I don't know of a built-in function, but you're welcome to use my
daydiff script below. It actually gives you year, month, day, hour,
minute, second.. Not just days. But modify it as you desire.
-TG
<?php
# Standard format dates and times
$startdate = "04/12/04";
$starttime = "13:05:01";
$enddate = "10/14/04";
$endtime = "13:05:01";
# Break apart dates and times for mktime
list($smonth,$sday,$syear) = explode("/",$startdate);
list($emonth,$eday,$eyear) = explode("/",$enddate);
list($shour,$sminute,$ssecond) = explode(":",$starttime);
list($ehour,$eminute,$esecond) = explode(":",$endtime);
# Number of seconds in each timeframe, 1 month = 30 days
$secondsequiv =
array("Years"=>31536000,"Months"=>2592000,"Days"=>86400,"Hours"=>3600,"M
inutes"=>60);
# How many seconds between two dates/times
$daydiff = mktime($ehour,$eminute,$esecond,$emonth,$eday,$eyear) -
mktime($shour,$sminute,$ssecond,$smonth,$sday,$syear);
if ($daydiff < 0) { $daydiff *= -1; $negative = TRUE; }
# Just to make sure I didn't use $remainder somewhere else in my script
and forgot
if (isset($remainder)) unset($remainder);
# Cycle through timeframes checking to see if number is large enough to
be a full year/month/day/etc
# If so, find out how many and store remainder for further processing
# If not, set to zero and continue processing
foreach ($secondsequiv as $timeframe=>$seconds) {
if (isset($remainder)) { $checkvalue = $remainder; } else {
$checkvalue = $daydiff; }
if ($checkvalue >= $seconds) {
$daydiffarr[$timeframe] = floor($checkvalue/$seconds);
$remainder = $daydiff % $seconds;
} else {
$daydiffarr[$timeframe] = 0;
}
}
# If $reminder is never used, then we're dealing with less than a
minute's worth of time diff
if (isset($remainder)) {
$daydiffarr["Seconds"] = $remainder;
} else {
$daydiffarr["Seconds"] = $daydiff;
}
# Display results
if ($negative) echo "NEGATIVE!!<br>\n";
foreach ($daydiffarr as $timeframe=>$count) {
echo "$timeframe = $count<br>\n";
}
?>
> -----Original Message-----
> From: Peter Lauri [mailto:[EMAIL PROTECTED]
> Sent: Thursday, December 02, 2004 11:38 AM
> To: [EMAIL PROTECTED]
> Subject: [PHP] Days remaining?
>
>
> Best groupmember,
>
> I have the date 2004-12-24 in a string, and 2004-11-05 in a
> other. Is there
> any date function that can assist in calculating the number
> of days left
> until 2004-12-24 when it is 2004-11-05. (the dates are just testdates)
>
> --
> - Best Of Times
> /Peter Lauri
>
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> PHP General Mailing List (http://www.php.net/)
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>
>
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