I am trying to represent the variable:
$row['Bible_knowledge_phrase_solver_game_question_topics_1']
Where the # 1 is replaced by a variable --- $i
The following code executes without an error, but “Hello world” doesn’t show on
the screen.
?php
-Original Message-
From: Ron Piggott [mailto:ron.pigg...@actsministries.org]
Sent: Thursday, June 21, 2012 3:47 AM
To: php-general@lists.php.net
Subject: [PHP] Variable representation
I am trying to represent the variable:
$row['Bible_knowledge_phrase_solver_game_question_topics_1
or you can do this
echo $row[Bible_knowledge_phrase_solver_game_question_topics_$i];
On 02-04-2012 07:15, tamouse mailing lists wrote:
As for doing what you originally asked, that requires doing an eval()
on the statement utilizing string interpolation, like so:
eval('echo image $i is $image_' . $i . '.PHP_EOL;');
but I think that's a bit harder to read and understand
On Mon, Apr 2, 2012 at 4:34 AM, Maciek Sokolewicz
maciek.sokolew...@gmail.com wrote:
Usually if you think you need to use eval: think again. In this case, it
again holds true.
Instead of doing what you do, you can also reference the variable as:
echo ${'image_'.$i};
or
echo
Hi Everyone:
I am assigning the value of 4 images to variables following a database query:
$image_1 = stripslashes( $row['image_1'] );
$image_2 = stripslashes( $row['image_2'] );
$image_3 = stripslashes( $row['image_3'] );
$image_4 = stripslashes( $row['image_4'] );
What I need help with is
It would better to just use an array, and then iterate through that.
$images[] = stripslashes( $row['image_1'] );
$images[] = stripslashes( $row['image_2'] );
$images[] = stripslashes( $row['image_3'] );
$images[] = stripslashes( $row['image_4'] );
foreach( $images as $k = $v ) {
$k++;
On 04/02/2012 06:52 AM, Ron Piggott wrote:
$image_1 = stripslashes( $row['image_1'] );
$image_2 = stripslashes( $row['image_2'] );
$image_3 = stripslashes( $row['image_3'] );
$image_4 = stripslashes( $row['image_4'] );
[...] (Not all 4 variables have an image.)
How is it meant in the database?
On 04/02/2012 07:46 AM, Adam Randall wrote:
$images[] = stripslashes( $row['image_1'] );
$images[] = stripslashes( $row['image_2'] );
$images[] = stripslashes( $row['image_3'] );
$images[] = stripslashes( $row['image_4'] );
$images[1] = stripslashes( $row['image_1'] );
$images[2] =
On Sun, Apr 1, 2012 at 10:52 PM, Ron Piggott
ron.pigg...@actsministries.org wrote:
Hi Everyone:
I am assigning the value of 4 images to variables following a database query:
$image_1 = stripslashes( $row['image_1'] );
$image_2 = stripslashes( $row['image_2'] );
$image_3 = stripslashes(
Ugh, gmail mangled the code there. Here's a pastebin of the response
which is better formatted: http://pastie.org/3712761
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On Mon, Apr 2, 2012 at 12:20 AM, tamouse mailing lists
tamouse.li...@gmail.com wrote:
Ugh, gmail mangled the code there. Here's a pastebin of the response
which is better formatted: http://pastie.org/3712761
Sweet. I spent so long on my reply, two others snuck in before me. :)
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