Something like this...? if( $n % 100 != 0 ) { $n += 100 - ($n % 100); }
Although I don't think your example is any messier... maybe ceil/floor should have a precision field added... -philip On Fri, 8 Feb 2002, Charlie Killian wrote: > For an arbitrary large number I need to round() it up to the hundreds place > if it is not divisible by 100 and leave it untouched if it is. > > So 1100 would round to 1100 and > 1101 would round to 1200. > > Is there a clean way to do this? > > Currently I'm: > $scale = round($scale+49, -2); // round up to hundreds. > > But this is messy. > > Charlie > > > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php > -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php