First this is not a 2d array it is a single d array each element of which is
another array.
If you search the array for a value you won't find it as each element is an
array.
$layerDes[1][0] is not an element of $layerDes it is an element of the array
$layerDes[1].
As far as I know there is no built in way to search down this tree. I think
you'll need
To walk the array and check the first element of each e.g.
Foreach($layerDes as $count=>$array)
{ if ($array[0] == $searchstring)
{ $key = $count;
break;
}
}
Tim Ward
www.chessish.com <http://www.chessish.com>
----------
From: Pushkar Pradhan [SMTP:[EMAIL PROTECTED]]
Sent: 14 May 2002 19:51
To: [EMAIL PROTECTED]
Subject: array_search in 2-d arrays
I've a 2 D array and would like to search for vals. in the first
dimension
only i.e.
myArray[0][0]
myArray[1][0]
myArray[2][0]
myArray[3][0]
.
.
.
and not in the elements myArray[0][1]....
CODE:
for($l = 0; $l < count($layer); $l++) {
$key = array_search($layer[$l], $layerDes); // $layerDes is 2-D
$layer[$l] = $layerNames[$key];
}
My $key is undefined after execution, is it because the elements are
in
$layerDes[i][0]?
Using $key === also didn't help? Any ideas, thanks.
-Pushkar S. Pradhan
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
