Re: [PHP] generating variable names

2002-09-08 Thread timo stamm
Hi Kevin, I find it a bit awkward to mix variables and arrays in a pseudo array. But I guess you have reasons... Anyhow, maybe this is what you want: $variable1="one"; $variable2="two"; $variable3 = array(); $variable3[0]="three"; $variable4 = array(); $variable4[0]="four"; $j=1; wh

RE: [PHP] generating variable names

2002-09-06 Thread Daniel Masson
septiembre de 2002 13:38 Para: php-general Asunto: [PHP] generating variable names Hoping someone can help me with this. Below I have an example of what I'm trying to accomplish. Bottom line.. I need to print out $variable3[0] and $variable4[0] and my problem is that I'm trying to gen

[PHP] generating variable names

2002-09-06 Thread Kevin Heflin
Hoping someone can help me with this. Below I have an example of what I'm trying to accomplish. Bottom line.. I need to print out $variable3[0] and $variable4[0] and my problem is that I'm trying to generate the variable name. I can get this to work with $variable1 and $variable2 which are not a

Re: [PHP] Generating variable names 'on the fly'

2001-09-21 Thread Marcus Rasmussen
You can allso do like this: $i = 1; ${"test". $i} = "123"; echo $test1; ___ Marcus Rasmussen [EMAIL PROTECTED] On 21-09-01 at 11:21 _lallous wrote: >you can always use eval to create a variable too! > >$i = 1; >eval("\$test$i=123;"); >echo $test1; >?> > >

[PHP] Generating variable names 'on the fly'

2001-09-20 Thread Neil Freeman
Hi there, How do I generate variable names 'on the fly'? I wish to have variable names along the lines of $genre_category_1, $genre_category_2, $genre_category_3 etc. Ideally it would be along the lines of this... ### $current_field_number = 1; $genre_number_fields = 7; whi