query

[Shawn McKenzie]

eval($data)

returns Parse error: parse error, unexpected T_STRING in
C:\apps\apache2\htdocs\test\query.php(23) : eval()'d code on line 1

Thanks!
Shawn

Shawn McKenzie [EMAIL PROTECTED] wrote in message
news:[EMAIL PROTECTED]
 How can I evaluate a var that is from a text field of a database?
Example:

 MySQL field `name` = hi my name is $name

 In my script I have:

 $name = Shawn;

 After fetching a query result as an associative array I have the contents
of
 the `name` field in $data

 If I echo $data I get:  hi my name is $name

 I would like to get:  hi my name is Shawn

 TIA,
 Shawn





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Re: [PHP] Re: Eval var from query

[Kevin Stone]

The string you send to eval() must be valid PHP code.  So try this..

eval( 'echo '.$data.';');

- Kevin


- Original Message -
From: Shawn McKenzie [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Monday, July 14, 2003 1:15 PM
Subject: [PHP] Re: Eval var from query


 eval($data)

 returns Parse error: parse error, unexpected T_STRING in
 C:\apps\apache2\htdocs\test\query.php(23) : eval()'d code on line 1

 Thanks!
 Shawn

 Shawn McKenzie [EMAIL PROTECTED] wrote in message
 news:[EMAIL PROTECTED]
  How can I evaluate a var that is from a text field of a database?
 Example:
 
  MySQL field `name` = hi my name is $name
 
  In my script I have:
 
  $name = Shawn;
 
  After fetching a query result as an associative array I have the
contents
 of
  the `name` field in $data
 
  If I echo $data I get:  hi my name is $name
 
  I would like to get:  hi my name is Shawn
 
  TIA,
  Shawn
 
 



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 To unsubscribe, visit: http://www.php.net/unsub.php





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Re: [PHP] Re: Eval var from query

[Kevin Stone]

I realized that may not make any sense.  Following up the eample relates to
your original query like this..

 MySQL field `name` = hi my name is $name
 In my script I have:
 $name = Shawn;

$data = 'hi my name is $name';
$code = 'echo '.$data.';';
$name = 'Shawn';
eval($code); // prints hi may name is Shawn.

Hope that makes it more clear.

- Kevin



- Original Message -
From: Kevin Stone [EMAIL PROTECTED]
To: PHP-GENERAL [EMAIL PROTECTED]
Sent: Monday, July 14, 2003 1:23 PM
Subject: Re: [PHP] Re: Eval var from query


 The string you send to eval() must be valid PHP code.  So try this..

 eval( 'echo '.$data.';');

 - Kevin


 - Original Message -
 From: Shawn McKenzie [EMAIL PROTECTED]
 To: [EMAIL PROTECTED]
 Sent: Monday, July 14, 2003 1:15 PM
 Subject: [PHP] Re: Eval var from query


  eval($data)
 
  returns Parse error: parse error, unexpected T_STRING in
  C:\apps\apache2\htdocs\test\query.php(23) : eval()'d code on line 1
 
  Thanks!
  Shawn
 
  Shawn McKenzie [EMAIL PROTECTED] wrote in message
  news:[EMAIL PROTECTED]
   How can I evaluate a var that is from a text field of a database?
  Example:
  
   MySQL field `name` = hi my name is $name
  
   In my script I have:
  
   $name = Shawn;
  
   After fetching a query result as an associative array I have the
 contents
  of
   the `name` field in $data
  
   If I echo $data I get:  hi my name is $name
  
   I would like to get:  hi my name is Shawn
  
   TIA,
   Shawn
  
  
 
 
 
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  To unsubscribe, visit: http://www.php.net/unsub.php
 
 



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Re: [PHP] Re: Eval var from query

[Shawn McKenzie]

Thanks Kevin!  That works great.  It outputs:  hi my name is Shawn

Now if I want to assign $data to another var, let's say $newdata and have it
eval the $name var inside of that.  How would that work?

Meaning I want to $newdata = hi my name is Shawn

Thanks!
Shawn

Kevin Stone [EMAIL PROTECTED] wrote in message
news:[EMAIL PROTECTED]
 The string you send to eval() must be valid PHP code.  So try this..

 eval( 'echo '.$data.';');

 - Kevin


 - Original Message -
 From: Shawn McKenzie [EMAIL PROTECTED]
 To: [EMAIL PROTECTED]
 Sent: Monday, July 14, 2003 1:15 PM
 Subject: [PHP] Re: Eval var from query


  eval($data)
 
  returns Parse error: parse error, unexpected T_STRING in
  C:\apps\apache2\htdocs\test\query.php(23) : eval()'d code on line 1
 
  Thanks!
  Shawn
 
  Shawn McKenzie [EMAIL PROTECTED] wrote in message
  news:[EMAIL PROTECTED]
   How can I evaluate a var that is from a text field of a database?
  Example:
  
   MySQL field `name` = hi my name is $name
  
   In my script I have:
  
   $name = Shawn;
  
   After fetching a query result as an associative array I have the
 contents
  of
   the `name` field in $data
  
   If I echo $data I get:  hi my name is $name
  
   I would like to get:  hi my name is Shawn
  
   TIA,
   Shawn
  
  
 
 
 
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  To unsubscribe, visit: http://www.php.net/unsub.php
 
 





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Re: [PHP] Re: Eval var from query

[Shawn McKenzie]

Got it!

eval( '$newdata = '.$data.';');

Thanks!
Shawn

Shawn McKenzie [EMAIL PROTECTED] wrote in message
news:[EMAIL PROTECTED]
 Thanks Kevin!  That works great.  It outputs:  hi my name is Shawn

 Now if I want to assign $data to another var, let's say $newdata and have
it
 eval the $name var inside of that.  How would that work?

 Meaning I want to $newdata = hi my name is Shawn

 Thanks!
 Shawn

 Kevin Stone [EMAIL PROTECTED] wrote in message
 news:[EMAIL PROTECTED]
  The string you send to eval() must be valid PHP code.  So try this..
 
  eval( 'echo '.$data.';');
 
  - Kevin
 
 
  - Original Message -
  From: Shawn McKenzie [EMAIL PROTECTED]
  To: [EMAIL PROTECTED]
  Sent: Monday, July 14, 2003 1:15 PM
  Subject: [PHP] Re: Eval var from query
 
 
   eval($data)
  
   returns Parse error: parse error, unexpected T_STRING in
   C:\apps\apache2\htdocs\test\query.php(23) : eval()'d code on line 1
  
   Thanks!
   Shawn
  
   Shawn McKenzie [EMAIL PROTECTED] wrote in message
   news:[EMAIL PROTECTED]
How can I evaluate a var that is from a text field of a database?
   Example:
   
MySQL field `name` = hi my name is $name
   
In my script I have:
   
$name = Shawn;
   
After fetching a query result as an associative array I have the
  contents
   of
the `name` field in $data
   
If I echo $data I get:  hi my name is $name
   
I would like to get:  hi my name is Shawn
   
TIA,
Shawn
   
   
  
  
  
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   To unsubscribe, visit: http://www.php.net/unsub.php
  
  
 
 





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Re: [PHP] Re: Eval var from query

[Kevin Stone]

- Original Message -
From: Shawn McKenzie [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Monday, July 14, 2003 1:51 PM
Subject: Re: [PHP] Re: Eval var from query


 Thanks Kevin!  That works great.  It outputs:  hi my name is Shawn

 Now if I want to assign $data to another var, let's say $newdata and have
it
 eval the $name var inside of that.  How would that work?

 Meaning I want to $newdata = hi my name is Shawn

 Thanks!
 Shawn

Umm.. well.. '$name' is a litteral inside the string until it is evaluated.
It doesn't matter if you make a copy of the variable, '$name' is still going
to be a litteral value.  So you'll have to eval() it exactly the same way
every time.  But maybe I can offer an alternative...

You look at this string and see a code evaluation problem.  I look at this
string and see a find and replace problem.  Consider useing str_replace()
to search for and replace '$name' as a template marker rather than a
variable to be evaluated..

$data = 'hi my name is $name';
$name = 'Shawn';
echo str_replace('$name', $name, $data);

This accomplishes exactly the same thing and it's a perfectly valid form.
Plus it's going to work on any string becuase you don't have to turn them
into PHP code first.

- Kevin



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