Re: [PHP] Return an Array and immediately reference an index
Bojan Tesanovic wrote:
On Apr 12, 2008, at 12:33 AM, Daniel Kolbo wrote:
Hello,
I want to return an array from function and reference an index all in
one line. Is this possible?
In the code below I want I want $yo to be the array(5,6).
Here is what I've tried,
function returnarray() {
return array('lose' = array(5,6), 'win' = array(9,8));
}
$yo = returnarray()['lose'];
var_dump($yo);
This yields a parse error.
function returnarray() {
return array('lose' = array(5,6), 'win' = array(9,8));
}
$yo = {returnarray()}['lose'];
var_dump($yo);
This yields a parse error.
function returnarray() {
return array('lose' = array(5,6), 'win' = array(9,8));
}
$yo = ${returnarray()}['lose'];
var_dump($yo);
This gives notices as the result of returnarray() is being converted
to a string. $yo === NULL...not what i want.
function returnarray() {
return array('lose' = array(5,6), 'win' = array(9,8));
}
$yo = returnarray()-['lose'];
var_dump($yo);
This yields a parse error.
function returnarray() {
return array('lose' = array(5,6), 'win' = array(9,8));
}
$yo = ${returnarray()}-['lose'];
var_dump($yo);
This yields a parse error.
Thanks for your help in advance.
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This is not possible in PHP, though you can have a Array wrapper class
function returnarray() {
return new ArrayObject( array('lose' = array(5,6), 'win' =
array(9,8)) );
}
var_dump (returnarray()-offsetGet('lose'));
or even better make you own wrapper class with __set() and __get()
methods so you can have
var_dump (returnarray()-lose);
of course only in PHP5
Well, not quite so fast saying this is only possible in PHP5
You could do something like this.
?php
function returnHash() {
return (object) array('lose' = array(5,6), 'win' = array(9,8));
}
print_r(returnHash()-lose);
?
Basically, this converts your newly built array into an object, using
the stdClass object.
Then reference the index via an object variable name instead of an array
style access method.
Bojan Tesanovic
http://www.carster.us/
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Re: [PHP] Return an Array and immediately reference an index
On 12 Apr 2008, at 00:31, Daniel Kolbo wrote:
Philip Thompson wrote:
On Apr 11, 2008, at 5:33 PM, Daniel Kolbo wrote:
I want to return an array from function and reference an index all
in one line. Is this possible?
In the code below I want I want $yo to be the array(5,6).
Here is what I've tried,
function returnarray() {
return array('lose' = array(5,6), 'win' = array(9,8));
}
$yo = returnarray()['lose'];
var_dump($yo);
This yields a parse error.
function returnarray() {
return array('lose' = array(5,6), 'win' = array(9,8));
}
$yo = {returnarray()}['lose'];
var_dump($yo);
This yields a parse error.
function returnarray() {
return array('lose' = array(5,6), 'win' = array(9,8));
}
$yo = ${returnarray()}['lose'];
var_dump($yo);
This gives notices as the result of returnarray() is being
converted to a string. $yo === NULL...not what i want.
function returnarray() {
return array('lose' = array(5,6), 'win' = array(9,8));
}
$yo = returnarray()-['lose'];
var_dump($yo);
This yields a parse error.
function returnarray() {
return array('lose' = array(5,6), 'win' = array(9,8));
}
$yo = ${returnarray()}-['lose'];
var_dump($yo);
This yields a parse error.
The PHP parser does not support this, but you may see it in a future
version - it's a commonly requested feature.
There are various ways to code around this limitation as other posters
have stated but to me they all add far too much processing to make it
worth saving a line of code and a temporary variable.
-Stut
--
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Re: [PHP] Return an Array and immediately reference an index
Jim Lucas wrote:
Bojan Tesanovic wrote:
On Apr 12, 2008, at 12:33 AM, Daniel Kolbo wrote:
Hello,
I want to return an array from function and reference an index all in
one line. Is this possible?
In the code below I want I want $yo to be the array(5,6).
Here is what I've tried,
function returnarray() {
return array('lose' = array(5,6), 'win' = array(9,8));
}
$yo = returnarray()['lose'];
var_dump($yo);
This yields a parse error.
function returnarray() {
return array('lose' = array(5,6), 'win' = array(9,8));
}
$yo = {returnarray()}['lose'];
var_dump($yo);
This yields a parse error.
function returnarray() {
return array('lose' = array(5,6), 'win' = array(9,8));
}
$yo = ${returnarray()}['lose'];
var_dump($yo);
This gives notices as the result of returnarray() is being converted
to a string. $yo === NULL...not what i want.
function returnarray() {
return array('lose' = array(5,6), 'win' = array(9,8));
}
$yo = returnarray()-['lose'];
var_dump($yo);
This yields a parse error.
function returnarray() {
return array('lose' = array(5,6), 'win' = array(9,8));
}
$yo = ${returnarray()}-['lose'];
var_dump($yo);
This yields a parse error.
Thanks for your help in advance.
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This is not possible in PHP, though you can have a Array wrapper class
function returnarray() {
return new ArrayObject( array('lose' = array(5,6), 'win' =
array(9,8)) );
}
var_dump (returnarray()-offsetGet('lose'));
or even better make you own wrapper class with __set() and __get()
methods so you can have
var_dump (returnarray()-lose);
of course only in PHP5
Well, not quite so fast saying this is only possible in PHP5
You could do something like this.
?php
function returnHash() {
return (object) array('lose' = array(5,6), 'win' = array(9,8));
}
print_r(returnHash()-lose);
?
Basically, this converts your newly built array into an object, using
the stdClass object.
Then reference the index via an object variable name instead of an array
style access method.
Bojan Tesanovic
http://www.carster.us/
Thanks, I appreciate your comment Bojan
DanK
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Re: [PHP] Return an Array and immediately reference an index
Stut wrote:
On 12 Apr 2008, at 00:31, Daniel Kolbo wrote:
Philip Thompson wrote:
On Apr 11, 2008, at 5:33 PM, Daniel Kolbo wrote:
I want to return an array from function and reference an index all
in one line. Is this possible?
In the code below I want I want $yo to be the array(5,6).
Here is what I've tried,
function returnarray() {
return array('lose' = array(5,6), 'win' = array(9,8));
}
$yo = returnarray()['lose'];
var_dump($yo);
This yields a parse error.
function returnarray() {
return array('lose' = array(5,6), 'win' = array(9,8));
}
$yo = {returnarray()}['lose'];
var_dump($yo);
This yields a parse error.
function returnarray() {
return array('lose' = array(5,6), 'win' = array(9,8));
}
$yo = ${returnarray()}['lose'];
var_dump($yo);
This gives notices as the result of returnarray() is being converted
to a string. $yo === NULL...not what i want.
function returnarray() {
return array('lose' = array(5,6), 'win' = array(9,8));
}
$yo = returnarray()-['lose'];
var_dump($yo);
This yields a parse error.
function returnarray() {
return array('lose' = array(5,6), 'win' = array(9,8));
}
$yo = ${returnarray()}-['lose'];
var_dump($yo);
This yields a parse error.
The PHP parser does not support this, but you may see it in a future
version - it's a commonly requested feature.
There are various ways to code around this limitation as other posters
have stated but to me they all add far too much processing to make it
worth saving a line of code and a temporary variable.
-Stut
Thanks Stut. By chance do you know of any proposed syntax for this
feature? Or, what syntax would seem logical to you?
DanK
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Re: [PHP] Return an Array and immediately reference an index
On 12 Apr 2008, at 15:18, Daniel Kolbo wrote:
Stut wrote:
On 12 Apr 2008, at 00:31, Daniel Kolbo wrote:
Philip Thompson wrote:
On Apr 11, 2008, at 5:33 PM, Daniel Kolbo wrote:
I want to return an array from function and reference an index
all in one line. Is this possible?
In the code below I want I want $yo to be the array(5,6).
Here is what I've tried,
function returnarray() {
return array('lose' = array(5,6), 'win' = array(9,8));
}
$yo = returnarray()['lose'];
var_dump($yo);
This yields a parse error.
function returnarray() {
return array('lose' = array(5,6), 'win' = array(9,8));
}
$yo = {returnarray()}['lose'];
var_dump($yo);
This yields a parse error.
function returnarray() {
return array('lose' = array(5,6), 'win' = array(9,8));
}
$yo = ${returnarray()}['lose'];
var_dump($yo);
This gives notices as the result of returnarray() is being
converted to a string. $yo === NULL...not what i want.
function returnarray() {
return array('lose' = array(5,6), 'win' = array(9,8));
}
$yo = returnarray()-['lose'];
var_dump($yo);
This yields a parse error.
function returnarray() {
return array('lose' = array(5,6), 'win' = array(9,8));
}
$yo = ${returnarray()}-['lose'];
var_dump($yo);
This yields a parse error.
The PHP parser does not support this, but you may see it in a
future version - it's a commonly requested feature.
There are various ways to code around this limitation as other
posters have stated but to me they all add far too much processing
to make it worth saving a line of code and a temporary variable.
-Stut
Thanks Stut. By chance do you know of any proposed syntax for this
feature? Or, what syntax would seem logical to you?
I'm sure I've seen it discussed on the internals list but I don't know
if anything has been agreed. Your best bet is to search the archives
for the internals list.
-Stut
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Re: [PHP] Return an Array and immediately reference an index
On Fri, Apr 11, 2008 at 6:33 PM, Daniel Kolbo [EMAIL PROTECTED] wrote: search the archives ;) http://www.mail-archive.com/php-general@lists.php.net/msg224626.html -nathan
Re: [PHP] Return an Array and immediately reference an index
On Sat, Apr 12, 2008 at 9:12 AM, Nathan Nobbe [EMAIL PROTECTED] wrote:
On Fri, Apr 11, 2008 at 6:33 PM, Daniel Kolbo [EMAIL PROTECTED] wrote:
search the archives ;)
http://www.mail-archive.com/php-general@lists.php.net/msg224626.html
-nathan
?php
function ReturnArray() {
return array('a' = 'f', 'b' = 'g', 'c' = 'h', 'd' = 'i', 'e' = 'j');
}
echo ${!${!1}=ReturnArray()}['a']; // 'f'
?
:)
--
-Casey
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Re: [PHP] Return an Array and immediately reference an index
On Sat, Apr 12, 2008 at 12:18 PM, Casey [EMAIL PROTECTED] wrote:
On Sat, Apr 12, 2008 at 9:12 AM, Nathan Nobbe [EMAIL PROTECTED]
wrote:
On Fri, Apr 11, 2008 at 6:33 PM, Daniel Kolbo [EMAIL PROTECTED] wrote:
search the archives ;)
http://www.mail-archive.com/php-general@lists.php.net/msg224626.html
-nathan
?php
function ReturnArray() {
return array('a' = 'f', 'b' = 'g', 'c' = 'h', 'd' = 'i', 'e' =
'j');
}
echo ${!${!1}=ReturnArray()}['a']; // 'f'
?
ya; i never did sit down and try to figure out how that works; care to
explain ?
-nathan
Re: [PHP] Return an Array and immediately reference an index
On Sat, Apr 12, 2008 at 9:35 AM, Nathan Nobbe [EMAIL PROTECTED] wrote:
On Sat, Apr 12, 2008 at 12:18 PM, Casey [EMAIL PROTECTED] wrote:
On Sat, Apr 12, 2008 at 9:12 AM, Nathan Nobbe [EMAIL PROTECTED]
wrote:
On Fri, Apr 11, 2008 at 6:33 PM, Daniel Kolbo [EMAIL PROTECTED] wrote:
search the archives ;)
http://www.mail-archive.com/php-general@lists.php.net/msg224626.html
-nathan
?php
function ReturnArray() {
return array('a' = 'f', 'b' = 'g', 'c' = 'h', 'd' = 'i', 'e' =
'j');
}
echo ${!${!1}=ReturnArray()}['a']; // 'f'
?
ya; i never did sit down and try to figure out how that works; care to
explain ?
-nathan
?php
echo ${!${!1}=ReturnArray()}['a'];
${!${!1}=ReturnArray()}['a']
!1 resolves to false.
${!${false}=ReturnArray()}['a']
false resolves to... I don't know. Let's just say false resolves to a.
${!$a=ReturnArray()}['a']
$a is now the array. The ! changes the returned array into the
boolean false (like: if (!$handle = fopen('x', 'r')) { echo
'connection failed' }.
${false}['a']
I don't know what false resolves to, but we're using a.
$a['a']
?
--
-Casey
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Re: [PHP] Return an Array and immediately reference an index
Casey wrote:
On Sat, Apr 12, 2008 at 9:35 AM, Nathan Nobbe [EMAIL PROTECTED] wrote:
On Sat, Apr 12, 2008 at 12:18 PM, Casey [EMAIL PROTECTED] wrote:
On Sat, Apr 12, 2008 at 9:12 AM, Nathan Nobbe [EMAIL PROTECTED]
wrote:
On Fri, Apr 11, 2008 at 6:33 PM, Daniel Kolbo [EMAIL PROTECTED] wrote:
search the archives ;)
http://www.mail-archive.com/php-general@lists.php.net/msg224626.html
-nathan
?php
function ReturnArray() {
return array('a' = 'f', 'b' = 'g', 'c' = 'h', 'd' = 'i', 'e' =
'j');
}
echo ${!${!1}=ReturnArray()}['a']; // 'f'
?
ya; i never did sit down and try to figure out how that works; care to
explain ?
-nathan
?php
echo ${!${!1}=ReturnArray()}['a'];
${!${!1}=ReturnArray()}['a']
!1 resolves to false.
${!${false}=ReturnArray()}['a']
false resolves to... I don't know. Let's just say false resolves to a.
${!$a=ReturnArray()}['a']
$a is now the array. The ! changes the returned array into the
boolean false (like: if (!$handle = fopen('x', 'r')) { echo
'connection failed' }.
${false}['a']
I don't know what false resolves to, but we're using a.
$a['a']
?
Just awesome! Thanks for the explanation Casey, and thanks for the
archived link Nathan. I knew I'd learn something by asking.
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Re: [PHP] Return an Array and immediately reference an index
On Apr 12, 2008, at 6:18 PM, Casey wrote:
On Sat, Apr 12, 2008 at 9:12 AM, Nathan Nobbe
[EMAIL PROTECTED] wrote:
On Fri, Apr 11, 2008 at 6:33 PM, Daniel Kolbo [EMAIL PROTECTED]
wrote:
search the archives ;)
http://www.mail-archive.com/php-general@lists.php.net/msg224626.html
-nathan
?php
function ReturnArray() {
return array('a' = 'f', 'b' = 'g', 'c' = 'h', 'd' = 'i',
'e' = 'j');
}
echo ${!${!1}=ReturnArray()}['a']; // 'f'
?
:)
--
-Casey
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WOW!! PHP always surprises me, this is the pros of PHP not being
strict type language.
Igor Jocic
http://www.carster.us/
[PHP] Return an Array and immediately reference an index
Hello,
I want to return an array from function and reference an index all in
one line. Is this possible?
In the code below I want I want $yo to be the array(5,6).
Here is what I've tried,
function returnarray() {
return array('lose' = array(5,6), 'win' = array(9,8));
}
$yo = returnarray()['lose'];
var_dump($yo);
This yields a parse error.
function returnarray() {
return array('lose' = array(5,6), 'win' = array(9,8));
}
$yo = {returnarray()}['lose'];
var_dump($yo);
This yields a parse error.
function returnarray() {
return array('lose' = array(5,6), 'win' = array(9,8));
}
$yo = ${returnarray()}['lose'];
var_dump($yo);
This gives notices as the result of returnarray() is being converted to
a string. $yo === NULL...not what i want.
function returnarray() {
return array('lose' = array(5,6), 'win' = array(9,8));
}
$yo = returnarray()-['lose'];
var_dump($yo);
This yields a parse error.
function returnarray() {
return array('lose' = array(5,6), 'win' = array(9,8));
}
$yo = ${returnarray()}-['lose'];
var_dump($yo);
This yields a parse error.
Thanks for your help in advance.
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Re: [PHP] Return an Array and immediately reference an index
Top-posting side comment: It's not nice to hijack threads.
My comments are below...
On Apr 11, 2008, at 5:33 PM, Daniel Kolbo wrote:
Hello,
I want to return an array from function and reference an index all
in one line. Is this possible?
In the code below I want I want $yo to be the array(5,6).
Here is what I've tried,
function returnarray() {
return array('lose' = array(5,6), 'win' = array(9,8));
}
$yo = returnarray()['lose'];
var_dump($yo);
This yields a parse error.
function returnarray() {
return array('lose' = array(5,6), 'win' = array(9,8));
}
$yo = {returnarray()}['lose'];
var_dump($yo);
This yields a parse error.
function returnarray() {
return array('lose' = array(5,6), 'win' = array(9,8));
}
$yo = ${returnarray()}['lose'];
var_dump($yo);
This gives notices as the result of returnarray() is being converted
to a string. $yo === NULL...not what i want.
function returnarray() {
return array('lose' = array(5,6), 'win' = array(9,8));
}
$yo = returnarray()-['lose'];
var_dump($yo);
This yields a parse error.
function returnarray() {
return array('lose' = array(5,6), 'win' = array(9,8));
}
$yo = ${returnarray()}-['lose'];
var_dump($yo);
This yields a parse error.
Thanks for your help in advance.
Perhaps these pages may assist you:
http://php.net/manual/en/function.array.php
http://php.net/functions
For more immediate help, I think you want to do something along these
lines:
?php
function returnArray ($index) {
$arr = array('lose'=array(5,6), 'win'=array(9,8));
return isset ($arr[$index]) ? $arr[$index] : 'Index not found';
}
$returnTheValueForThis = 'lose';
$result = returnArray ($returnTheValueForThis);
var_dump ($result);
?
This var_dump will return:
array(2) { [0]= int(5) [1]= int(6) }
Hope that helps. Do some more reading in the manual to help yourself
out. ;)
~Philip
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Re: [PHP] Return an Array and immediately reference an index
Philip Thompson wrote:
Top-posting side comment: It's not nice to hijack threads.
My comments are below...
On Apr 11, 2008, at 5:33 PM, Daniel Kolbo wrote:
Hello,
I want to return an array from function and reference an index all in
one line. Is this possible?
In the code below I want I want $yo to be the array(5,6).
Here is what I've tried,
function returnarray() {
return array('lose' = array(5,6), 'win' = array(9,8));
}
$yo = returnarray()['lose'];
var_dump($yo);
This yields a parse error.
function returnarray() {
return array('lose' = array(5,6), 'win' = array(9,8));
}
$yo = {returnarray()}['lose'];
var_dump($yo);
This yields a parse error.
function returnarray() {
return array('lose' = array(5,6), 'win' = array(9,8));
}
$yo = ${returnarray()}['lose'];
var_dump($yo);
This gives notices as the result of returnarray() is being converted
to a string. $yo === NULL...not what i want.
function returnarray() {
return array('lose' = array(5,6), 'win' = array(9,8));
}
$yo = returnarray()-['lose'];
var_dump($yo);
This yields a parse error.
function returnarray() {
return array('lose' = array(5,6), 'win' = array(9,8));
}
$yo = ${returnarray()}-['lose'];
var_dump($yo);
This yields a parse error.
Thanks for your help in advance.
Perhaps these pages may assist you:
http://php.net/manual/en/function.array.php
http://php.net/functions
For more immediate help, I think you want to do something along these
lines:
?php
function returnArray ($index) {
$arr = array('lose'=array(5,6), 'win'=array(9,8));
return isset ($arr[$index]) ? $arr[$index] : 'Index not found';
}
$returnTheValueForThis = 'lose';
$result = returnArray ($returnTheValueForThis);
var_dump ($result);
?
This var_dump will return:
array(2) { [0]= int(5) [1]= int(6) }
Hope that helps. Do some more reading in the manual to help yourself
out. ;)
~Philip
Just to be sure, where you saying I hijacked a thread? If so, please
educate me as to how i did this. Now to the response.
Thanks for the response.
I am familiar with the construction and returning of the arrays and
referencing an index of the array. I understand your code. However,
this is not what I am trying to do.
I could simply do:
function returnarray() {
return array('lose' = array(5,6), 'win' = array(9,8));
}
$yo = returnarray();
var_dump($yo['lose']);
To get my desired result.
I was just seeing if PHP had the capability to combine those last two
lines into one. I realize the function itself is rather trivial, but
just wanted some function to return an array for the sake of demonstration.
Thanks,
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Re: [PHP] Return an Array and immediately reference an index
On Apr 11, 2008, at 6:31 PM, Daniel Kolbo wrote:
Philip Thompson wrote:
Top-posting side comment: It's not nice to hijack threads.
My comments are below...
On Apr 11, 2008, at 5:33 PM, Daniel Kolbo wrote:
Hello,
I want to return an array from function and reference an index all
in one line. Is this possible?
In the code below I want I want $yo to be the array(5,6).
Here is what I've tried,
function returnarray() {
return array('lose' = array(5,6), 'win' = array(9,8));
}
$yo = returnarray()['lose'];
var_dump($yo);
This yields a parse error.
function returnarray() {
return array('lose' = array(5,6), 'win' = array(9,8));
}
$yo = {returnarray()}['lose'];
var_dump($yo);
This yields a parse error.
function returnarray() {
return array('lose' = array(5,6), 'win' = array(9,8));
}
$yo = ${returnarray()}['lose'];
var_dump($yo);
This gives notices as the result of returnarray() is being
converted to a string. $yo === NULL...not what i want.
function returnarray() {
return array('lose' = array(5,6), 'win' = array(9,8));
}
$yo = returnarray()-['lose'];
var_dump($yo);
This yields a parse error.
function returnarray() {
return array('lose' = array(5,6), 'win' = array(9,8));
}
$yo = ${returnarray()}-['lose'];
var_dump($yo);
This yields a parse error.
Thanks for your help in advance.
Perhaps these pages may assist you:
http://php.net/manual/en/function.array.php
http://php.net/functions
For more immediate help, I think you want to do something along
these lines:
?php
function returnArray ($index) {
$arr = array('lose'=array(5,6), 'win'=array(9,8));
return isset ($arr[$index]) ? $arr[$index] : 'Index not found';
}
$returnTheValueForThis = 'lose';
$result = returnArray ($returnTheValueForThis);
var_dump ($result);
?
This var_dump will return:
array(2) { [0]= int(5) [1]= int(6) }
Hope that helps. Do some more reading in the manual to help
yourself out. ;)
~Philip
Just to be sure, where you saying I hijacked a thread? If so,
please educate me as to how i did this. Now to the response.
If you are viewing a message (in this case, the thread entitled
Quarters -- ERRORS --) and you hit Reply and change the message to
whatever (in this case, Return an Array and immediately reference an
index), it still shows up in the same thread as the Quarters one.
This implies that your email has to do with the Quarters one... but it
really doesn't. =D
So, in order to fix this, just hit New instead of Reply. =D No harm
done, just good listserv netiquette for people reading their emails
that shove the *same content* emails together. We're all here to
learn, right.
Thanks for the response.
I am familiar with the construction and returning of the arrays and
referencing an index of the array. I understand your code.
However, this is not what I am trying to do.
I could simply do:
function returnarray() {
return array('lose' = array(5,6), 'win' = array(9,8));
}
$yo = returnarray();
var_dump($yo['lose']);
To get my desired result.
I was just seeing if PHP had the capability to combine those last
two lines into one. I realize the function itself is rather
trivial, but just wanted some function to return an array for the
sake of demonstration.
Thanks,
Oooh. I see what you're saying now. Sorry for the confusion. To my
knowledge (which is limited ;), I don't think you can do that. This is
somewhat similar to some desired functionality in PHP - I don't
remember the name of it. For example,
?php
class f1() {
function f2() {
echo Hello;
}
function f3() {
echo World!;
}
}
new f1()-f2() . new f1()-f3();
?
Something like that. Basically, call a class/function and get the
contents directly without instantiating it first. Maybe others have an
opinion on this
~Philip
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Re: [PHP] Return an Array and immediately reference an index
On Apr 12, 2008, at 12:33 AM, Daniel Kolbo wrote:
Hello,
I want to return an array from function and reference an index all
in one line. Is this possible?
In the code below I want I want $yo to be the array(5,6).
Here is what I've tried,
function returnarray() {
return array('lose' = array(5,6), 'win' = array(9,8));
}
$yo = returnarray()['lose'];
var_dump($yo);
This yields a parse error.
function returnarray() {
return array('lose' = array(5,6), 'win' = array(9,8));
}
$yo = {returnarray()}['lose'];
var_dump($yo);
This yields a parse error.
function returnarray() {
return array('lose' = array(5,6), 'win' = array(9,8));
}
$yo = ${returnarray()}['lose'];
var_dump($yo);
This gives notices as the result of returnarray() is being
converted to a string. $yo === NULL...not what i want.
function returnarray() {
return array('lose' = array(5,6), 'win' = array(9,8));
}
$yo = returnarray()-['lose'];
var_dump($yo);
This yields a parse error.
function returnarray() {
return array('lose' = array(5,6), 'win' = array(9,8));
}
$yo = ${returnarray()}-['lose'];
var_dump($yo);
This yields a parse error.
Thanks for your help in advance.
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This is not possible in PHP, though you can have a Array wrapper class
function returnarray() {
return new ArrayObject( array('lose' = array(5,6), 'win' = array
(9,8)) );
}
var_dump (returnarray()-offsetGet('lose'));
or even better make you own wrapper class with __set() and __get()
methods so you can have
var_dump (returnarray()-lose);
of course only in PHP5
Bojan Tesanovic
http://www.carster.us/
