Hi Justin,
For future reference, your choice of subject is poor - be more descriptive,
your subject could apply to 99% of the questions asked on this list.
I have no idea what you've created in DW MX 2004, nor have you given us any
information about it.
If you have an authorisation level stored
I don't understand the question.
One should always check the existence of something before attempting to use
it.
If (isset($var) gettype($var) == boolean) is one way of type checking.
Christian Jul Jensen [EMAIL PROTECTED] wrote in message
news:[EMAIL PROTECTED]
Hi
In PHP5 the behaviour
Hi,
this is a plain design fault on your side:
?php
$a = 'this is not an array';
if( is_array( $a['foo'] ) )
print '1';
[...]
?
allright, just set $a to be a string, thats allright, now
you check wether an string-offset ( foo ) is an array or
not which causes an FATAL
Hi
Thanks for taking time to look into this.
[EMAIL PROTECTED] (Red Wingate) writes:
this is a plain design fault on your side:
I'm sorry, but I don't agree. It is standard in PHP4, and one of the
advantages of having a type loose programming language.
Now this makes sense as you first
* Thus wrote Christian Jul Jensen ([EMAIL PROTECTED]):
Hi
Thanks for taking time to look into this.
[EMAIL PROTECTED] (Red Wingate) writes:
this is a plain design fault on your side:
I'm sorry, but I don't agree. It is standard in PHP4, and one of the
advantages of having a
Firstly I'd rewrite your other script to store the data in an array.
The benefits of doing so are simply demonstrated:
?php
foreach ($products as $product)
dosomethingto($product);
?
However, if you are unable to rewrite your script:
The correct syntax is:
?php
${'product' . $i}
?
Ryan A
Hey,
OK, got it, thanks!
-Ryan
On 1/4/2004 1:00:04 AM, Aidan Lister ([EMAIL PROTECTED]) wrote:
Firstly
I'd rewrite your other script to store the data in an array.
The benefits of doing so are simply demonstrated:
?php
foreach ($products as $product)
dosomethingto($product);
?
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