[PHP] Tricky variable question! Impossible??

[Andy]

Hi guys,

I am not sure if this is possible. Not on my knowledge, but maybe someone is
smarter than I am :-)

I want to pass an icon to a function. Therefore I am putting all the html
into a var called icon.
Inside this html their is another variable with an array which value is set
inside the function.

How can I pass this html thing and ensure that the variable is gonna be set?
Take a look at the code underneath.
Like that it is just printing out $picture_id[$i]

  $icon_1 =  a href=\index.php?fuseaction=editaction=deleteid=%s\
  onclick=\return confirm('Are you sure you want to delete picture no:
$picture_id[$i]');\
  img src=\../app_global/pics/delete.gif\ width=20 height=20 border=0
alt=\delete\
 /a;

Can anybody help on this?

Thanx for any help

Cheers Andy



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Re: [PHP] Tricky variable question! Impossible??

[Edward van Bilderbeek - Bean IT]

Well, as long as you use double quotes:  the variables will be parsed
inside you statement... single quotes however mean the exact string...

example:
$icon = 1.jpg;
$str = this is the image $icon;
$str2 = 'this is the image $icon';

print $str; // returns: this is the image 1.jpg
print $str2; // returns: this is the image $icon


Greets,

Edward

- Original Message -
From: Andy [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Saturday, February 16, 2002 6:03 PM
Subject: [PHP] Tricky variable question! Impossible??


 Hi guys,

 I am not sure if this is possible. Not on my knowledge, but maybe someone
is
 smarter than I am :-)

 I want to pass an icon to a function. Therefore I am putting all the html
 into a var called icon.
 Inside this html their is another variable with an array which value is
set
 inside the function.

 How can I pass this html thing and ensure that the variable is gonna be
set?
 Take a look at the code underneath.
 Like that it is just printing out $picture_id[$i]

   $icon_1 =  a href=\index.php?fuseaction=editaction=deleteid=%s\
   onclick=\return confirm('Are you sure you want to delete picture
no:
 $picture_id[$i]');\
   img src=\../app_global/pics/delete.gif\ width=20 height=20
border=0
 alt=\delete\
  /a;

 Can anybody help on this?

 Thanx for any help

 Cheers Andy



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 PHP General Mailing List (http://www.php.net/)
 To unsubscribe, visit: http://www.php.net/unsub.php




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