[PHP] Re: function args declared by-reference, with default value?

[Derick Rethans]

Nick Eby wrote:

true or false:

when declaring a function, a given argument can be declared to pass by
reference, or can be declared to have a default value, but never both.

i.e., you can only write one of:
function foo(&$param)
function foo($param = "bar")

but never the equivalent of:
function foo(&$param = "bar")

is there a way to declare an argument with both pass-by-reference and
default-value properties?

No, but this will be supported by Zend Engine 2, which will drive PHP 5 and higher.

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