[PHP] simple, but missing something?

[Jas]

Not sure why I am not able to get this to work, but to make my stuff 
easier to configure for different environments I am trying to re-code 
some of my stuff to work with options from an array.

$cfg['hostname'] = www.server.com;  // Server domain or ip address
$cfg['username'] = username;// Database user name
$cfg['password'] = password;// Database password
$cfg['bugemail'] = [EMAIL PROTECTED];
The do something like this:

function database_connection() {
 @mysql_connect($cfg[hostname],$cfg[username],$cfg[password]);
 @mysql_select_database($cfg[database]); }
Is there something special I have to do to get variables out of an array 
for use here?  I have used $user = name; and called stuff like 
@mysql_connect($name); and it has worked before, I think I am missing 
something here.

TIA
Jas
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RE: [PHP] simple, but missing something?

[Jay Blanchard]

[snip]
$cfg['hostname'] = www.server.com;  // Server domain or ip address
$cfg['username'] = username;// Database user name
$cfg['password'] = password;// Database password
$cfg['bugemail'] = [EMAIL PROTECTED];

The do something like this:

function database_connection() {
  @mysql_connect($cfg[hostname],$cfg[username],$cfg[password]);
  @mysql_select_database($cfg[database]); }
[/snip]

Why are you not using the single quoted array names? i.e.

  @mysql_connect($cfg['hostname'],$cfg['username'],$cfg['password']);

Have you echo'd each out afterwords to see if they are right? Use
mysql_error() to return connection errors so that you know what they
are.

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Re: [PHP] simple, but missing something?

[Jas]

Jay Blanchard wrote:

[snip]
$cfg['hostname'] = www.server.com;  // Server domain or ip address
$cfg['username'] = username;// Database user name
$cfg['password'] = password;// Database password
$cfg['bugemail'] = [EMAIL PROTECTED];
The do something like this:

function database_connection() {
  @mysql_connect($cfg[hostname],$cfg[username],$cfg[password]);
  @mysql_select_database($cfg[database]); }
[/snip]
Why are you not using the single quoted array names? i.e.

  @mysql_connect($cfg['hostname'],$cfg['username'],$cfg['password']);

Have you echo'd each out afterwords to see if they are right? Use
mysql_error() to return connection errors so that you know what they
are.
Yeah I have tried single quoted array names, double-quoted variable 
names, and the output of the print_r($cfg) displays the variables are 
present and when I do a mysql_error() and mysql_errno() I get could not 
connect to database, 1046 errors.

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Re: [PHP] simple, but missing something?

[Burhan Khalid]

Jas wrote:
Not sure why I am not able to get this to work, but to make my stuff 
easier to configure for different environments I am trying to re-code 
some of my stuff to work with options from an array.

$cfg['hostname'] = www.server.com;  // Server domain or ip address
$cfg['username'] = username;// Database user name
$cfg['password'] = password;// Database password
$cfg['bugemail'] = [EMAIL PROTECTED];
The do something like this:

function database_connection() {
 @mysql_connect($cfg[hostname],$cfg[username],$cfg[password]);
 @mysql_select_database($cfg[database]); }
I think your array isn't in scope here, that's why you can't see the array.

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