RE: [PHP] How do I initialize a page to do something ONCE
Jason Wong and Larry Brown, Nevermind, it's working now. Not sure how. I performed the same test many times, but this time when I tried it, it worked. It might be that I manually deleted the older session variables. I did read the notes on php.net for session_unset(), very informative. Thanks to both of you for your help. :) - Nilaab > -Original Message- > From: Larry Brown [mailto:[EMAIL PROTECTED]] > Sent: Friday, November 22, 2002 9:31 AM > To: PHP List; @ Nilaab > Subject: RE: [PHP] How do I initialize a page to do something ONCE > > > Your first post stated.. > > The only problem is that it is not processing the second if block -- > if($start_over == 1) -- unless I actually set start_over=1 in the get > string. > > > > Your second sounds like it is executing the second block... > > >The variable $initialize contains "int(1)", so it does set itself within > the last if statement. > > If the second block is being executed... > > Did you check out php.net and the comments about session_unset()? > > If it is not, are you closing the browser between tests? The session > information stays open even after leaving the site and coming back. > > Larry S. Brown > Dimension Networks, Inc. > (727) 723-8388 > > > > > -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] How do I initialize a page to do something ONCE
Your first post stated.. > The only problem is that it is not processing the second if block -- if($start_over == 1) -- unless I actually set start_over=1 in the get string. > Your second sounds like it is executing the second block... >The variable $initialize contains "int(1)", so it does set itself within the last if statement. If the second block is being executed... Did you check out php.net and the comments about session_unset()? If it is not, are you closing the browser between tests? The session information stays open even after leaving the site and coming back. Larry S. Brown Dimension Networks, Inc. (727) 723-8388 -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] How do I initialize a page to do something ONCE
The variable $initialize contains "int(1)", so it does set itself within the
last if statement. I'm just not sure why it's not unsetting all the sessions
when the page loads.
- Nilaab
> -Original Message-
> From: Jason Wong [mailto:[EMAIL PROTECTED]]
> Sent: Friday, November 22, 2002 2:36 AM
> To: [EMAIL PROTECTED]
> Subject: Re: [PHP] How do I initialize a page to do something ONCE
>
>
> On Friday 22 November 2002 07:26, [EMAIL PROTECTED] wrote:
> > Hello,
> >
> > I have a newbie problem. I have an php page that has many
> layers of forms
> > to it. Once the user is finished with filling out one form and
> sending it,
> > another form appears. This is of course done using simple
> if-else or switch
> > statements. The problem is, how do I initialize a function or any other
> > type of process just ONCE for the entire page. I don't want the
> function or
> > process to run everytime a new form is displayed. Keep in mind that I'm
> > also using sessions for this. Here is a tiny stripped-down
> example, of my
> > failed attempt, that might help you analyze my question:
> >
> > session_start();
> >
> > if(!isset($initialize)) {
> >$start_over = 1;
> > }
>
> > if ($start_over == 1) {
> >$temp_log = $logged_in;
> >session_unset();
> >$logged_in = $temp_log;
> >$initialize = 1;
> >session_register("logged_in", "initialize");
> > }
>
> > There is the code/pseudo-code combination of what I have so
> far. The only
> > problem is that it is not processing the second if block --
> if($start_over
> > == 1) -- unless I actually set start_over=1 in the get string.
> How would I
> > make sure that the page processes everything in that if block only ONCE
> > after the page first loads? Also, if anyone knows a better way of
> > displaying one form after another in on a single php page, I'm
> open to any
> > ideas.
>
> OK, the only reason why the 2nd IF block is not executed is if
> $initialize is
> not empty (ie isset($initialize) is TRUE hence $start_over = 1 is never
> executed). So try:
>
> if(!isset($initialize)) {
> $start_over = 1; }
> else {
>var_dump($initialize); // to see what the it contains
> }
>
>
> --
> Jason Wong -> Gremlins Associates -> www.gremlins.biz
> Open Source Software Systems Integrators
> * Web Design & Hosting * Internet & Intranet Applications Development *
>
> /*
> My BIOLOGICAL ALARM CLOCK just went off ... It has noiseless DOZE
> FUNCTION and full kitchen!!
> */
>
>
> --
> PHP General Mailing List (http://www.php.net/)
> To unsubscribe, visit: http://www.php.net/unsub.php
>
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To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] How do I initialize a page to do something ONCE
On Friday 22 November 2002 07:26, [EMAIL PROTECTED] wrote:
> Hello,
>
> I have a newbie problem. I have an php page that has many layers of forms
> to it. Once the user is finished with filling out one form and sending it,
> another form appears. This is of course done using simple if-else or switch
> statements. The problem is, how do I initialize a function or any other
> type of process just ONCE for the entire page. I don't want the function or
> process to run everytime a new form is displayed. Keep in mind that I'm
> also using sessions for this. Here is a tiny stripped-down example, of my
> failed attempt, that might help you analyze my question:
>
> session_start();
>
> if(!isset($initialize)) {
>$start_over = 1;
> }
> if ($start_over == 1) {
>$temp_log = $logged_in;
>session_unset();
>$logged_in = $temp_log;
>$initialize = 1;
>session_register("logged_in", "initialize");
> }
> There is the code/pseudo-code combination of what I have so far. The only
> problem is that it is not processing the second if block -- if($start_over
> == 1) -- unless I actually set start_over=1 in the get string. How would I
> make sure that the page processes everything in that if block only ONCE
> after the page first loads? Also, if anyone knows a better way of
> displaying one form after another in on a single php page, I'm open to any
> ideas.
OK, the only reason why the 2nd IF block is not executed is if $initialize is
not empty (ie isset($initialize) is TRUE hence $start_over = 1 is never
executed). So try:
if(!isset($initialize)) {
$start_over = 1; }
else {
var_dump($initialize); // to see what the it contains
}
--
Jason Wong -> Gremlins Associates -> www.gremlins.biz
Open Source Software Systems Integrators
* Web Design & Hosting * Internet & Intranet Applications Development *
/*
My BIOLOGICAL ALARM CLOCK just went off ... It has noiseless DOZE
FUNCTION and full kitchen!!
*/
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] How do I initialize a page to do something ONCE
Hello,
I have a newbie problem. I have an php page that has many layers of forms to
it. Once the user is finished with filling out one form and sending it,
another form appears. This is of course done using simple if-else or switch
statements. The problem is, how do I initialize a function or any other type
of process just ONCE for the entire page. I don't want the function or
process to run everytime a new form is displayed. Keep in mind that I'm also
using sessions for this. Here is a tiny stripped-down example, of my failed
attempt, that might help you analyze my question:
session_start();
if(!isset($initialize)) {
$start_over = 1;
}
// There were too many sessions to unregister,
// so I just used the session_unset() function and kept one necessary
session
// which is the login_id that is needed in order for the person to be able
to
// access this page, which they have gotten through authentication earlier:
if ($start_over == 1) {
$temp_log = $logged_in;
session_unset();
$logged_in = $temp_log;
$initialize = 1;
session_register("logged_in", "initialize");
}
if (!$submit1) {
.. Display first form
elseif (!$submit2 && $submit1) {
.. Display second form
elseif (!$submit3 && $submit1 && $submit2) {
.. Display third form
elseif ($submit1 && $submit2 && $submit3) {
.. Add To Database
}
There is the code/pseudo-code combination of what I have so far. The only
problem is that it is not processing the second if block -- if($start_over
== 1) -- unless I actually set start_over=1 in the get string. How would I
make sure that the page processes everything in that if block only ONCE
after the page first loads? Also, if anyone knows a better way of displaying
one form after another in on a single php page, I'm open to any ideas.
Thanks,
- Nilaab
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