Re: [PHP] using returned references directly?

2004-05-18 Thread Burhan Khalid 
Jeff Schmidt wrote:
Hello,
  Say I have object A, with method getObjectB(), which returns a 
reference to object2.

Is there a way to do something like $A-getObjectB()-methodFromObjectB();
Don't know if this would work, but you could give it it a try :
call_user_func(array(get_class($A-getObjectB()), 'methodFromObjectB'));
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RE: [PHP] using returned references directly?

2004-05-18 Thread Ford, Mike [LSS] 
On 17 May 2004 22:26, Jeff Schmidt wrote:

 Hello,
Say I have object A, with method getObjectB(), which returns a
 reference to object2. 
 
 Is there a way to do something like
 $A-getObjectB()-methodFromObjectB();
 
 ??
 
 When I try that, I get a parse error? Is this simply not
 possible with
 PHP, or is the syntax just a little different?
 
 I mean, I could:
 
 $b = $A-getObjectB();
 $b-methodFromObjectB();

That's how you have to do it in PHP 4.  In PHP 5, you will be able to use the 
collapsed version -- it's one of the OO improvements.

Cheers!

Mike

-
Mike Ford,  Electronic Information Services Adviser,
Learning Support Services, Learning  Information Services,
JG125, James Graham Building, Leeds Metropolitan University,
Headingley Campus, LEEDS,  LS6 3QS,  United Kingdom
Email: [EMAIL PROTECTED]
Tel: +44 113 283 2600 extn 4730  Fax:  +44 113 283 3211 

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[PHP] using returned references directly?

2004-05-17 Thread Jeff Schmidt 
Hello,
  Say I have object A, with method getObjectB(), which returns a 
reference to object2.

Is there a way to do something like $A-getObjectB()-methodFromObjectB();
??
When I try that, I get a parse error? Is this simply not possible with 
PHP, or is the syntax just a little different?

I mean, I could:
$b = $A-getObjectB();
$b-methodFromObjectB();
But since I only want to use object B once, it seems like a waste to 
store it and then use it. I do this kind of thing in other OO languages 
quite frequently.

Jeff Schmidt


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