[PHP] Logic of conditionals and the ( ) operators
In a nutshell: Will this work? if ($perm == (11 || 12)) Explanation: I am laying the groundwork for a photo viewing system with a private and public mode, and additionally if an admin is logged in, there is an additional level of permission. I came up with a number system to make it easier (and is calcualted by a class) so now, instead of checking against the $mode variable, if the user is logged in, and then what their user level is if they are logged in, I just check against some numbers (the class evaluates all those conditions and assigns the appropriate number a single permission variable, $perm.
Re: [PHP] Logic of conditionals and the ( ) operators
On Fri, 2009-12-18 at 10:21 -0800, Allen McCabe wrote: In a nutshell: Will this work? if ($perm == (11 || 12)) Explanation: I am laying the groundwork for a photo viewing system with a private and public mode, and additionally if an admin is logged in, there is an additional level of permission. I came up with a number system to make it easier (and is calcualted by a class) so now, instead of checking against the $mode variable, if the user is logged in, and then what their user level is if they are logged in, I just check against some numbers (the class evaluates all those conditions and assigns the appropriate number a single permission variable, $perm. That equates to if($perm == true) as 11 in this case translates to true (being a positive integer) The code never needs to figure out the || part, as the first part is true. I think what you'd want to do is possibly: if($perm == 11 || $perm == 12) Thanks, Ash http://www.ashleysheridan.co.uk
Re: [PHP] Logic of conditionals and the ( ) operators (RESOLVED)
Thank you Ashley, it makes perfect sense. I don't know why I didn't just set up some tests like Shiplu suggested! I've rewritten all my code BACK to the correct way. (I thought it looked cooler, oh well). On Fri, Dec 18, 2009 at 10:47 AM, Ashley Sheridan a...@ashleysheridan.co.ukwrote: On Fri, 2009-12-18 at 10:21 -0800, Allen McCabe wrote: In a nutshell: Will this work? if ($perm == (11 || 12)) Explanation: I am laying the groundwork for a photo viewing system with a private and public mode, and additionally if an admin is logged in, there is an additional level of permission. I came up with a number system to make it easier (and is calcualted by a class) so now, instead of checking against the $mode variable, if the user is logged in, and then what their user level is if they are logged in, I just check against some numbers (the class evaluates all those conditions and assigns the appropriate number a single permission variable, $perm. That equates to if($perm == true) as 11 in this case translates to true (being a positive integer) The code never needs to figure out the || part, as the first part is true. I think what you'd want to do is possibly: if($perm == 11 || $perm == 12) Thanks, Ash http://www.ashleysheridan.co.uk
Re: [PHP] Logic of conditionals and the ( ) operators
Hi, Yes, what Ashley said is correct. Also, if you want to avoid writing $perm several times in the if, or if you have a lot of permissions you can do: if (in_array($perm, array(11, 22))) And you can put in that array all the permissions you need to. Regards, Jonathan On Fri, Dec 18, 2009 at 3:47 PM, Ashley Sheridan a...@ashleysheridan.co.uk wrote: On Fri, 2009-12-18 at 10:21 -0800, Allen McCabe wrote: In a nutshell: Will this work? if ($perm == (11 || 12)) Explanation: I am laying the groundwork for a photo viewing system with a private and public mode, and additionally if an admin is logged in, there is an additional level of permission. I came up with a number system to make it easier (and is calcualted by a class) so now, instead of checking against the $mode variable, if the user is logged in, and then what their user level is if they are logged in, I just check against some numbers (the class evaluates all those conditions and assigns the appropriate number a single permission variable, $perm. That equates to if($perm == true) as 11 in this case translates to true (being a positive integer) The code never needs to figure out the || part, as the first part is true. I think what you'd want to do is possibly: if($perm == 11 || $perm == 12) Thanks, Ash http://www.ashleysheridan.co.uk -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
