RE: [PHP] Insert an array into MySQL

2002-06-23 Thread John Holmes

Your second method should work, but it's dependent on what your form
looks like and how your table was created. You obviously have a key set
for this column and you're trying to insert the same value twice, which
makes an error.

Show us what your form looks like, not the whole thing, just for the
checkboxes. Also, what does your CREATE TABLE look like for the table
your trying to insert this data into?

---John Holmes...

 -Original Message-
 From: Rob Packer [mailto:[EMAIL PROTECTED]]
 Sent: Sunday, June 23, 2002 7:50 AM
 To: [EMAIL PROTECTED]
 Subject: [PHP] Insert an array into MySQL
 
 Hi, I've seen a few post for this same thing but I can't seem to get
it
 working. What I'm doing is taking a form with check boxes and putting
them
 into an array. Then I'm attempting to INSERT them into the db, one
 checkbox
 value per row.
 
 Okay,  well I've tries 2 ways that I think should work and they only
 insert
 the first value. They both produce this error Duplicate entry '0' for
key
 1 (which I don't understand) Anyway here is the code I'm trying...
 
 (I'm not trying to use both blocks of code, just one or the other)
 
 // First code
 while(list($key,$value)=each($pagetype)){
 //echo $value.br;//test
 $links=INSERT INTO $username_links (links) VALUES ('$value');
 $insert=mysql_query($links,$connection);
 
 }
 
 // Second code attempt
 $number=count($pagetype);
 for($a=0;$a$number;$a++){
 $links=INSERT INTO $username_links (links) VALUES ('$pagetype[$a]');
 $insert=mysql_query($links) or die(mysql_error());
 //echo $pagetype[$a];//test
 }
 
 
 
 
 Thanks in advance...Robert
 
 
 
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Re: [PHP] Insert an array into MySQL

2002-06-23 Thread Rob Packer


John Holmes [EMAIL PROTECTED] wrote in message
001201c21ab5$0df073a0$b402a8c0@mango">news:001201c21ab5$0df073a0$b402a8c0@mango...
 Your second method should work, but it's dependent on what your form
 looks like and how your table was created. You obviously have a key set
 for this column and you're trying to insert the same value twice, which
 makes an error.

 Show us what your form looks like, not the whole thing, just for the
 checkboxes. Also, what does your CREATE TABLE look like for the table
 your trying to insert this data into?

 ---John Holmes...

  -Original Message-
  From: Rob Packer [mailto:[EMAIL PROTECTED]]
  Sent: Sunday, June 23, 2002 7:50 AM
  To: [EMAIL PROTECTED]
  Subject: [PHP] Insert an array into MySQL
 
  Hi, I've seen a few post for this same thing but I can't seem to get
 it
  working. What I'm doing is taking a form with check boxes and putting
 them
  into an array. Then I'm attempting to INSERT them into the db, one
  checkbox
  value per row.
 
  Okay,  well I've tries 2 ways that I think should work and they only
  insert
  the first value. They both produce this error Duplicate entry '0' for
 key
  1 (which I don't understand) Anyway here is the code I'm trying...
 
  (I'm not trying to use both blocks of code, just one or the other)
 
  // First code
  while(list($key,$value)=each($pagetype)){
  //echo $value.br;//test
  $links=INSERT INTO $username_links (links) VALUES ('$value');
  $insert=mysql_query($links,$connection);
 
  }
 
  // Second code attempt
  $number=count($pagetype);
  for($a=0;$a$number;$a++){
  $links=INSERT INTO $username_links (links) VALUES ('$pagetype[$a]');
  $insert=mysql_query($links) or die(mysql_error());
  //echo $pagetype[$a];//test
  }
 
 
 
 
  Thanks in advance...Robert
 
 
 
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Re: [PHP] Insert an array into MySQL

2002-06-23 Thread Rob Packer

oops, sorry about the other post (I've got a baby that likes the
keyboard)...

Hi,

This is the form, which I had doubts about, but it seemed to put things into
the array correctly when I tested it by printing it out.
I can't see how, it will print
key=0
value=index.html
key=1
value=about.html
key=2
value=whats_new.html
when I test it and then have a duplicate key. It's saying that I have 2
$pagetype[0] correct? Anyhow, here's the form...

INPUT TYPE=hidden NAME=pagetype[] VALUE='index.html'Home Page br
INPUT TYPE=checkbox NAME=pagetype[] VALUE='about.html'About Page  br
INPUT TYPE=checkbox NAME=pagetype[] VALUE='whats_new.html'What's New
Pagebr
INPUT TYPE=checkbox NAME=pagetype[] VALUE='contact.html'Contact Pagebr
INPUT TYPE=checkbox NAME=pagetype[] VALUE='favorite_links.html'Favorite
Links br


The CREATE TABLE is this:
I define the table name from user input.

 $query_links=CREATE TABLE $username_links (id INT(4) not null, links
VARCHAR(20) not null, UNIQUE (id));
 if(mysql_query($query_links,$connection)){
  echo Links table created!br;
 }else{
  echo no links table madeBR;
 }




thanks,
 Rob




John Holmes [EMAIL PROTECTED] wrote in message
001201c21ab5$0df073a0$b402a8c0@mango">news:001201c21ab5$0df073a0$b402a8c0@mango...
 Your second method should work, but it's dependent on what your form
 looks like and how your table was created. You obviously have a key set
 for this column and you're trying to insert the same value twice, which
 makes an error.

 Show us what your form looks like, not the whole thing, just for the
 checkboxes. Also, what does your CREATE TABLE look like for the table
 your trying to insert this data into?

 ---John Holmes...

  -Original Message-
  From: Rob Packer [mailto:[EMAIL PROTECTED]]
  Sent: Sunday, June 23, 2002 7:50 AM
  To: [EMAIL PROTECTED]
  Subject: [PHP] Insert an array into MySQL
 
  Hi, I've seen a few post for this same thing but I can't seem to get
 it
  working. What I'm doing is taking a form with check boxes and putting
 them
  into an array. Then I'm attempting to INSERT them into the db, one
  checkbox
  value per row.
 
  Okay,  well I've tries 2 ways that I think should work and they only
  insert
  the first value. They both produce this error Duplicate entry '0' for
 key
  1 (which I don't understand) Anyway here is the code I'm trying...
 
  (I'm not trying to use both blocks of code, just one or the other)
 
  // First code
  while(list($key,$value)=each($pagetype)){
  //echo $value.br;//test
  $links=INSERT INTO $username_links (links) VALUES ('$value');
  $insert=mysql_query($links,$connection);
 
  }
 
  // Second code attempt
  $number=count($pagetype);
  for($a=0;$a$number;$a++){
  $links=INSERT INTO $username_links (links) VALUES ('$pagetype[$a]');
  $insert=mysql_query($links) or die(mysql_error());
  //echo $pagetype[$a];//test
  }
 
 
 
 
  Thanks in advance...Robert
 
 
 
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Re: [PHP] Insert an array into MySQL

2002-06-23 Thread Rob Packer

Nevermind, I got it. I had Unique for a field which made it mad.




Rob Packer [EMAIL PROTECTED] wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
 oops, sorry about the other post (I've got a baby that likes the
 keyboard)...

 Hi,

 This is the form, which I had doubts about, but it seemed to put things
into
 the array correctly when I tested it by printing it out.
 I can't see how, it will print
 key=0
 value=index.html
 key=1
 value=about.html
 key=2
 value=whats_new.html
 when I test it and then have a duplicate key. It's saying that I have 2
 $pagetype[0] correct? Anyhow, here's the form...

 INPUT TYPE=hidden NAME=pagetype[] VALUE='index.html'Home Page br
 INPUT TYPE=checkbox NAME=pagetype[] VALUE='about.html'About Page  br
 INPUT TYPE=checkbox NAME=pagetype[] VALUE='whats_new.html'What's New
 Pagebr
 INPUT TYPE=checkbox NAME=pagetype[] VALUE='contact.html'Contact Pagebr
 INPUT TYPE=checkbox NAME=pagetype[] VALUE='favorite_links.html'Favorite
 Links br


 The CREATE TABLE is this:
 I define the table name from user input.

  $query_links=CREATE TABLE $username_links (id INT(4) not null, links
 VARCHAR(20) not null, UNIQUE (id));
  if(mysql_query($query_links,$connection)){
   echo Links table created!br;
  }else{
   echo no links table madeBR;
  }




 thanks,
  Rob




 John Holmes [EMAIL PROTECTED] wrote in message
 001201c21ab5$0df073a0$b402a8c0@mango">news:001201c21ab5$0df073a0$b402a8c0@mango...
  Your second method should work, but it's dependent on what your form
  looks like and how your table was created. You obviously have a key set
  for this column and you're trying to insert the same value twice, which
  makes an error.
 
  Show us what your form looks like, not the whole thing, just for the
  checkboxes. Also, what does your CREATE TABLE look like for the table
  your trying to insert this data into?
 
  ---John Holmes...
 
   -Original Message-
   From: Rob Packer [mailto:[EMAIL PROTECTED]]
   Sent: Sunday, June 23, 2002 7:50 AM
   To: [EMAIL PROTECTED]
   Subject: [PHP] Insert an array into MySQL
  
   Hi, I've seen a few post for this same thing but I can't seem to get
  it
   working. What I'm doing is taking a form with check boxes and putting
  them
   into an array. Then I'm attempting to INSERT them into the db, one
   checkbox
   value per row.
  
   Okay,  well I've tries 2 ways that I think should work and they only
   insert
   the first value. They both produce this error Duplicate entry '0' for
  key
   1 (which I don't understand) Anyway here is the code I'm trying...
  
   (I'm not trying to use both blocks of code, just one or the other)
  
   // First code
   while(list($key,$value)=each($pagetype)){
   //echo $value.br;//test
   $links=INSERT INTO $username_links (links) VALUES ('$value');
   $insert=mysql_query($links,$connection);
  
   }
  
   // Second code attempt
   $number=count($pagetype);
   for($a=0;$a$number;$a++){
   $links=INSERT INTO $username_links (links) VALUES ('$pagetype[$a]');
   $insert=mysql_query($links) or die(mysql_error());
   //echo $pagetype[$a];//test
   }
  
  
  
  
   Thanks in advance...Robert
  
  
  
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   To unsubscribe, visit: http://www.php.net/unsub.php
 
 





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