Re: [PHP] can't figure out this mysql error

2004-01-27 Thread Jason Wong
On Tuesday 27 January 2004 02:23, Chris W. Parker wrote: > If I put the two functions mysql functions within the query method I > created I get an error on those two lines BUT the program continues as > normal WITH the data being printed to the page just as I want it to. > Clearly the mysql resour

RE: [PHP] can't figure out this mysql error

2004-01-26 Thread Chris W. Parker
Jason Wong on Friday, January 23, 2004 10:03 PM said: > Time to put the php debugger in action -- echo all your variables to > see that contain what you expect them to contain. 'echo $this->Result;' prints "Resource id #2" 'print_r($this->Result);' prints "Resource

Re: [PHP] can't figure out this mysql error

2004-01-23 Thread Jason Wong
On Saturday 24 January 2004 01:07, Chris W. Parker wrote: > on Friday, January 23, 2004 8:54 AM said: > > All of what you say makes sense. Hopefully your suggestion will help > > me find the problem! > > In looking through my code I see that I already do this. EVERY call to a > mysql function

RE: [PHP] can't figure out this mysql error

2004-01-23 Thread Chris W. Parker
Chris W. Parker <> on Friday, January 23, 2004 8:54 AM said: > All of what you say makes sense. Hopefully your suggestion will help > me find the problem! In looking through my code I see that I already do this. EVERY call to a mysql function has "or die($this->stop("$current_line:".__LINE__)

RE: [PHP] can't figure out this mysql error

2004-01-23 Thread Chris W. Parker
Jason Wong on Thursday, January 22, 2004 8:49 PM said: > The if-clause will never be evaluated because if there had been an > error your program would have dieded on the previous line. Heh.. yeah I thought about that as I was examining the code for this post. But th

Re: [PHP] can't figure out this mysql error

2004-01-22 Thread Jason Wong
On Friday 23 January 2004 09:38, Chris W. Parker wrote: > function query($sql, $current_line) > { > $this->Result = mysql_query($sql) or die($this->stop($current_line)); > > if(!$this->Result) > { > echo mysql_error(); > } The if-clause will never be evaluated because if there had be

[PHP] can't figure out this mysql error

2004-01-22 Thread Chris W. Parker
Hi. I have a db class that accesses and executes querys as well as returns the result (if you so choose to have it returned). One method within this class is called query() (how genius!). It's defined like so: Result = mysql_query($sql) or die($this->stop($current_line)); if(!$this->Result)