Hello Richard,
Wednesday, July 25, 2007, 12:05:22 AM, you wrote:
I think you're just missing $contato_name = $_POST['contato_name'] in
here somewhere...
That was what was missing indeed :-)
That said, if you are using striplashes, you have magic_quotes_gpc on,
and that's something you may
Good afternoon list,
Probably a no-brainer for the most of you but i'm in a pickle: i've
set up a variable to receive in the body of the notification mail
upon sending a form.
The body of the mail should read like this:
Obrigado por nos contatar, $contato_name. Recebemos sua mensagem
[ For those of you who are going to get pissed for top-posting, find
something better to bitch about. I'm in a rush, but trying to help.
;-P ]
Luc,
You're not defining $contato_name.
Do this:
$contato_name = $_POST['contato_name'];
On 7/24/07, Luc [EMAIL PROTECTED] wrote:
Good evening Daniel,
It was foretold that on 24/7/2007 @ 17:47:46 GMT-0400 (which was
18:47:46 where I live) Daniel Brown would write:
snipped a bit
You're not defining $contato_name.
Do this:
$contato_name = $_POST['contato_name'];
Yes!!
Oh so simple for a
On Tue, July 24, 2007 3:33 pm, Luc wrote:
if (empty($_POST['altura'])){
$contacter_form_error[] = 'favor preencher altura';
}
if (empty($_POST['largura'])){
$contacter_form_error[] = 'favor preencher largura';
}
else {
Wong [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Thursday, February 06, 2003 12:25 AM
Subject: Re: Re: RE: [PHP] Variable Problem
On Thursday 06 February 2003 07:48, Sunfire wrote:
on any server i ever dealt with if i put:
input type=sent value=?php\$sent\?
in the edit box for the value
On Thursday 06 February 2003 22:50, Sunfire wrote:
no that doesnt work either what you get when you do that one in the edit
box is:
using:
input type=text name=sent value=?php echo \$sent\;?
or any different with echo in the value field gives me in the box:
?php \\;?}
...rest of the script
I have a variable that get's chopped off at the %20 character.
In the form page I have:
bFrom: ?= $name;?
brE-mail address: ?= $email;?br
?= $sent;?/b/font/td
$sent and $name shows up fine, but immedieately I added (for testing)
input type=text name=sent value=?= $sent;?
input
On Thursday 06 February 2003 04:41, Sierra Times.com wrote:
I have a variable that get's chopped off at the %20 character.
In the form page I have:
bFrom: ?= $name;?
brE-mail address: ?= $email;?br
?= $sent;?/b/font/td
$sent and $name shows up fine, but immedieately I added
: Wednesday, February 05, 2003 3:41 PM
To: [EMAIL PROTECTED]
Subject: [PHP] Variable Problem
I have a variable that get's chopped off at the %20 character.
In the form page I have:
bFrom: ?= $name;?
brE-mail address: ?= $email;?br
?= $sent;?/b/font/td
$sent and $name shows up fine
PM
Subject: Spam: Re: [PHP] Variable Problem
On Thursday 06 February 2003 04:41, Sierra Times.com wrote:
I have a variable that get's chopped off at the %20 character.
In the form page I have:
bFrom: ?= $name;?
brE-mail address: ?= $email;?br
?= $sent;?/b/font/td
$sent
need to echo...specially if there are 300 lines of code a block...
- Original Message -
From: Leonard Burton [EMAIL PROTECTED]
To: Sierra Times.com [EMAIL PROTECTED]; [EMAIL PROTECTED]
Sent: Wednesday, February 05, 2003 4:16 PM
Subject: Spam: RE: [PHP] Variable Problem
You need to put
--- Sunfire [EMAIL PROTECTED] wrote:
you can do:
echo BLOCK
//any valid html code here
input type=sent value=\sent\
BLOCK;
No, he needed to output $sent, which is dynamic.
Also, it is a lot cleaner (and likely faster) just to use
? (or ?php) and ? to switch in/out of PHP as needed. If
Shiflett [EMAIL PROTECTED]
To: Sunfire [EMAIL PROTECTED]; [EMAIL PROTECTED]
Sent: Wednesday, February 05, 2003 5:44 PM
Subject: Spam: Re: RE: [PHP] Variable Problem
--- Sunfire [EMAIL PROTECTED] wrote:
you can do:
echo BLOCK
//any valid html code here
input type=sent value=\sent\
BLOCK
--- Sunfire [EMAIL PROTECTED] wrote:
on any server i ever dealt with if i put:
input type=sent value=?php\$sent\?
in the edit box for the value i always always end up
with ?php instead of what $sent stands for..the only
way i found it to work is with echo but maybe im
missing something
You
On Thursday 06 February 2003 07:48, Sunfire wrote:
on any server i ever dealt with if i put:
input type=sent value=?php\$sent\?
in the edit box for the value i always always end up with ?php instead of
what $sent stands for..the only way i found it to work is with echo but
maybe im missing
I have a variable name in a print END and then some text after it. The
thing is, php thinks that the text is part of the variable name, which makes
the variable, and the text after it, not show up. But, if I put a space, it
makes my html not work right. Any ideas?
--
PHP General Mailing
show your code
-Original Message-
From: Leif K-Brooks [mailto:[EMAIL PROTECTED]]
Sent: Friday, March 22, 2002 5:18 PM
To: [EMAIL PROTECTED]
Subject: [PHP] Variable problem
I have a variable name in a print END and then some text after it. The
thing is, php thinks that the text
${varable}ABC
-Original Message-
From: Leif K-Brooks [mailto:[EMAIL PROTECTED]]
Sent: Friday, March 22, 2002 5:21 PM
To: Rick Emery
Subject: Re: [PHP] Variable problem
on 3/22/02 6:18 PM, Rick Emery at [EMAIL PROTECTED] wrote:
show your code
-Original Message-
From
On 22 Mar 2002 at 17:27, Rick Emery wrote:
${varable}ABC
in quotes you can help php with
{$(varabl)}ABC
-Original Message-
From: Leif K-Brooks [mailto:[EMAIL PROTECTED]]
Sent: Friday, March 22, 2002 5:21 PM
To: Rick Emery
Subject: Re: [PHP] Variable problem
on 3/22
Hello,
I created a librairy with configuration setting: background color, font size,
customer's name, etc. Like this:
(lib_config.inc)
$bgcolor = #ff;
$co = ABC enterprise;
A second file is building html page headders:
(lib_intra.inc)
function title($name_section,$name_page){
print
:26 PM
Subject: RE: [PHP] Variable problem
Use an array !?, I mean :
$result[$i] = test;
How do I combine the following so it is treated as one variable
$i=10
$result$i=test;
I want this to be:
$result10=test;
$i changes so I cannot just put in 10 instead of I
How do I combine the following so it is treated as one variable
$i=10
$result$i=test;
I want this to be:
$result10=test;
$i changes so I cannot just put in 10 instead of I.
anybody know how i can do that?
TIA
Randy
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe,
?php
$i = 10;
eval (\$result$i=\test\;);
echo $result10;
?
Valentin Petruchek (aki Zliy Pes)
http://zliypes.com.ua
mailto:[EMAIL PROTECTED]
- Original Message -
From: [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Saturday, January 19, 2002 2:47 AM
Subject: [PHP] Variable Problem
Use an array !?, I mean :
$result[$i] = test;
How do I combine the following so it is treated as one variable
$i=10
$result$i=test;
I want this to be:
$result10=test;
$i changes so I cannot just put in 10 instead of I.
anybody know how i can do that?
--
Yoel Benitez
Hello.
How do I combine the following so it is treated as one variable
$i=10
$result$i="test";
I want this to be:
$result10="test";
$i changes so I cannot just put in 10 instead of I.
anybody know how i can do that?
TIA
Randy
How about the below.
?
$i=10;
${"result$i"}="test";
echo
How do I combine the following so it is treated as one variable.
It's a good question, but why? Most likely an array will work best for
this job, arrays are good:
http://www.php.net/manual/en/language.types.array.php
The man page on foreach is nice too, and has many examples which include
To: Fì¤á
Cc: [EMAIL PROTECTED]; [EMAIL PROTECTED]
Subject: Re: [PHP] Variable Problem
How do I combine the following so it is treated as one variable.
It's a good question, but why? Most likely an array will
work best for
this job, arrays are good:
http://www.php.net/manual/en
-Original Message-
From: Philip Olson [mailto:[EMAIL PROTECTED]]
Sent: Saturday, January 19, 2002 2:30 PM
To: Fì¤á
Cc: [EMAIL PROTECTED]; [EMAIL PROTECTED]
Subject: Re: [PHP] Variable Problem
How do I combine the following so it is treated as one variable.
It's a good
Hi!
I 'm trying not to hard code my php coding and I'm trying to pass a
variable name into the $row[coloumname_$variable];
I get an error message for this code.
I'm just wondering if I could do this trick using other ways of writing
it.
Thanks for reviewing!
regards,
Dani
--
PHP General
-BEGIN PGP SIGNED MESSAGE-
Hash: SHA1
* On 16-01-02 at 12:45
* Dani said
Hi!
I 'm trying not to hard code my php coding and I'm trying to pass a
variable name into the $row[coloumname_$variable];
I get an error message for this code.
I'm just wondering if I could do
Hi!
I 'm trying not to hard code my php coding and I'm trying to pass a
variable name into the $row[coloumname_$variable];
$row[columname_$variable] should do it.
$row[constant] is threaten as constant which is normally not the programmers
intention (set_error_reporting(0) and you'll see
$row[coloumname_${v$ariable}]
-Original Message-
From: Dani [mailto:[EMAIL PROTECTED]]
Sent: Wednesday, January 16, 2002 8:36 AM
To: [EMAIL PROTECTED]
Subject: [PHP] variable problem - help!
Importance: High
Hi!
I 'm trying not to hard code my php coding and I'm trying to pass
hi again james,
btw, consider doing this :
if (empty($submit)) {
or
if (!empty($submit)) {
as it doesn't run into such problems. or use isset although i tend to
almost always use empty, i LOVE empty() !!! each have their uses :
http://www.php.net/manual/en/function.empty.php
James Smith wrote:
Alright, when i was programming with PHP3, I would use
if statements like this:
if(!$submit) {
// display form
} else {
// display signup complete
}
to make multiple pages. Or I would do this:
if($action == "signup") {
if(!$submit) {
//display
://chatmusic.com/volunteer.htm
- Original Message -
From: James Smith [EMAIL PROTECTED]
Newsgroups: php.general
Sent: Tuesday, January 30, 2001 1:54 AM
Subject: [PHP] Variable Problem when UPGRADING...
Alright, when i was programming with PHP3, I would use
if statements like this:
if(!$submit
Alright, when i was programming with PHP3, I would use
if statements like this:
if(!$submit) {
// display form
} else {
// display signup complete
}
to make multiple pages. Or I would do this:
if($action == "signup") {
if(!$submit) {
//display form
} else {
// display
this has to do with error reporting,
using the function :
http://www.php.net/manual/en/function.error-reporting.php
definition of types :
http://www.php.net/manual/en/phpdevel-errors.php
you may have E_ALL or E_NOTICE on within php.ini
philip olson
http://www.cornado.com/
On Mon, 29 Jan
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