[PHP] Other Notice problem...

2002-11-08 Thread R B
This is not the same question i asked yesterday.

When i set error_reporting  =  E_ALL and display_errors = On in my php.ini, 
i get the next message:

Notice: Undefined variable: varname in .

How can i fix this problem without setting error_reporting  =  E_ALL  
~E_NOTICE and/or display_errors = Off, or what way do you think is the best 
to resolve this problem?

Thanks,

RB



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Re: [PHP] Other Notice problem...

2002-11-08 Thread Marco Tabini
This usually means that you're using a variable without having
initialized it. For example

$a = $b + 1;

will give you that warning if no value is assigned to $b prior to this
line. It's PHP's way of telling you that you might be doing something
wrong.

Perhaps if you post some of your code we can help better?


Marco

-
php|architect -- The Monthly Magazine For PHP Professionals
Come visit us on the web at http://www.phparch.com!

On Fri, 2002-11-08 at 10:31, R B wrote:
 This is not the same question i asked yesterday.
 
 When i set error_reporting  =  E_ALL and display_errors = On in my php.ini, 
 i get the next message:
 
 Notice: Undefined variable: varname in .
 
 How can i fix this problem without setting error_reporting  =  E_ALL  
 ~E_NOTICE and/or display_errors = Off, or what way do you think is the best 
 to resolve this problem?
 
 Thanks,
 
 RB
 
 
 
 _
 Charla con tus amigos en línea mediante MSN Messenger: 
 http://messenger.microsoft.com/es
 
 
 -- 
 PHP General Mailing List (http://www.php.net/)
 To unsubscribe, visit: http://www.php.net/unsub.php
 



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Re: [PHP] Other Notice problem...

2002-11-08 Thread Ernest E Vogelsinger
At 16:31 08.11.2002, R B spoke out and said:
[snip]
This is not the same question i asked yesterday.

When i set error_reporting  =  E_ALL and display_errors = On in my php.ini, 
i get the next message:

Notice: Undefined variable: varname in .

How can i fix this problem without setting error_reporting  =  E_ALL  
~E_NOTICE and/or display_errors = Off, or what way do you think is the best 
to resolve this problem?
[snip] 

But it's the same answer ;-)
If you want to be completely warning-and-notice-free, you need to define
the variable before accessing it:

// this will give a notice
echo $undefined_var;

// and this won't
$define_var = 'some data, or simply put null here';
echo $defined_var;

The same holds true for array indices:

$test_array = array('One', 'Two', 'Three');

// this will give a notice
echo $test_array[3];

// and this won't
echo $test_array[2];

// and this won't as well
if (array_key_exists(3))
echo $test_array[3];

Get the idea? IMHO it's complete overkill with PHP to predefine variables
since they're auto-initialized with NULL when used first. These notices are
only for the development cycle, to aid us in spotting a problem where you
expect some data to be there, but it aint because the variable name has
been mistyped...


-- 
   O Ernest E. Vogelsinger 
   (\) ICQ #13394035 
^ http://www.vogelsinger.at/



Re: [PHP] Other Notice problem...

2002-11-08 Thread R B
My code is:

?php
 some code.
 
 

 if ($status == ADD) {

   some code ...
   ...
   ...
 }
?
The message is: Notice: Undefined variable: status in 

I'm going to explain how my script work.
I have an php page (addProduct.php) with an input form. I have 2 buttons 
(add and cancel) and a hidden control with name=status. If i press the add 
button, the page submit the form data to the same page (form 
action=addProduct.php) with status hidden control name set to ADD, so the 
if statement its true only if i press the add button.
I see the message when i call the page to add the data not when i submit the 
data.

How can i fix the problem? or there is another best way to do this?



From: Marco Tabini [EMAIL PROTECTED]
To: R B [EMAIL PROTECTED]
CC: [EMAIL PROTECTED]
Subject: Re: [PHP] Other Notice problem...
Date: 08 Nov 2002 10:25:46 -0500

This usually means that you're using a variable without having
initialized it. For example

$a = $b + 1;

will give you that warning if no value is assigned to $b prior to this
line. It's PHP's way of telling you that you might be doing something
wrong.

Perhaps if you post some of your code we can help better?


Marco

-
php|architect -- The Monthly Magazine For PHP Professionals
Come visit us on the web at http://www.phparch.com!

On Fri, 2002-11-08 at 10:31, R B wrote:
 This is not the same question i asked yesterday.

 When i set error_reporting  =  E_ALL and display_errors = On in my 
php.ini,
 i get the next message:

 Notice: Undefined variable: varname in .

 How can i fix this problem without setting error_reporting  =  E_ALL 
 ~E_NOTICE and/or display_errors = Off, or what way do you think is the 
best
 to resolve this problem?

 Thanks,

 RB



 _
 Charla con tus amigos en línea mediante MSN Messenger:
 http://messenger.microsoft.com/es


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Re: [PHP] Other Notice problem...

2002-11-08 Thread Marco Tabini
Try

if (isset ($status)  $status == 'ADD')

instead... this should take care of the error--IF you're sure that the
fact that the $status variable is not set at that point is ok.


Marco

-
php|architect -- The Monthly Magazine For PHP Professionals
Come visit us on the web at http://www.phparch.com!

On Fri, 2002-11-08 at 11:04, R B wrote:
 My code is:
 
 ?php
   some code.
   
   
 
   if ($status == ADD) {
 
 some code ...
 ...
 ...
   }
 ?
 The message is: Notice: Undefined variable: status in 
 
 I'm going to explain how my script work.
 I have an php page (addProduct.php) with an input form. I have 2 buttons 
 (add and cancel) and a hidden control with name=status. If i press the add 
 button, the page submit the form data to the same page (form 
 action=addProduct.php) with status hidden control name set to ADD, so the 
 if statement its true only if i press the add button.
 I see the message when i call the page to add the data not when i submit the 
 data.
 
 How can i fix the problem? or there is another best way to do this?
 
 
 
 From: Marco Tabini [EMAIL PROTECTED]
 To: R B [EMAIL PROTECTED]
 CC: [EMAIL PROTECTED]
 Subject: Re: [PHP] Other Notice problem...
 Date: 08 Nov 2002 10:25:46 -0500
 
 This usually means that you're using a variable without having
 initialized it. For example
 
 $a = $b + 1;
 
 will give you that warning if no value is assigned to $b prior to this
 line. It's PHP's way of telling you that you might be doing something
 wrong.
 
 Perhaps if you post some of your code we can help better?
 
 
 Marco
 
 -
 php|architect -- The Monthly Magazine For PHP Professionals
 Come visit us on the web at http://www.phparch.com!
 
 On Fri, 2002-11-08 at 10:31, R B wrote:
   This is not the same question i asked yesterday.
  
   When i set error_reporting  =  E_ALL and display_errors = On in my 
 php.ini,
   i get the next message:
  
   Notice: Undefined variable: varname in .
  
   How can i fix this problem without setting error_reporting  =  E_ALL 
   ~E_NOTICE and/or display_errors = Off, or what way do you think is the 
 best
   to resolve this problem?
  
   Thanks,
  
   RB
  
  
  
   _
   Charla con tus amigos en línea mediante MSN Messenger:
   http://messenger.microsoft.com/es
  
  
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   To unsubscribe, visit: http://www.php.net/unsub.php
  
 
 
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Re: [PHP] Other Notice problem...

2002-11-08 Thread Ernest E Vogelsinger
At 17:04 08.11.2002, R B spoke out and said:
[snip]
I'm going to explain how my script work.
I have an php page (addProduct.php) with an input form. I have 2 buttons 
(add and cancel) and a hidden control with name=status. If i press the add 
button, the page submit the form data to the same page (form 
action=addProduct.php) with status hidden control name set to ADD, so the 
if statement its true only if i press the add button.
I see the message when i call the page to add the data not when i submit the 
data.
[snip] 

Ahhh your $status variable should be a form variable? Well, as pointed
out many times the last days, register_globals is OFF by default since PHP
v.4.something. Either turn register_globals on in your PHP.ini (bad and
deprecated, read the security bulletins), or you refer to the _POST array:

if ($_POST['status'] == ADD)

if the data is not set (the status control empty), you'll still get a
notice about an undefined array index, so you might

if (array_key_exists('status', $_POST)) {
switch ($_POST['status']) {
case 'ADD':
break;
default:
echo 'Unsupported status!';
}
}
else echo 'No status sent!';



-- 
   O Ernest E. Vogelsinger 
   (\) ICQ #13394035 
^ http://www.vogelsinger.at/



Re: [PHP] Other Notice problem...

2002-11-08 Thread R B
The array_key_exists or isset is a good solution.
About your comment, i have the register_globals=on.
I have 2 questions:

1.- What's the relation to have register_globals=off with this notice 
message?

2.- I read the security comment about register_globals=on in the php.ini, 
but i set to on because if i set to off, i can't pass GET variables to other 
page. how can you pass GET variables to other page without setting 
register_globals=on?



From: Ernest E Vogelsinger [EMAIL PROTECTED]
To: R B [EMAIL PROTECTED]
CC: [EMAIL PROTECTED],[EMAIL PROTECTED]
Subject: Re: [PHP] Other Notice problem...
Date: Fri, 08 Nov 2002 17:14:30 +0100

At 17:04 08.11.2002, R B spoke out and said:
[snip]
I'm going to explain how my script work.
I have an php page (addProduct.php) with an input form. I have 2 buttons
(add and cancel) and a hidden control with name=status. If i press the 
add
button, the page submit the form data to the same page (form
action=addProduct.php) with status hidden control name set to ADD, so 
the
if statement its true only if i press the add button.
I see the message when i call the page to add the data not when i submit 
the
data.
[snip]

Ahhh your $status variable should be a form variable? Well, as pointed
out many times the last days, register_globals is OFF by default since PHP
v.4.something. Either turn register_globals on in your PHP.ini (bad and
deprecated, read the security bulletins), or you refer to the _POST array:

if ($_POST['status'] == ADD)

if the data is not set (the status control empty), you'll still get a
notice about an undefined array index, so you might

if (array_key_exists('status', $_POST)) {
switch ($_POST['status']) {
case 'ADD':
break;
default:
echo 'Unsupported status!';
}
}
else echo 'No status sent!';



--
   O Ernest E. Vogelsinger
   (\) ICQ #13394035
^ http://www.vogelsinger.at/


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Re: [PHP] Other Notice problem...

2002-11-08 Thread Ernest E Vogelsinger
At 17:27 08.11.2002, R B spoke out and said:
[snip]
The array_key_exists or isset is a good solution.
About your comment, i have the register_globals=on.
I have 2 questions:

1.- What's the relation to have register_globals=off with this notice 
message?

If register_globals is OFF, $status will simply not be set by PHP. You can
always access it as $_POST['status'] or $_REQUEST['status'].

2.- I read the security comment about register_globals=on in the php.ini, 
but i set to on because if i set to off, i can't pass GET variables to other 
page. how can you pass GET variables to other page without setting 
register_globals=on?

What do you mean by pass it on to other page? I'm afraid I don't get you.
What are you trying to accomplish?


-- 
   O Ernest E. Vogelsinger 
   (\) ICQ #13394035 
^ http://www.vogelsinger.at/



Re: [PHP] Other Notice problem...

2002-11-08 Thread R B
About your comment 1:

if i have register_globals=on, why $status is not be set by PHP?

About your comment 2:

if i have 2 pages: p01.php and p02.php,
with p01.php code:
...
...
a href=p02.php?pp=2link/a
...
...

and p02.php code:
...
...
echo $pp;
...
...

If i have register_globals=off, then when i click the link, in p02.php page, 
the echo command display nothing.
If i have register_globals=on, then the echo command displays the value buy 
this way is deprecated.
How can i run the script without problems having register_globals=off?

Thanks,

RB




From: Ernest E Vogelsinger [EMAIL PROTECTED]
To: R B [EMAIL PROTECTED]
CC: [EMAIL PROTECTED],[EMAIL PROTECTED]
Subject: Re: [PHP] Other Notice problem...
Date: Fri, 08 Nov 2002 17:31:25 +0100

At 17:27 08.11.2002, R B spoke out and said:
[snip]
The array_key_exists or isset is a good solution.
About your comment, i have the register_globals=on.
I have 2 questions:

1.- What's the relation to have register_globals=off with this notice
message?

If register_globals is OFF, $status will simply not be set by PHP. You can
always access it as $_POST['status'] or $_REQUEST['status'].

2.- I read the security comment about register_globals=on in the php.ini,
but i set to on because if i set to off, i can't pass GET variables to 
other
page. how can you pass GET variables to other page without setting
register_globals=on?

What do you mean by pass it on to other page? I'm afraid I don't get you.
What are you trying to accomplish?


--
   O Ernest E. Vogelsinger
   (\) ICQ #13394035
^ http://www.vogelsinger.at/


_
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Re: [PHP] Other Notice problem...

2002-11-08 Thread Stuart
On Friday, Nov 8, 2002, at 16:44 Europe/London, R B wrote:

if i have 2 pages: p01.php and p02.php,
with p01.php code:
...
...
a href=p02.php?pp=2link/a
...
...

and p02.php code:
...
...
echo $pp;
...
...

If i have register_globals=off, then when i click the link, in p02.php 
page, the echo command display nothing.
If i have register_globals=on, then the echo command displays the 
value buy this way is deprecated.
How can i run the script without problems having register_globals=off?

p02.php code:
...
...
echo $_GET['pp'];
...
...

--
Stuart


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Re: [PHP] Other Notice problem...

2002-11-08 Thread R B
And without using the $_GET[] array.




From: Stuart [EMAIL PROTECTED]
To: R B [EMAIL PROTECTED]
CC: [EMAIL PROTECTED], [EMAIL PROTECTED], [EMAIL PROTECTED]
Subject: Re: [PHP] Other Notice problem...
Date: Fri, 8 Nov 2002 16:52:50 +

On Friday, Nov 8, 2002, at 16:44 Europe/London, R B wrote:

if i have 2 pages: p01.php and p02.php,
with p01.php code:
...
...
a href=p02.php?pp=2link/a
...
...

and p02.php code:
...
...
echo $pp;
...
...

If i have register_globals=off, then when i click the link, in p02.php 
page, the echo command display nothing.
If i have register_globals=on, then the echo command displays the value 
buy this way is deprecated.
How can i run the script without problems having register_globals=off?

p02.php code:
...
...
echo $_GET['pp'];
...
...

--
Stuart



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Re: [PHP] Other Notice problem...

2002-11-08 Thread Stuart
On Friday, Nov 8, 2002, at 16:56 Europe/London, R B wrote:

And without using the $_GET[] array.


Why don't you want to use the $_GET array? If you really don't want to 
use it you can use the extract function but if you're going to do that 
you might as well have register_globals on.

--
Stuart

p02.php code:
...
...
echo $_GET['pp'];
...
...

--
Stuart



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Re: [PHP] Other Notice problem...

2002-11-08 Thread Ernest E Vogelsinger
At 17:44 08.11.2002, R B spoke out and said:
[snip]
About your comment 1:

if i have register_globals=on, why $status is not be set by PHP?

well _then_ we have 2 possibilities:
1) your form input field isn't named status but rather Status or
STATUS - take care of the case here, PHP is case sensitive with variables
and associative indices.
2) Your form simply submits _nothing_ in this field - check your JavaScript
(perhaps it is disabled?)

About your comment 2:

if i have 2 pages: p01.php and p02.php,
with p01.php code:
...
a href=p02.php?pp=2link/a
...

and p02.php code:
...
echo $pp;

If i have register_globals=off, then when i click the link, in p02.php page, 
the echo command display nothing.
If i have register_globals=on, then the echo command displays the value buy 
this way is deprecated.
How can i run the script without problems having register_globals=off?

?php
$parms = null;
foreach ($_GET as $p=$v) {
   if ($parms) $parms .= '';
   $parms .= $p=.urlencode($v);
}
?
...
a href=p02.php??php=$parms?

This will do what you want (untested, but should work)


-- 
   O Ernest E. Vogelsinger 
   (\) ICQ #13394035 
^ http://www.vogelsinger.at/



Re: [PHP] Other Notice problem...

2002-11-08 Thread Jason Wong
On Saturday 09 November 2002 00:52, Stuart wrote:
  How can i run the script without problems having register_globals=off?

 p02.php code:
 ...
 ...
 echo $_GET['pp'];
 ...
 ...

Yes. And try reading the manual, or the archives.

-- 
Jason Wong - Gremlins Associates - www.gremlins.com.hk
Open Source Software Systems Integrators
* Web Design  Hosting * Internet  Intranet Applications Development *

/*
While money can't buy happiness, it certainly lets you choose your own
form of misery.
*/


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Re: [PHP] Other Notice problem...

2002-11-08 Thread Jason Wong
On Saturday 09 November 2002 00:56, R B wrote:
 And without using the $_GET[] array.

Probably by using black magic instead -- or maybe use $_REQUEST, but I don't 
think you want to use that either :)

-- 
Jason Wong - Gremlins Associates - www.gremlins.com.hk
Open Source Software Systems Integrators
* Web Design  Hosting * Internet  Intranet Applications Development *

/*
Auribus teneo lupum.
[I hold a wolf by the ears.]
[Boy, it *sounds* good.  But what does it *mean*?]
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Re: [PHP] Other Notice problem...

2002-11-08 Thread Marco Tabini
Well, it's possible he's using an older version of PHP in which
superglobals did not yet exist.


Marco

-
php|architect -- The Monthly Magazine For PHP Professionals
Come visit us on the web at http://www.phparch.com!

On Fri, 2002-11-08 at 12:09, Jason Wong wrote:
 On Saturday 09 November 2002 00:56, R B wrote:
  And without using the $_GET[] array.
 
 Probably by using black magic instead -- or maybe use $_REQUEST, but I don't 
 think you want to use that either :)
 
 -- 
 Jason Wong - Gremlins Associates - www.gremlins.com.hk
 Open Source Software Systems Integrators
 * Web Design  Hosting * Internet  Intranet Applications Development *
 
 /*
 Auribus teneo lupum.
   [I hold a wolf by the ears.]
   [Boy, it *sounds* good.  But what does it *mean*?]
 */
 
 
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Re: [PHP] Other Notice problem...

2002-11-08 Thread Jason Wong
On Saturday 09 November 2002 01:02, Marco Tabini wrote:
 Well, it's possible he's using an older version of PHP in which
 superglobals did not yet exist.

It looks to me as if he just wants to use plain $variable but with 
register_globals disabled that's just not possible. 

Unless you go through that extract($_POST) ritual, all of which is covered in 
the manual and archives.

-- 
Jason Wong - Gremlins Associates - www.gremlins.com.hk
Open Source Software Systems Integrators
* Web Design  Hosting * Internet  Intranet Applications Development *

/*
The biggest problem with communication is the illusion that it has occurred.
*/


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Re: [PHP] Other Notice problem...

2002-11-08 Thread R B
It's ok. I understand that i can't use plain variables with 
register_globals=on, but this is only for GET variables or to all variables?

Thanks,

RB



From: Jason Wong [EMAIL PROTECTED]
Reply-To: [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Subject: Re: [PHP] Other Notice problem...
Date: Sat, 9 Nov 2002 01:42:56 +0800

On Saturday 09 November 2002 01:02, Marco Tabini wrote:
 Well, it's possible he's using an older version of PHP in which
 superglobals did not yet exist.

It looks to me as if he just wants to use plain $variable but with
register_globals disabled that's just not possible.

Unless you go through that extract($_POST) ritual, all of which is covered 
in
the manual and archives.

--
Jason Wong - Gremlins Associates - www.gremlins.com.hk
Open Source Software Systems Integrators
* Web Design  Hosting * Internet  Intranet Applications Development *

/*
The biggest problem with communication is the illusion that it has 
occurred.
*/


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Re: [PHP] Other Notice problem...

2002-11-08 Thread Stuart
On Friday, Nov 8, 2002, at 17:59 Europe/London, R B wrote:

It's ok. I understand that i can't use plain variables with 
register_globals=on, but this is only for GET variables or to all 
variables?

The value of register_globals only affects the CGI variables (get, 
post, server, cookies, etc). You can use other variables in the same 
way as you ever did.

--
Stuart


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