John,
Why does the non-existent key in the array below evaluate to the
first char of the array value?
$foo = '' ;
$foo['one']['two'] = 'test-value' ;
// Evaluates to: string(1) t
var_dump( $foo['one']['two']['three'] ) ;
JH Strings are arrays. PHP probably takes the string 'three' and
On Wed, 25 Aug 2004 14:04:51 +0100, Geoff Caplan [EMAIL PROTECTED] wrote:
I think you are probably right - but this behaviour causes problems.
For example:
$foo['one']['two'] = test-string ;
// Evaluates to TRUE (not what's wanted!)
isset( $foo['one']['two']['three'] ) ;
I need a
From: Geoff Caplan [EMAIL PROTECTED]
Why does the non-existent key in the array below evaluate to the
first char of the array value?
$foo = '' ;
$foo['one']['two'] = 'test-value' ;
// Evaluates to: string(1) t
var_dump( $foo['one']['two']['three'] ) ;
JH Strings are arrays. PHP probably takes the
Geoff Caplan wrote:
I think you are probably right - but this behaviour causes problems.
For example:
$foo['one']['two'] = test-string ;
// Evaluates to TRUE (not what's wanted!)
isset( $foo['one']['two']['three'] ) ;
I need a reliable way to test for the non-existence of a
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