David Harkness wrote:
Casting does not change an object. You must copy the relevant value(s) from
the object returned into a new DateTimePlus. Since DateTime's constructor
takes only a string, and I assume it won't accept your format directly,
unless you implement __toString I believe (not
On Fri, Oct 8, 2010 at 12:50 PM, Nathan Rixham nrix...@gmail.com wrote:
David Harkness wrote:
Casting does not change an object. You must copy the relevant value(s)
from
the object returned into a new DateTimePlus. Since DateTime's constructor
takes only a string, and I assume it won't
Hi,
I'm trying to extends the base class DateTime.
parent::createFromFormat(H.i d.m.Y, $string); returns a DateTime and I
want to convert it into a DateTimePlus (my own extended class). What's the
best way to do this plz ?
Some code:
class DateTimePlus extends DateTime
{
static function
Casting does not change an object. You must copy the relevant value(s) from
the object returned into a new DateTimePlus. Since DateTime's constructor
takes only a string, and I assume it won't accept your format directly,
you're better off converting the string into a Unix timestamp and creating a
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