Re: [PHP] Eval()??? A variables contents?

2001-11-09 Thread Kurt Lieber

On Friday 09 November 2001 11:51 am, Christopher Raymond wrote:
 Let's say I have:

 $content = ?PHP Query_Database( $category );?;


 If I use ?PHP echo $content; ?, it doesn't evaluate that content. What am
 I doing wrong here?

What you're doing doesn't make any sense.  If it were to work, it would look 
like the following:

?PHP ?PHP Query_Database( $category );? ; ?,

or something similar.  I think what you want to do is:
?php
  $content = query_database($category);
  echo $content;
?

that's using psuedo-code, of course.  You'll want to substitute correct php 
syntax for returning database results.

--kurt

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Re: [PHP] Eval()??? A variables contents?

2001-11-09 Thread Chris Hobbs

I just asked a similar question yesterday. The answer is, conveniently
enough, eval().

One trick from the php.net page on the function is to do somehting like
this:

$content = ?PHP Query_Database( $category );?;
echo eval (?$content);


Christopher Raymond wrote:
 
 PHP Gurus:
 
 I have one for you. I'm sure there is a simple solution, but I'm having
 difficulty finding it.
 
 Let's say I have:
 
 $content = ?PHP Query_Database( $category );?;
 
 If I use ?PHP echo $content; ?, it doesn't evaluate that content. What am
 I doing wrong here?
 
 Is there an equivalent to JavaScript's eval($commands) function?
 
 TIA,
 
 Christopher Raymond
 
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Re: [PHP] Eval()??? A variables contents?

2001-11-09 Thread Christopher Raymond

on 11/9/01 2:01 PM, Kurt Lieber at [EMAIL PROTECTED] wrote:

 What you're doing doesn't make any sense.  If it were to work, it would look
 like the following:
 
 ?PHP ?PHP Query_Database( $category );? ; ?,
 
 or something similar.  I think what you want to do is:
 ?php
 $content = query_database($category);
 echo $content;
 ?
 
 that's using psuedo-code, of course.  You'll want to substitute correct php
 syntax for returning database results.




Kurt:

I understand where you are coming from, and I appreciate your answer.
However, I'm trying to get PHP to parse commands that are stored in a
variable because I'm passing those commands to a function. Inside the
function, it needs to evaluate the commands stored in the variable.

Does you solution solve that or does my description clarify my problem
better?


Thanks,

Christopher


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RE: [PHP] Eval()??? A variables contents?

2001-11-09 Thread Johnson, Kirk

http://www.php.net/manual/en/function.eval.php

Kirk


 -Original Message-
 From: Christopher Raymond [mailto:[EMAIL PROTECTED]]
 Sent: Friday, November 09, 2001 1:11 PM
 To: PHP List
 Subject: Re: [PHP] Eval()??? A variables contents?
 
 
 on 11/9/01 2:01 PM, Kurt Lieber at [EMAIL PROTECTED] wrote:
 
  What you're doing doesn't make any sense.  If it were to 
 work, it would look
  like the following:
  
  ?PHP ?PHP Query_Database( $category );? ; ?,
  
  or something similar.  I think what you want to do is:
  ?php
  $content = query_database($category);
  echo $content;
  ?
  
  that's using psuedo-code, of course.  You'll want to 
 substitute correct php
  syntax for returning database results.
 
 
 
 
 Kurt:
 
 I understand where you are coming from, and I appreciate your answer.
 However, I'm trying to get PHP to parse commands that are stored in a
 variable because I'm passing those commands to a function. Inside the
 function, it needs to evaluate the commands stored in the variable.
 
 Does you solution solve that or does my description clarify my problem
 better?

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