Re: [PHP] Math rounding problem

Charlie, For an arbitrary large number I need to round() it up to the hundreds place if it is not divisible by 100 and leave it untouched if it is. So 1100 would round to 1100 and 1101 would round to 1200. Is there a clean way to do this? Currently I'm: $scale = round($scale+49,

RE: [PHP] Math rounding problem

This equation from Bogdan is simple and working: $scale=ceil($scale/100)*100; Thanks to all those who helped, Charlie -Original Message- From: Bogdan Stancescu [mailto:[EMAIL PROTECTED]] $scale=ceil($scale/100)*100, maybe? Bogdan -- PHP General Mailing List

Re: [PHP] Math rounding problem

ceil() maybe - Original Message - From: Charlie Killian [EMAIL PROTECTED] To: [EMAIL PROTECTED] Sent: Friday, February 08, 2002 4:14 PM Subject: [PHP] Math rounding problem For an arbitrary large number I need to round() it up to the hundreds place if it is not divisible by 100 and