Re: [PHP] Simple Math Calculation Problem....
* Thus wrote Scott Fletcher ([EMAIL PROTECTED]):
> Hi!
>
> I'm a little stuck with this simple math problem. I'm trying to get a
> number of days in integer, not float.
>
> --snip--
>$input_date = "12/16/2002";
>$UserInput = explode("/", $input_date);
>
>$UserInputMonth = $UserInput[0];
>$UserInputDay = $UserInput[1];
>$UserInputYear = $UserInput[2];
>
>$clockDate = mktime(0,0,0,date("m"),date("d"),date("Y"));
>$inputDate = mktime(0,0,0,$UserInputMonth,$UserInputDay,$UserInputYear);
I think strtotime might be more efficient..
$clockDate = strtotime(date("m/d/Y"));
$inputDate = strtotime("12/16/2002");
>
>$Days = (($clockDate - $inputDate) / (24 * 3600));
You can cast it:
$Days = (integer)(($clockDate - $inputDate) / (24 * 3600));
>//$Days = round(Days);
> --snip--
HTH,
Curt
--
"I used to think I was indecisive, but now I'm not so sure."
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Re: [PHP] Simple Math Calculation Problem....
* Thus wrote Scott Fletcher ([EMAIL PROTECTED]): > The int() function is for C/C++ programming only. This Int() function is > not supported in PHP. In PHP it would be Intval(). For float, Floatval(). > For double, DoubleVal(). Etc. But beware of the Octual numbers. You can cast like you can in C/C++ $Days = (int) $value; // C compatible $Days = (integer) $value; // php method Curt -- "I used to think I was indecisive, but now I'm not so sure." -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Simple Math Calculation Problem....
> The int() function is for C/C++ programming only. This Int() function is > not supported in PHP. In PHP it would be Intval(). For float, Floatval(). > For double, DoubleVal(). Etc. But beware of the Octual numbers. > sorry, confusing my flash action script again :( -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Simple Math Calculation Problem....
Gee! I forgot the '$'. It's been right there in my face. Thanks! I hope
the round() function work without a problem because I saw in some posting
that some people have this problem where if 3.51 is rounded, it return a 3.
"Seth - Kate Buntin" <[EMAIL PROTECTED]> wrote in message
news:[EMAIL PROTECTED]
I used your snip you just posted and changed the $Days = round(Days) to
$Days = round($Days) and got 228.
-Original Message-
From: Scott Fletcher [mailto:[EMAIL PROTECTED]
Sent: Friday, August 01, 2003 9:18 AM
To: [EMAIL PROTECTED]
Subject: [PHP] Simple Math Calculation Problem
Hi!
I'm a little stuck with this simple math problem. I'm trying to get
a number of days in integer, not float.
--snip--
$input_date = "12/16/2002";
$UserInput = explode("/", $input_date);
$UserInputMonth = $UserInput[0];
$UserInputDay = $UserInput[1];
$UserInputYear = $UserInput[2];
$clockDate = mktime(0,0,0,date("m"),date("d"),date("Y"));
$inputDate =
mktime(0,0,0,$UserInputMonth,$UserInputDay,$UserInputYear);
$Days = (($clockDate - $inputDate) / (24 * 3600));
//$Days = round(Days);
--snip--
But then I get the idea of doing the round function but it only
return a '0' value. Anyone know?
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Re: [PHP] Simple Math Calculation Problem....
The int() function is for C/C++ programming only. This Int() function is not supported in PHP. In PHP it would be Intval(). For float, Floatval(). For double, DoubleVal(). Etc. But beware of the Octual numbers. "Skate" <[EMAIL PROTECTED]> wrote in message news:[EMAIL PROTECTED] > > >$Days = (($clockDate - $inputDate) / (24 * 3600)); > > $Days = int(($clockDate - $inputDate) / (24 * 3600)); > > you tried that? > > -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] Simple Math Calculation Problem....
I used your snip you just posted and changed the $Days = round(Days) to
$Days = round($Days) and got 228.
-Original Message-
From: Scott Fletcher [mailto:[EMAIL PROTECTED]
Sent: Friday, August 01, 2003 9:18 AM
To: [EMAIL PROTECTED]
Subject: [PHP] Simple Math Calculation Problem
Hi!
I'm a little stuck with this simple math problem. I'm trying to get
a number of days in integer, not float.
--snip--
$input_date = "12/16/2002";
$UserInput = explode("/", $input_date);
$UserInputMonth = $UserInput[0];
$UserInputDay = $UserInput[1];
$UserInputYear = $UserInput[2];
$clockDate = mktime(0,0,0,date("m"),date("d"),date("Y"));
$inputDate =
mktime(0,0,0,$UserInputMonth,$UserInputDay,$UserInputYear);
$Days = (($clockDate - $inputDate) / (24 * 3600));
//$Days = round(Days);
--snip--
But then I get the idea of doing the round function but it only
return a '0' value. Anyone know?
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Simple Math Calculation Problem....
>$Days = (($clockDate - $inputDate) / (24 * 3600)); $Days = int(($clockDate - $inputDate) / (24 * 3600)); you tried that? -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Simple Math Calculation Problem....
Hi!
I'm a little stuck with this simple math problem. I'm trying to get a
number of days in integer, not float.
--snip--
$input_date = "12/16/2002";
$UserInput = explode("/", $input_date);
$UserInputMonth = $UserInput[0];
$UserInputDay = $UserInput[1];
$UserInputYear = $UserInput[2];
$clockDate = mktime(0,0,0,date("m"),date("d"),date("Y"));
$inputDate = mktime(0,0,0,$UserInputMonth,$UserInputDay,$UserInputYear);
$Days = (($clockDate - $inputDate) / (24 * 3600));
//$Days = round(Days);
--snip--
But then I get the idea of doing the round function but it only return a
'0' value. Anyone know?
--
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To unsubscribe, visit: http://www.php.net/unsub.php
