Re: [PHP] simplify if/then statement
Using pull down for $state. This works great! > $incfilename = "Calc".$state.".class.inc"; > if (file_exists($incfilename)) > include($incfilename); > else > echo "Please select a State.\n"; Thanks To Everyone, j -- http://jimlong.net/web > I'd do something similar to this, along with > putting all states in an array to make sure > $state is actually a state (in_array). And > maybe you want to add guam :) > > a) be sure $state is set, else load default > b) be sure $state is not bogus, else yell at them > c) be sure the $state file exists, if so, include >it else houston we have a problem -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] simplify if/then statement
On Sat, 27 Apr 2002, Philip Olson wrote: > I'd do something similar to this, along with putting all states in an > array to make sure $state is actually a state (in_array). And maybe you > want to add guam :) As an early Christmas present, here's the array (to save the OP some typing - I'm posting this to the list because I use it a lot and assume it'd be handy for others too). Uses USPS 2-letter abbreviations and includes territories. $states = array( 'AK' => 'Alaska', 'AL' => 'Alabama', 'AR' => 'Arkansas', 'AS' => 'American Samoa', 'AZ' => 'Arizona', 'CA' => 'California', 'CO' => 'Colorado', 'CT' => 'Connecticut', 'DC' => 'District of Columbia', 'DE' => 'Delaware', 'FL' => 'Florida', 'GA' => 'Georgia', 'GU' => 'Guam', 'HI' => 'Hawaii', 'IA' => 'Iowa', 'ID' => 'Idaho', 'IL' => 'Illinois', 'IN' => 'Indiana', 'KS' => 'Kansas', 'KY' => 'Kentucky', 'LA' => 'Louisiana', 'MA' => 'Massachusetts', 'MD' => 'Maryland', 'ME' => 'Maine', 'MH' => 'Marshall Islands', 'MI' => 'Michigan', 'MN' => 'Minnesota', 'MO' => 'Missouri', 'MP' => 'Northern Mariana Islands', 'MS' => 'Mississippi', 'MT' => 'Montana', 'NC' => 'North Carolina', 'ND' => 'North Dakota', 'NE' => 'Nebraska', 'NH' => 'New Hampshire', 'NJ' => 'New Jersey', 'NM' => 'New Mexico', 'NV' => 'Nevada', 'NY' => 'New York', 'OH' => 'Ohio', 'OK' => 'Oklahoma', 'OR' => 'Oregon', 'PA' => 'Pennsylvania', 'PR' => 'Puerto Rico', 'RI' => 'Rhode Island', 'SC' => 'South Carolina', 'SD' => 'South Dakota', 'TN' => 'Tennessee', 'TX' => 'Texas', 'UT' => 'Utah', 'VA' => 'Virginia', 'VI' => 'Virgin Islands (U.S.)', 'VT' => 'Vermont', 'WA' => 'Washington', 'WI' => 'Wisconsin', 'WV' => 'West Virginia', 'WY' => 'Wyoming'); miguel -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] simplify if/then statement
Hi,
Make an array $arr of all the states and loop
$state = "AR";
$arr = array();
array_push($arr, "AL", "AR", "AZ");
foreach ($arr as $key => $value)
{
if ($state == $value){
include("Calc$value.class.inc");
}
}
Cheers,
Pekka
http://photography-on-the.net/
At 4/27/2002, you wrote:
>Hi,
>
>I've got the following statement for a state options menu.
>How can this be expressed in a simple manner for all 52 states?
>
>
>//choose state
>
>if ($state == "AL") {
>
>// include class
> include("CalcAL.class.inc");
>}
>
>else if ($state == "AR") {
>
>// include class
> include("CalcAR.class.inc");
>}
>
>else if ($state == "AZ") {
>
>// include class
> include("CalcAZ.class.inc");
>}
>
>else{
>echo "Please select a State.\n";
>}
>
>Thank You Very Much,
>
>Jim Long
>--
>http://jimlong.net/web
>
>--
>PHP General Mailing List (http://www.php.net/)
>To unsubscribe, visit: http://www.php.net/unsub.php
--
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RE: [PHP] simplify if/then statement
I'd do something similar to this, along with
putting all states in an array to make sure
$state is actually a state (in_array). And
maybe you want to add guam :)
a) be sure $state is set, else load default
b) be sure $state is not bogus, else yell at them
c) be sure the $state file exists, if so, include
it else houston we have a problem
Regards,
Philip Olson
On Sat, 27 Apr 2002, Stuart Dallas wrote:
> $incfilename = "Calc".$state.".class.inc";
> if (file_exists($incfilename))
> include($incfilename);
> else
> echo "Please select a State.\n";
>
> --
> Stuart
>
> -Original Message-
> From: Jim Long [mailto:[EMAIL PROTECTED]]
> Sent: 27 April 2002 20:00
> To: php
> Subject: [PHP] simplify if/then statement
>
>
> Hi,
>
> I've got the following statement for a state options menu.
> How can this be expressed in a simple manner for all 52 states?
>
>
> //choose state
>
> if ($state == "AL") {
>
> // include class
> include("CalcAL.class.inc");
> }
>
> else if ($state == "AR") {
>
> // include class
> include("CalcAR.class.inc");
> }
>
> else if ($state == "AZ") {
>
> // include class
> include("CalcAZ.class.inc");
> }
>
> else{
> echo "Please select a State.\n";
> }
>
> Thank You Very Much,
>
> Jim Long
> --
> http://jimlong.net/web
>
> --
> PHP General Mailing List (http://www.php.net/)
> To unsubscribe, visit: http://www.php.net/unsub.php
>
>
>
> --
> PHP General Mailing List (http://www.php.net/)
> To unsubscribe, visit: http://www.php.net/unsub.php
>
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] simplify if/then statement
On Sat, 27 Apr 2002, Jim Long wrote:
> I've got the following statement for a state options menu.
> How can this be expressed in a simple manner for all 52 states?
switch(strtolower($state))
{
case 'al':
include 'CalcALclass.inc';
break;
case 'ar':
include 'CalcALclass.inc';
break;
}
Or, really, just:
include "Calc{$state}class.inc";
miguel
> //choose state
>
> if ($state == "AL") {
>
> // include class
> include("CalcAL.class.inc");
> }
>
> else if ($state == "AR") {
>
> // include class
> include("CalcAR.class.inc");
> }
>
> else if ($state == "AZ") {
>
> // include class
> include("CalcAZ.class.inc");
> }
>
> else{
> echo "Please select a State.\n";
> }
>
> Thank You Very Much,
>
> Jim Long
>
--
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To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] simplify if/then statement
On Sunday 28 April 2002 02:59, Jim Long wrote:
> Hi,
>
> I've got the following statement for a state options menu.
> How can this be expressed in a simple manner for all 52 states?
>
>
> //choose state
>
> if ($state == "AL") {
>
> // include class
> include("CalcAL.class.inc");
> }
>
> else if ($state == "AR") {
Take a look at the switch construct.
--
Jason Wong -> Gremlins Associates -> www.gremlins.com.hk
Open Source Software Systems Integrators
* Web Design & Hosting * Internet & Intranet Applications Development *
/*
Parsley
is gharsley.
-- Ogden Nash
*/
--
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RE: [PHP] simplify if/then statement
$incfilename = "Calc".$state.".class.inc";
if (file_exists($incfilename))
include($incfilename);
else
echo "Please select a State.\n";
--
Stuart
-Original Message-
From: Jim Long [mailto:[EMAIL PROTECTED]]
Sent: 27 April 2002 20:00
To: php
Subject: [PHP] simplify if/then statement
Hi,
I've got the following statement for a state options menu.
How can this be expressed in a simple manner for all 52 states?
//choose state
if ($state == "AL") {
// include class
include("CalcAL.class.inc");
}
else if ($state == "AR") {
// include class
include("CalcAR.class.inc");
}
else if ($state == "AZ") {
// include class
include("CalcAZ.class.inc");
}
else{
echo "Please select a State.\n";
}
Thank You Very Much,
Jim Long
--
http://jimlong.net/web
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] simplify if/then statement
Hi,
I've got the following statement for a state options menu.
How can this be expressed in a simple manner for all 52 states?
//choose state
if ($state == "AL") {
// include class
include("CalcAL.class.inc");
}
else if ($state == "AR") {
// include class
include("CalcAR.class.inc");
}
else if ($state == "AZ") {
// include class
include("CalcAZ.class.inc");
}
else{
echo "Please select a State.\n";
}
Thank You Very Much,
Jim Long
--
http://jimlong.net/web
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
