Omar,
I would first take the select statement and try running it in mysql to make
sure it actually runs (substituting a valid value for the variable of
course). Then if it has problems you can see what error messages mysql
gives you.
Good Luck,
Jonathan Duncan
Omar Campos [EMAIL PROTECTED]
In article [EMAIL PROTECTED],
[EMAIL PROTECTED] says...
I have a file. I'll paste from line 32 to 34
?
.
$sql = select USUARIO from docente where USUARIO = '$usuario';
$result = mysql_query($sql, $link);
Replace the above line with (all on one line)
$result = mysql_query($sql,
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