[PHP] Re: eval help

2003-03-03 Thread neko 
note that the following php:

?php
/*
  eval testing
  SM 3/3/2003 1:28PM
*/

$name = Scott;
$arr[] = Dude;
$arr2[name] = Broness!;

echo($arr2['name']); // test

$str  = brHello, $name;
$str2 = brHello, $arr[0];
$str3 = brHello, $arr2['name'];

eval (\$evaldString = \$str\;);
echo $evaldString;

eval (\$evaldString = \$str2\;);
echo $evaldString;

eval (\$evaldString = \$str3\;);
echo $evaldString;

?

produces:

Broness!brHello, ScottbrHello, DudebrHello,

--

note that the last cannot be seen - I'm sure I'm almost there, but I have to
be able to reference an associative array.

Scott



-- 
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php

Re: [PHP] Re: eval help

2003-03-03 Thread Dan Hardiker 
Hi,

 $arr2[name] = Broness!;
..
 $str3 = brHello, $arr2['name'];
..
 eval (\$evaldString = \$str3\;);
 echo $evaldString;

Your almost there... just remember one very simple rule - if in doubt,
break out. Meaning, if you're having variable resolution issues, then just
break out of the string. Apply the following change to have happy dreams:

From:
 $str3 = brHello, $arr2['name'];

To:
 $str3 = brHello, .$arr2['name'];


-- 
Dan Hardiker [EMAIL PROTECTED]
ADAM Software  Systems Engineer
First Creative



-- 
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php

Re: [PHP] Re: eval help

2003-03-03 Thread neko 
Thanks Dan - I just worked this out before reading your solution! :)

$str4 = brHello, .$arr2['name'];

cheers and thanks to all - lets see how that goes within my framework now :)

neko



-- 
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php

[PHP] Re: eval help

2003-03-03 Thread neko 
Actually, I just realised that what I want to accomplish is different from
my example - the main issue is with scope:

?php
/*
  eval testing 3
  SM 33/3/2003 2:32PM
*/

func1();

function func1()
{
  echo(brwe're in the pipe, 5-5-5.);

  $str  = brHello, \$name;
  $str2 = brHello, \$arr[0];
  $str3 = brHello, \$arr2['name'];

  echo doEvalWithVarsInScope($str);
  echo doEvalWithVarsInScope($str2);
  echo doEvalWithVarsInScope($str3);
}

function doEvalWithVarsInScope($str)
{
  echo(brtrying to eval for str=$str);

  $name = Scott;
  $arr[] = Dude;
  $arr2[name] = Broness!;

  eval (\$evaldString = \$str\;);
  return $evaldString;
}

?

--

will produce:

we're in the pipe, 5-5-5.
trying to eval for str=
Hello, $name
Hello, Scott
trying to eval for str=
Hello, $arr[0]
Hello, Dude
trying to eval for str=
Hello, $arr2['name']
Hello,

--

any (more) help is greatly appreciated.

cheers,
neko



-- 
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php

[PHP] Re: eval help

2003-03-03 Thread neko 
?php
/*
  eval testing 3
  SM 33/3/2003 2:32PM
*/

define(NAME_TAG, name);
func1();

function func1()
{
  echo(brwe're in the pipe, 5-5-5.);

  $str  = brHello, \$name;
  $str2 = brHello, \$arr[0];
  $str3 = brHello, \$arr2[.NAME_TAG.];

  echo doEvalWithVarsInScope($str);
  echo doEvalWithVarsInScope($str2);
  echo doEvalWithVarsInScope($str3);
}

function doEvalWithVarsInScope($str)
{
  echo(brtrying to eval for str=$str and NAME_TAG:.NAME_TAG);

  $name = Scott;
  $arr[] = Dude;
  $arr2[NAME_TAG] = Broness!;

  eval (\$evaldString = \$str\;);
  return $evaldString;
}

?

--

produces:


we're in the pipe, 5-5-5.
trying to eval for str=
Hello, $name and NAME_TAG:name
Hello, Scott
trying to eval for str=
Hello, $arr[0] and NAME_TAG:name
Hello, Dude
trying to eval for str=
Hello, $arr2[name] and NAME_TAG:name
Hello, Broness!

--

done, but it's uglier than I was hoping :(



-- 
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php

[PHP] Re: eval help

2003-03-03 Thread neko 
ok - my latest in the eval saga is this:

I want to be able to eval a function call anywhere in the string supplied,
and the function call is not in scope when the string is defined.

So

-- somewhere in my code I wanted something like this:

$string = brtesting nodename: \$node-getName()
pagename:\$nodePageTags[.TAG_PAGENAME.];

-- where the code is evaled eventually, there is a $node object defined, so
the function call should work. Of course, that currently does not work :)

cheers,
neko



-- 
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php