[PHP] Passing array to function

I am trying to write a function that builds a multiple-choice drop down list. As such, I need to specify an array in the name attribute of the select tag. I am trying to pass a parameter to the function which gets used as this name attribute, but seem to be having problems with the square

RE: [PHP] Passing array to function

-Original Message- From: Bill Hudspeth [mailto:[EMAIL PROTECTED]] Sent: 13 August 2002 17:10 [] DESIRED FUNCTION VERSION $elementname=cgroup_1[]; $elementsarray=$chon_group_a; PrintOptionBox($elementname,$elementsarray); Well, looks ok-ish so far -- what's in the

[PHP] passing array to function?

How do you write a function that takes an array as an argument? Could someone please point me at an example? Regards, Jaxon -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list

Re: [PHP] passing array to function?

On Wed, 7 Feb 2001 11:30, Jaxon wrote: How do you write a function that takes an array as an argument? Could someone please point me at an example? Regards, Jaxon Try this: ?php function show_elements($ary) { while(list($key,$val) = each($ary)) { echo "$key =