[PHP] Parse Error(newbie)
I get a parse error on this line $query = "SELECT * FROM news ORDER BY id DESC LIMIT 1"; I believe that it is an error in the SQL statement Thanks in advance JJ Harrison[EMAIL PROTECTED]www.tececo.com -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Parse Error(newbie)
Look for errors in the line above this one. PHP doesn't know what SQL is...it's just a string to PHP. ---John Holmes... - Original Message - From: [EMAIL PROTECTED] To: [EMAIL PROTECTED] Sent: Wednesday, May 29, 2002 9:03 AM Subject: [PHP] Parse Error(newbie) I get a parse error on this line $query = SELECT * FROM news ORDER BY id DESC LIMIT 1; I believe that it is an error in the SQL statement Thanks in advance JJ Harrison [EMAIL PROTECTED] www.tececo.com -- -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Parse Error(newbie)
[EMAIL PROTECTED] wrote: $query = SELECT * FROM news ORDER BY id DESC LIMIT 1; I believe that it is an error in the SQL statement Nope, looks fine. Show us the previous few lines, the error is probably in those somewhere. -- Stuart -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Parse Error(newbie)
-BEGIN PGP SIGNED MESSAGE- Hash: SHA1 * and then [EMAIL PROTECTED] declared I get a parse error on this line $query = SELECT * FROM news ORDER BY id DESC LIMIT 1; I believe that it is an error in the SQL statement Nothing wrong with that. Let's have the whole error msg and the code surrouding the line it says it's on please It might well not be on that line at all. - -- Nick Wilson // www.tioka.com -BEGIN PGP SIGNATURE- Version: GnuPG v1.0.6 (GNU/Linux) iD8DBQE89NLaHpvrrTa6L5oRAiZ0AJ9fXPhupt203ghx8nNnDkgrtkgpsgCfQRFO tpYkUeHN5k9+EZxGuZbP34k= =QCuq -END PGP SIGNATURE- -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Parse Error(newbie)
Here is the function:
function print_new_story(){
$query = SELECT * FROM news ORDER BY id DESC LIMIT 1;
$result = mysql_query($query);
$num_results = mysql_num_rows($result);
for ($i=0; $i $num_results; $i++)
{
$row = mysql_fetch_array($result);
echo 'h2a href=#: ';
echo $row['title'];
if(!$row['date'] == 0){
echo ' - ';
echo date(d-M-y, $row['date']);
}
echo ' :/a/h2br';
include $row['int_location'];
}
}
and here is the error message:
Parse error: parse error in \\johnh\c\co2 busters\includes\functions.php on
line 81
- Original Message -
From: Nick Wilson [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Wednesday, May 29, 2002 11:08 PM
Subject: Re: [PHP] Parse Error(newbie)
-BEGIN PGP SIGNED MESSAGE-
Hash: SHA1
* and then [EMAIL PROTECTED] declared
I get a parse error on this line
$query = SELECT * FROM news ORDER BY id DESC LIMIT 1;
I believe that it is an error in the SQL statement
Nothing wrong with that. Let's have the whole error msg and the code
surrouding the line it says it's on please It might well not be on
that line at all.
- --
Nick Wilson // www.tioka.com
-BEGIN PGP SIGNATURE-
Version: GnuPG v1.0.6 (GNU/Linux)
iD8DBQE89NLaHpvrrTa6L5oRAiZ0AJ9fXPhupt203ghx8nNnDkgrtkgpsgCfQRFO
tpYkUeHN5k9+EZxGuZbP34k=
=QCuq
-END PGP SIGNATURE-
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Re: [PHP] Parse Error(newbie)
On Wednesday 29 May 2002 21:13, [EMAIL PROTECTED] wrote:
Here is the function:
function print_new_story(){
$query = SELECT * FROM news ORDER BY id DESC LIMIT 1;
$result = mysql_query($query);
$num_results = mysql_num_rows($result);
for ($i=0; $i $num_results; $i++)
{
$row = mysql_fetch_array($result);
echo 'h2a href=#: ';
echo $row['title'];
if(!$row['date'] == 0){
echo ' - ';
echo date(d-M-y, $row['date']);
}
echo ' :/a/h2br';
include $row['int_location'];
}
}
and here is the error message:
Parse error: parse error in \\johnh\c\co2 busters\includes\functions.php on
line 81
We're not mind readers, which is line 81?
--
Jason Wong - Gremlins Associates - www.gremlins.com.hk
Open Source Software Systems Integrators
* Web Design Hosting * Internet Intranet Applications Development *
/*
Would it help if I got out and pushed?
-- Princess Leia Organa
*/
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Re: [PHP] Parse Error(newbie)
Line 81 is $query.
I showed it in my first email.
I suspect this line is the one causing the trouble(It is about four lines
above the start of the function and is the only previous PHP statement)
mysql_query(delete from conf_event where time ( time() );
- Original Message -
From: Jason Wong [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Wednesday, May 29, 2002 11:11 PM
Subject: Re: [PHP] Parse Error(newbie)
On Wednesday 29 May 2002 21:13, [EMAIL PROTECTED] wrote:
Here is the function:
function print_new_story(){
$query = SELECT * FROM news ORDER BY id DESC LIMIT 1;
$result = mysql_query($query);
$num_results = mysql_num_rows($result);
for ($i=0; $i $num_results; $i++)
{
$row = mysql_fetch_array($result);
echo 'h2a href=#: ';
echo $row['title'];
if(!$row['date'] == 0){
echo ' - ';
echo date(d-M-y, $row['date']);
}
echo ' :/a/h2br';
include $row['int_location'];
}
}
and here is the error message:
Parse error: parse error in \\johnh\c\co2 busters\includes\functions.php
on
line 81
We're not mind readers, which is line 81?
--
Jason Wong - Gremlins Associates - www.gremlins.com.hk
Open Source Software Systems Integrators
* Web Design Hosting * Internet Intranet Applications Development *
/*
Would it help if I got out and pushed?
-- Princess Leia Organa
*/
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RE: [PHP] Parse Error(newbie)
mysql_query(delete from conf_event where time ( time() );
You're missing the ending there.
Niklas
-Original Message-
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]]
Sent: 29. toukokuuta 2002 16:20
To: [EMAIL PROTECTED]
Subject: Re: [PHP] Parse Error(newbie)
Line 81 is $query.
I showed it in my first email.
I suspect this line is the one causing the trouble(It is about four
lines above the start of the function and is the only previous PHP
statement) mysql_query(delete from conf_event where time ( time() );
- Original Message -
From: Jason Wong [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Wednesday, May 29, 2002 11:11 PM
Subject: Re: [PHP] Parse Error(newbie)
On Wednesday 29 May 2002 21:13, [EMAIL PROTECTED] wrote:
Here is the function:
function print_new_story(){
$query = SELECT * FROM news ORDER BY id DESC LIMIT 1; $result =
mysql_query($query); $num_results = mysql_num_rows($result);
for ($i=0; $i $num_results; $i++)
{
$row = mysql_fetch_array($result);
echo 'h2a href=#: ';
echo $row['title'];
if(!$row['date'] == 0){
echo ' - ';
echo date(d-M-y, $row['date']);
}
echo ' :/a/h2br';
include $row['int_location'];
}
}
and here is the error message:
Parse error: parse error in \\johnh\c\co2
busters\includes\functions.php
on
line 81
We're not mind readers, which is line 81?
--
Jason Wong - Gremlins Associates - www.gremlins.com.hk
Open Source Software Systems Integrators
* Web Design Hosting * Internet Intranet Applications Development
*
/*
Would it help if I got out and pushed?
-- Princess Leia Organa
*/
--
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Re: [PHP] Parse Error(newbie)
On Wednesday 29 May 2002 21:22, Niklas Lampén wrote: mysql_query(delete from conf_event where time ( time() ); You're missing the ending there. Niklas -Original Message- From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]] Sent: 29. toukokuuta 2002 16:20 To: [EMAIL PROTECTED] Subject: Re: [PHP] Parse Error(newbie) Line 81 is $query. I showed it in my first email. I suspect this line is the one causing the trouble(It is about four lines above the start of the function and is the only previous PHP statement) mysql_query(delete from conf_event where time ( time() ); It is cases like these where an editor with /decent/ syntax highlighting is invaluable. -- Jason Wong - Gremlins Associates - www.gremlins.com.hk Open Source Software Systems Integrators * Web Design Hosting * Internet Intranet Applications Development * /* A man is like a rusty wheel on a rusty cart, He sings his song as he rattles along and then he falls apart. -- Richard Thompson */ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Parse Error(newbie)
Notepad at the moment as I can't change the settings of my computer due to lack of privilages - Original Message - From: Jason Wong [EMAIL PROTECTED] To: [EMAIL PROTECTED] Sent: Wednesday, May 29, 2002 11:26 PM Subject: Re: [PHP] Parse Error(newbie) On Wednesday 29 May 2002 21:22, Niklas Lampén wrote: mysql_query(delete from conf_event where time ( time() ); You're missing the ending there. Niklas -Original Message- From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]] Sent: 29. toukokuuta 2002 16:20 To: [EMAIL PROTECTED] Subject: Re: [PHP] Parse Error(newbie) Line 81 is $query. I showed it in my first email. I suspect this line is the one causing the trouble(It is about four lines above the start of the function and is the only previous PHP statement) mysql_query(delete from conf_event where time ( time() ); It is cases like these where an editor with /decent/ syntax highlighting is invaluable. -- Jason Wong - Gremlins Associates - www.gremlins.com.hk Open Source Software Systems Integrators * Web Design Hosting * Internet Intranet Applications Development * /* A man is like a rusty wheel on a rusty cart, He sings his song as he rattles along and then he falls apart. -- Richard Thompson */ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Parse Error(newbie)
On Wednesday 29 May 2002 21:45, [EMAIL PROTECTED] wrote: Notepad at the moment as I can't change the settings of my computer due to lack of privilages You have my sympathy :) -- Jason Wong - Gremlins Associates - www.gremlins.com.hk Open Source Software Systems Integrators * Web Design Hosting * Internet Intranet Applications Development * /* Take heart amid the deepening gloom that your dog is finally getting enough cheese. -- National Lampoon, Deteriorata */ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Parse Error(Newbie)
On Mon, 27 May 2002 [EMAIL PROTECTED] wrote:
I know it is probably something obvious but the following gives me a
parse error and as a newbie I am having trouble locating it.
$query = select * from news WHERE id = $_get['id'];
A lot of people have answered this already, but just for a little more
clarification, consider this:
The reason the computer requires you to surround a string with quotes is
so that it knows where the string begins and ends.
If you put quotes in the middle of the string, it thinks those mark the
end; why would it think otherwise, since that's what quotes are for.
So people have provided you with various solutions for this. Each of them
involve in some way indicating more specifically what's going on. Either
you use a different kind of quotes (if you started the string with single
quotes, it will let you put double quotes inside it without getting
confused, and vice versa), or you use the backslash character before
internal quotes. Backslash is the escape character which in this case
tells the parser to ignore the special meaning of the quote that follows.
So your line could have been written in any of the following ways:
$query = select * from news WHERE id = '{$_get['id']}';
$query = select * from news WHERE id = \{$_get['id']}\;
$query = 'select * from news WHERE id = ' . $_get['id'] . '';
miguel
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RE: [PHP] Parse Error(Newbie)
Also note that variables are case sensitive in PHP. So $_get and $_GET
are not the same. If you're using the new super-global variables on
PHP, then you need to use $_GET['id']...
---John Holmes...
-Original Message-
From: Miguel Cruz [mailto:[EMAIL PROTECTED]]
Sent: Monday, May 27, 2002 2:18 AM
To: [EMAIL PROTECTED]
Cc: [EMAIL PROTECTED]
Subject: Re: [PHP] Parse Error(Newbie)
On Mon, 27 May 2002 [EMAIL PROTECTED] wrote:
I know it is probably something obvious but the following gives me a
parse error and as a newbie I am having trouble locating it.
$query = select * from news WHERE id = $_get['id'];
A lot of people have answered this already, but just for a little more
clarification, consider this:
The reason the computer requires you to surround a string with quotes
is
so that it knows where the string begins and ends.
If you put quotes in the middle of the string, it thinks those mark
the
end; why would it think otherwise, since that's what quotes are for.
So people have provided you with various solutions for this. Each of
them
involve in some way indicating more specifically what's going on.
Either
you use a different kind of quotes (if you started the string with
single
quotes, it will let you put double quotes inside it without getting
confused, and vice versa), or you use the backslash character before
internal quotes. Backslash is the escape character which in this
case
tells the parser to ignore the special meaning of the quote that
follows.
So your line could have been written in any of the following ways:
$query = select * from news WHERE id = '{$_get['id']}';
$query = select * from news WHERE id = \{$_get['id']}\;
$query = 'select * from news WHERE id = ' . $_get['id'] . '';
miguel
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Re: [PHP] Parse Error(Newbie)
try this: $query = select * from news WHERE id = '$_get['id']'; the double quote right before the $ is ending the string, from that point on everything is an error. Matt On Mon, 27 May 2002 [EMAIL PROTECTED] wrote: I know it is probably something obvious but the following gives me a parse error and as a newbie I am having trouble locating it. $query = select * from news WHERE id = $_get['id']; JJ Harrison [EMAIL PROTECTED] www.tececo.com -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Parse Error(Newbie)
Another thing you may want to try is the following line: $query = select * from news WHERE id = ' . $_get['id'] . '; Matt On Mon, 27 May 2002 [EMAIL PROTECTED] wrote: I know it is probably something obvious but the following gives me a parse error and as a newbie I am having trouble locating it. $query = select * from news WHERE id = $_get['id']; JJ Harrison [EMAIL PROTECTED] www.tececo.com -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Parse Error(Newbie)
I know it is probably something obvious but the following gives me a parse error and as a newbie I am having trouble locating it. $query = "select * from news WHERE id = "$_get['id']""; JJ Harrison[EMAIL PROTECTED]www.tececo.com -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] Parse Error(Newbie)
$query = select * from news WHERE id = $_get['id']; you've got quotes within quotes - either change the inner quotes to single quotes, or escape them $query = select * from news WHERE id = '$_get[id]'; or $query = select * from news WHERE id = \$_get['id']\; -Original Message- From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]] Sent: Monday, May 27, 2002 3:47 PM To: [EMAIL PROTECTED] Subject: [PHP] Parse Error(Newbie) I know it is probably something obvious but the following gives me a parse error and as a newbie I am having trouble locating it. $query = select * from news WHERE id = $_get['id']; JJ Harrison [EMAIL PROTECTED] mailto:[EMAIL PROTECTED] www.tececo.com http://www.tececo.com
RE: [PHP] Parse Error(Newbie)
can you show us the lines above that line? say the previous 2 lines?.. also depending on what server your on you might want to try $query = SELECT * FROM news WHERE id = $_get['id']; but that line is ok ... with parse errors it's often, well i've found this any way, that it's the line above the line the message says it is.. -Original Message- From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]] Sent: Monday, 27 May 2002 3:47 PM To: [EMAIL PROTECTED] Subject: [PHP] Parse Error(Newbie) I know it is probably something obvious but the following gives me a parse error and as a newbie I am having trouble locating it. $query = select * from news WHERE id = $_get['id']; JJ Harrison [EMAIL PROTECTED] www.tececo.com
RE: [PHP] Parse Error(Newbie)
-Original Message- I know it is probably something obvious but the following gives me a parse error and as a newbie I am having trouble locating it. $query = select * from news WHERE id = $_get['id']; -Original Message- Any time you end up with two characters together is a pretty good indication of where you problem is. You might try this: $query = SELECT * FROM news WHERE ID = ' . $_get['id'] . '; Alternately, and depending on what you're doing and why, it might be more effective to do this: $idstring = $_get['id']; $query = SELECT * FROM news WHERE ID = '$idstring'; Your choice... CYA, Dave -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Parse Error(Newbie)
-BEGIN PGP SIGNED MESSAGE-
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* and then [EMAIL PROTECTED] declared
I get a parse error on line 114 can anyone see the problem?
Sorry if it is something obvious :}
for ($i=0; $i $num_results; $i++)
110. {
111. $row = mysql_fetch_array($result);
112. echo 'a href=';
113. echo $row['url'];
114. echo '';
Have you tried escaping the double quotes?
echo '\';
- --
Nick Wilson // www.explodingnet.com
-BEGIN PGP SIGNATURE-
Version: GnuPG v1.0.6 (GNU/Linux)
iD8DBQE87NI7HpvrrTa6L5oRAox5AJwJ5alFlqn0VtSTdLWKiQNVoKvZtQCgsEhj
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=LknC
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RE: [PHP] Parse Error(Newbie)
why now just write:
for ($i=0; $i $num_results; $i++) {
$row = mysql_fetch_array($result);
echo a href=\.$row['url'].\link text/a;
-Original Message-
From: Nick Wilson [mailto:[EMAIL PROTECTED]]
Sent: 23 May 2002 12:28 PM
To: [EMAIL PROTECTED]
Subject: Re: [PHP] Parse Error(Newbie)
-BEGIN PGP SIGNED MESSAGE-
Hash: SHA1
* and then [EMAIL PROTECTED] declared
I get a parse error on line 114 can anyone see the problem?
Sorry if it is something obvious :}
for ($i=0; $i $num_results; $i++)
110. {
111. $row = mysql_fetch_array($result);
112. echo 'a href=';
113. echo $row['url'];
114. echo '';
Have you tried escaping the double quotes?
echo '\';
- --
Nick Wilson // www.explodingnet.com
-BEGIN PGP SIGNATURE-
Version: GnuPG v1.0.6 (GNU/Linux)
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Umv5vrmmT8J0dDGSehyv5CU=
=LknC
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Re: [PHP] Parse Error(Newbie)
On jeudi, mai 23, 2002, at 01:27 , Nick Wilson wrote:
I get a parse error on line 114 can anyone see the problem?
Sorry if it is something obvious :}
for ($i=0; $i $num_results; $i++)
110. {
111. $row = mysql_fetch_array($result);
112. echo 'a href=';
113. echo $row['url'];
114. echo '';
Have you tried escaping the double quotes?
echo '\';
No !
echo '\';
will print :
\
Your line 114 is good
I don't see the problem but why not code like this :
while ($row = mysql_fetch_array($result, MYSQL_ASSOC)) {
echo 'A HREF=' . $row['url'] . ''.$row['site'].'/A';
}
If you don't see where is your problem, try to comment some
lines. Start with line 114... and execute your script to see
what happened.
R.
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