I'm not sure, but I just know that if you need to select the information
from two tables (and not just from one),
you should use JOIN syntax ( http://dev.mysql.com/doc/mysql/en/join.html )
Hope this helps,
Lab.
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I'm not sure, but I just know that if you need to select the information
from two tables (and not just from one),
you should use JOIN syntax ( http://dev.mysql.com/doc/mysql/en/join.html )
Hope this helps,
Lab.
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To unsubscribe, visit:
That's a SQL problem, nothing to do with PHP.
You've forgotten a JOIN clause.
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Skrol29
www.tinybutstrong.com
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PartyPosters a écrit :
I can't figure out what I am doing wrong,
this sql string seems to filter out the information I want but it duplicates
the
Ok I think I figured out my own problem. The speechmarks in the Form break
up the speech marks in the echo statement so I originally changed the echo
statements speechmark to a ' which worked but was informed that this was
considered bad syntax and that maybe I should add a \ in front of all
First of all, I'd use something like this:
-- CODE --
?
if (!isset($_GET['action']) || trim($_GET['action']) == )
{
?
form./form
?
}
else if ($_GET['action'] == 'adduser')
{
?
Foo
?
}
?
-- END --
But the actual error is in the echo. You're having quotation marks
inside it. You
On Tuesday 14 September 2004 18:06, Logan Moore wrote:
Ok I think I figured out my own problem. The speechmarks in the Form break
up the speech marks in the echo statement so I originally changed the echo
statements speechmark to a ' which worked but was informed that this was
considered bad
On Tue, 14 Sep 2004 18:32:50 +0800, Jason Wong [EMAIL PROTECTED] wrote:
On Tuesday 14 September 2004 18:06, Logan Moore wrote:
Ok I think I figured out my own problem. The speechmarks in the Form break
up the speech marks in the echo statement so I originally changed the echo
statements
add the following:
if( $i % 3 == 0 ) {
print(something else);
}
You might need to vary the zero in that equation to get it to print at the
right time by which I mean, the above will print something else on the
first iteration of the below loop.
-philip
On Wed, 4 Sep 2002, Cirkit
Hi,
On every loop, just put the text you want to add to a variable.
like
if($i == 0) echo first print;
elseif($i == 1) echo second;
elseif($i == 2) echo third; etc...
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Nicos - CHAILLAN Nicolas
[EMAIL PROTECTED]
www.WorldAKT.com - Hébergement de sites Internet
Cirkit Braker [EMAIL PROTECTED]
Sorry I hadn't read well, yes use if(!($i %3)) echo lala;
--
Nicos - CHAILLAN Nicolas
[EMAIL PROTECTED]
www.WorldAKT.com - Hébergement de sites Internet
[EMAIL PROTECTED] a écrit dans le message de news:
[EMAIL PROTECTED]
Hi,
On every loop, just put the text you want to add to a variable.
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