I would like to use eval() to evaluate another PHP file and store the output
of that file in a string.
So, let's say, for example, that I have a file called colors.php which
contains this:
pColors: ? echo Red, Yellow, Green, Blue; ?/p
Then, in another file, I have this:
$file =
OrangeHairedBoy wrote:
I would like to use eval() to evaluate another PHP file and store the
output of that file in a string.
You could use output buffering to do this a bit more easily, I think:
ob_start();
include('colors.php');
$colors = ob_get_contents();
ob_end_clean();
--
PHP General
While that is an awesome idea, I don't think it will work for me.
There's two reasons why. First, colors.php is actually stored in a MySQL
server.
Second, before the PHP code inside colors.php I want to be able to replace
data inside that file. For example:
$file = str_replace( Green , Orange ,
OrangeHairedBoy wrote:
I would like to use eval() to evaluate another PHP file and store the output
of that file in a string.
So, let's say, for example, that I have a file called colors.php which
contains this:
pColors: ? echo Red, Yellow, Green, Blue; ?/p
Then, in another file, I have this:
Marek,
OK...that worked...kinda, but it doesn't pass the output to $colors. It
echos it. I need the output to be passed to $colors.
Lewis
Marek Kilimajer [EMAIL PROTECTED] wrote in message
news:[EMAIL PROTECTED]
OrangeHairedBoy wrote:
I would like to use eval() to evaluate another PHP file
OrangeHairedBoy wrote:
I would like to use eval() to evaluate another PHP file and store
the output of that file in a string.
You could use output buffering to do this a bit more easily, I think:
ob_start();
include('colors.php');
$colors = ob_get_contents();
ob_end_clean();
While that
Thanks Michael Marek! It worked! :)
Michael Sims [EMAIL PROTECTED] wrote in message
news:[EMAIL PROTECTED]
OrangeHairedBoy wrote:
I would like to use eval() to evaluate another PHP file and store
the output of that file in a string.
You could use output buffering to do this a bit more
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