[PHP] Re: Replacing datafile with array
works like a charm
just initializet the $retVal function...
$retVal = array();
rest of script here
Daniel alsén [EMAIL PROTECTED] wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
Hi,
i am trying to replace a datafile wich contains the contents of a
directory
with an array.
I am reading the directory and am trying to pass the value to an array.
What
am i doing wrong? Shouldn´t $retVal contain the direcory info?
Also, is there a way to use the content of an array without getting the
word
'Array' at the start?
$handle=opendir('.');
while (false !== ($file = readdir($handle)))
if ($file != . $file != .. ereg(.jpg,$file)) {
$retVal[count($retVal)] = $file;
}
# Daniel Alsén| www.mindbash.com #
# [EMAIL PROTECTED] | +46 704 86 14 92 #
# ICQ: 63006462 | #
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RE: [PHP] Re: Replacing datafile with array
Hmm...
it still doesn´t work.
If i echo $retVal i just get the word 'Array' (the same number of times that
the number of files in the directory).
If i echo $file i get the file listing...however, it doesn´t pass on the
content to the rest of my script.
Maybe someone could help me out with the whole script? I downloaded this
from some script archive and it works if i use the list.photos datafile. But
i don´t want to change that file every time a new photo is uploaded.
I am trying to read the directory and use the directory handle listing
instead.
If anyone wants to help me out making this databasedriven instead youre very
welcome :)
?PHP
$retVal = array ();
//Load Directory Into Array
$handle=opendir('.');
while (false !== ($file = readdir($handle)))
if ($file != . $file != .. ereg(.jpg,$file)) {
$retVal [count($retVal)] = $file;
echo $retVal br\n;
}
//initialize variables
//$data_file = list.photos;
$thumbnail_dir = thumbs/;
$num_rows = 3;
$photos_per_row = 3;
$photos = file($retVal); //$retVal used to be $data_file
$total_photos = sizeof($photos);
$photos_per_page = $num_rows * $photos_per_row;
//check to see if the start variable exists in the URL.
//If not, then the user is on the first page - set start to 0
if(!isSet($start)){
$start = 0;
}
//init i to where it needs to start in the photos array
$i = $start;
$prev_start = $start - $photos_per_page;
$next_start = $start + $photos_per_page;
for ($row=0; $row $num_rows; $row++){
print(tr\n);
for ($col=0; $col $photos_per_row; $col++){
if($i $total_photos){
$thumbnail = $thumbnail_dir.trim($photos[$i]);
$thumb_image_size = getimagesize($thumbnail);
$image_size = getimagesize(trim($photos[$i]));
print(td align=\center\
a
href=\javascript:photo_open('photo_display.php?photo=.trim($photos[$i]).'
,'.$image_size[0].','.$image_size[1].');\img src=\.$thumbnail.\
.$thumb_image_size[3]. border=\0\/a/td\n);
} else {
print(td/td\n);
}
$i++;
}
print(/tr\n);
}
//Clean up directory array
closedir($handle);
return $retVal;
//end table
?
-Original Message-
From: _lallous [mailto:[EMAIL PROTECTED]]
Sent: den 18 september 2001 13:46
To: [EMAIL PROTECTED]
Subject: [PHP] Re: Replacing datafile with array
works like a charm
just initializet the $retVal function...
$retVal = array();
rest of script here
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To unsubscribe, e-mail: [EMAIL PROTECTED]
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RE: [PHP] Re: Replacing datafile with array II
Woops!
I actually got the listing to work by replacing $photos = file($retVal);
with $photos = $retVal; :)
But, there´s still a problem. The script doesn´t seem to be able to use the
navigation part (print out the next and previous links). That part of the
script looks like this:
?PHP
//print out navigation links
if(($start == 0) ($next_start $total_photos)){
//you're at the beginning of the photo gallery
?
font face=arial, helvetica size=2b
a href=galleri.php?start=?PHP print($next_start);?next page/a
/font/b
?PHP
}
elseif (($start 0) ($next_start $total_photos)){
//you're in the middle of the photo gallery
?
font face=arial, helvetica size=2
bfont color=#FF#171;/font
a href=galleri.php?start=?PHP print($prev_start); ?prev
page/a/b/font
b|/b
font face=arial, helvetica size=2
ba href=galleri.php?start=?PHP print($next_start); ?next page/a
font
color=#FF#187;/font/b/font
?PHP
}
elseif(($start == 0) ($next_start $total_photos)){
//you're in a photo gallery with only one page of photos
?
?PHP
}
else {
//you're at the end of the photo galley
?
font face=arial, helvetica size=2
bfont color=#FF#171;/font
a href=galleri.php?start=?PHP print($prev_start); ?prev
page/a/b/font
?PHP
}
?
-Original Message-
From: _lallous [mailto:[EMAIL PROTECTED]]
Sent: den 18 september 2001 13:46
To: [EMAIL PROTECTED]
Subject: [PHP] Re: Replacing datafile with array
works like a charm
just initializet the $retVal function...
$retVal = array();
rest of script here
Daniel alsén [EMAIL PROTECTED] wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
Hi,
i am trying to replace a datafile wich contains the contents of a
directory
with an array.
I am reading the directory and am trying to pass the value to an array.
What
am i doing wrong? Shouldn´t $retVal contain the direcory info?
Also, is there a way to use the content of an array without getting the
word
'Array' at the start?
$handle=opendir('.');
while (false !== ($file = readdir($handle)))
if ($file != . $file != .. ereg(.jpg,$file)) {
$retVal[count($retVal)] = $file;
}
# Daniel Alsén| www.mindbash.com #
# [EMAIL PROTECTED] | +46 704 86 14 92 #
# ICQ: 63006462 | #
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PHP General Mailing List (http://www.php.net/)
To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional commands, e-mail: [EMAIL PROTECTED]
To contact the list administrators, e-mail: [EMAIL PROTECTED]
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To unsubscribe, e-mail: [EMAIL PROTECTED]
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RE: [PHP] Re: Replacing datafile with array Sorry... .)
Sorry, It seems like every time i posted a question i was able to solve it myself :) Something strange going on in my problem solving part of the brain. I got the whole script to work. The navigation part solved itself when i moved the 'cleaning up' part to the very end of the script. Still, if anyone wants to help out, or has a good solution, to make this databasedriven - please e-mail me. Regards # Daniel Alsén| www.mindbash.com # # [EMAIL PROTECTED] | +46 704 86 14 92 # # ICQ: 63006462 | # -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
