I've solved it!
You have to put the field name of the DBF, not the array position. I
don't know exactly why, but it worked for me.
So the code is:
for ($x = 1; $x < $quant; $x++)
{
$drec = dbase_get_record_with_names($dbf,$x);
echo "$drec[NAME]";
}
Thanks a lot
When I try with
for ($x = 1; $x < $quant; $x++)
{
$drec = dbase_get_record_with_names($dbf,$x);
echo "$drec[0].",".$drec[1]"; <- and so on
}
It only shows the dots. It doesn't show any of the fields.
I know that dbf is a very prehistorical solution, but the clie
"Er GalvãO Abbott" <[EMAIL PROTECTED]> wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
> foreach ($drec as $nome)
> {
> echo "$nome";
> }
> But I'm trying (unsucessfully) to show only one or two fields of each
> records..
Instead of foreach(), try something like
echo $drec[0]
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