[PHP] Re: end of array

[Raj Shekhar]

M. Sokolewicz [EMAIL PROTECTED] writes:

 Raj Shekhar wrote:
  M. Sokolewicz [EMAIL PROTECTED] writes:
 
 Raj Shekhar wrote:
 
 $n_elts = count($myarray);
 for ($i=0; $i $n_elts ; $i++)
 {
 if ($i = $n_elts -1)
^^^
  Use of == required to make it work
 {
 echo On last element;
 break;
 }
 else
 {
 echo Somwhere in the middle;
 }
 }
 
 that's an eternal loop in case you hadn't noticed (*rolls eyes*)
  Oops :( not eternal loop though, only one loop
 why one?
 for($i=0; $i$n;$i++) {
   $i = ($n-1);
 }

My statement was, 

if ($i = $n_elts -1)

{
echo On last element;
break;
}

i.e.

- assign ($i = $n_elts -1) and check the return value of the
  assignment. 

- If the assignment succeeds (which should, unless you are running
  short of free memory) THEN

- echo 
- BREAK out of loop 

Since this conditions are met the first time the loop runs, the loop
will run only once. I know I am correct, since I ran the code this
time :P

-- 
Raj Shekhar
System Administrator, programmer and  slacker
home : http://rajshekhar.net
blog : http://rajshekhar.net/blog/

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[PHP] Re: end of array

[Raj Shekhar]

Jeffery Fernandez [EMAIL PROTECTED] writes:

 Hi all,
 
 I have a foreach loop on an array and within that loop I need to find
 if the array has reached the last pointer. I have tried
 
 if (next($row))
 {
 
 }
 
 but that advances the pointer. Any tips on finding out if the array
 pointer has reached the last element ?

$n_elts = count($myarray);
for ($i=0; $i $n_elts ; $i++)
{
if ($i = $n_elts -1)
{
echo On last element;
break;
}
else
{
echo Somwhere in the middle;
}
}

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[PHP] Re: end of array

[M. Sokolewicz]

Raj Shekhar wrote:
Jeffery Fernandez [EMAIL PROTECTED] writes:

Hi all,
I have a foreach loop on an array and within that loop I need to find
if the array has reached the last pointer. I have tried
if (next($row))
{
}
but that advances the pointer. Any tips on finding out if the array
pointer has reached the last element ?

$n_elts = count($myarray);
for ($i=0; $i $n_elts ; $i++)
{
if ($i = $n_elts -1)
{
echo On last element;
break;
}
else
{
echo Somwhere in the middle;
}
}
that's an eternal loop in case you hadn't noticed (*rolls eyes*)
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[PHP] Re: end of array

[Raj Shekhar]

M. Sokolewicz [EMAIL PROTECTED] writes:

 Raj Shekhar wrote:

  $n_elts = count($myarray);
  for ($i=0; $i $n_elts ; $i++)
  {
  if ($i = $n_elts -1)
  ^^^
Use of == required to make it work 

  {
  echo On last element;
  break;
  }
  else
  {
  echo Somwhere in the middle;
  }
  }
 that's an eternal loop in case you hadn't noticed (*rolls eyes*)

Oops :( not eternal loop though, only one loop 

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[PHP] Re: end of array

[M. Sokolewicz]

Raj Shekhar wrote:
M. Sokolewicz [EMAIL PROTECTED] writes:

Raj Shekhar wrote:

$n_elts = count($myarray);
for ($i=0; $i $n_elts ; $i++)
{
   if ($i = $n_elts -1)
  ^^^
Use of == required to make it work 


   {
   echo On last element;
   break;
   }
   else
   {
   echo Somwhere in the middle;
   }
}
that's an eternal loop in case you hadn't noticed (*rolls eyes*)

Oops :( not eternal loop though, only one loop 
why one?
for($i=0; $i$n;$i++) {
$i = ($n-1);
}
to me that means the following:
1. check if $i$n; true! ($i=0; $n1)
2. $i=$n-1, this means that $i$n (less by 1 in fact)
3. check if $i$n; true! ($i=$n-1; $n$i by definition)
4. $i is reset to $n-1
5-eternity. conditions are met, and var is reset
or am I missing something here? :)
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